您可以使用semver包来确定一个版本是否满足语义版本需求。这与比较两个实际版本不同，但这是一种比较。

例如，3.6.0+1234版本应与3.6.0相同。

import semver
semver.match('3.6.0+1234', '==3.6.0')
# True

from packaging import version
version.parse('3.6.0+1234') == version.parse('3.6.0')
# False

from distutils.version import LooseVersion
LooseVersion('3.6.0+1234') == LooseVersion('3.6.0')
# False

这是一个用于比较三个版本号的紧凑代码。注意，这里的字符串比较对所有对都失败了。

from itertools import permutations

for v1, v2 in permutations(["3.10.21", "3.10.3", "3.9.9"], 2):
    print(f"\nv1 = {v1}, v2 = {v2}")
    print(f"v1 < v2      version.parse(v1) < version.parse(v2)")
    print(f"{v1 < v2}         {version.parse(v1) < version.parse(v2)}")

这给了我们:

v1='3.10.21', v2='3.10.3'
v1 < v2      version.parse(v1) < version.parse(v2)
True         False

v1='3.10.21', v2='3.9.9'
v1 < v2      version.parse(v1) < version.parse(v2)
True         False

v1='3.10.3', v2='3.10.21'
v1 < v2      version.parse(v1) < version.parse(v2)
False         True

v1='3.10.3', v2='3.9.9'
v1 < v2      version.parse(v1) < version.parse(v2)
True         False

v1='3.9.9', v2='3.10.21'
v1 < v2      version.parse(v1) < version.parse(v2)
False         True

v1='3.9.9', v2='3.10.3'
v1 < v2      version.parse(v1) < version.parse(v2)
False         True

Permutations (iterable, 2)给出了一个可迭代对象的所有长度为2的排列。例如，

list(permutations('ABC', 2))

给了我们[(A, B), (' A ', ' C '), (A, B),(“B”、“C”)(“C”,“A”),(“C”、“B”)]。

使用python增加版本

def increment_version(version):
    version = version.split('.')
    if int(version[len(version) - 1]) >= 99:
        version[len(version) - 1] = '0'
        version[len(version) - 2] = str(int(version[len(version) - 2]) + 1)
    else:
        version[len(version) - 1] = str(int(version[len(version) - 1]) + 1)
    return '.'.join(version)

version = "1.0.0"
version_type_2 = "1.0"
print("old version",version ,"new version",increment_version(version))
print("old version",version_type_2 ,"new version",increment_version(version_type_2))

将版本字符串转换为元组并从那里开始有什么问题?对我来说已经够优雅了

>>> (2,3,1) < (10,1,1)
True
>>> (2,3,1) < (10,1,1,1)
True
>>> (2,3,1,10) < (10,1,1,1)
True
>>> (10,3,1,10) < (10,1,1,1)
False
>>> (10,3,1,10) < (10,4,1,1)
True

@kindall的解决方案是一个简单的例子，说明代码看起来有多好。

我正在寻找一个解决方案，不会增加任何新的依赖。检查以下(Python 3)解决方案:

class VersionManager:

    @staticmethod
    def compare_version_tuples(
            major_a, minor_a, bugfix_a,
            major_b, minor_b, bugfix_b,
    ):

        """
        Compare two versions a and b, each consisting of 3 integers
        (compare these as tuples)

        version_a: major_a, minor_a, bugfix_a
        version_b: major_b, minor_b, bugfix_b

        :param major_a: first part of a
        :param minor_a: second part of a
        :param bugfix_a: third part of a

        :param major_b: first part of b
        :param minor_b: second part of b
        :param bugfix_b: third part of b

        :return:    1 if a  > b
                    0 if a == b
                   -1 if a  < b
        """
        tuple_a = major_a, minor_a, bugfix_a
        tuple_b = major_b, minor_b, bugfix_b
        if tuple_a > tuple_b:
            return 1
        if tuple_b > tuple_a:
            return -1
        return 0

    @staticmethod
    def compare_version_integers(
            major_a, minor_a, bugfix_a,
            major_b, minor_b, bugfix_b,
    ):
        """
        Compare two versions a and b, each consisting of 3 integers
        (compare these as integers)

        version_a: major_a, minor_a, bugfix_a
        version_b: major_b, minor_b, bugfix_b

        :param major_a: first part of a
        :param minor_a: second part of a
        :param bugfix_a: third part of a

        :param major_b: first part of b
        :param minor_b: second part of b
        :param bugfix_b: third part of b

        :return:    1 if a  > b
                    0 if a == b
                   -1 if a  < b
        """
        # --
        if major_a > major_b:
            return 1
        if major_b > major_a:
            return -1
        # --
        if minor_a > minor_b:
            return 1
        if minor_b > minor_a:
            return -1
        # --
        if bugfix_a > bugfix_b:
            return 1
        if bugfix_b > bugfix_a:
            return -1
        # --
        return 0

    @staticmethod
    def test_compare_versions():
        functions = [
            (VersionManager.compare_version_tuples, "VersionManager.compare_version_tuples"),
            (VersionManager.compare_version_integers, "VersionManager.compare_version_integers"),
        ]
        data = [
            # expected result, version a, version b
            (1, 1, 0, 0, 0, 0, 1),
            (1, 1, 5, 5, 0, 5, 5),
            (1, 1, 0, 5, 0, 0, 5),
            (1, 0, 2, 0, 0, 1, 1),
            (1, 2, 0, 0, 1, 1, 0),
            (0, 0, 0, 0, 0, 0, 0),
            (0, -1, -1, -1, -1, -1, -1),  # works even with negative version numbers :)
            (0, 2, 2, 2, 2, 2, 2),
            (-1, 5, 5, 0, 6, 5, 0),
            (-1, 5, 5, 0, 5, 9, 0),
            (-1, 5, 5, 5, 5, 5, 6),
            (-1, 2, 5, 7, 2, 5, 8),
        ]
        count = len(data)
        index = 1
        for expected_result, major_a, minor_a, bugfix_a, major_b, minor_b, bugfix_b in data:
            for function_callback, function_name in functions:
                actual_result = function_callback(
                    major_a=major_a, minor_a=minor_a, bugfix_a=bugfix_a,
                    major_b=major_b, minor_b=minor_b, bugfix_b=bugfix_b,
                )
                outcome = expected_result == actual_result
                message = "{}/{}: {}: {}: a={}.{}.{} b={}.{}.{} expected={} actual={}".format(
                    index, count,
                    "ok" if outcome is True else "fail",
                    function_name,
                    major_a, minor_a, bugfix_a,
                    major_b, minor_b, bugfix_b,
                    expected_result, actual_result
                )
                print(message)
                assert outcome is True
                index += 1
        # test passed!


if __name__ == '__main__':
    VersionManager.test_compare_versions()

编辑:添加变量与元组比较。当然，具有元组比较的变体更好，但我正在寻找具有整数比较的变体

def versiontuple(v):
    return tuple(map(int, (v.split("."))))

>>> versiontuple("2.3.1") > versiontuple("10.1.1")
False