基于Kindall的解决方案发布我的完整功能。通过用前导零填充每个版本部分，我能够支持混合在数字中的任何字母数字字符。

虽然肯定不如他的一行函数漂亮，但它似乎可以很好地处理字母数字版本号。(如果您的版本控制系统中有较长的字符串，请确保适当地设置zfill(#)值。)

def versiontuple(v):
   filled = []
   for point in v.split("."):
      filled.append(point.zfill(8))
   return tuple(filled)

.

>>> versiontuple("10a.4.5.23-alpha") > versiontuple("2a.4.5.23-alpha")
True


>>> "10a.4.5.23-alpha" > "2a.4.5.23-alpha"
False

def versiontuple(v):
    return tuple(map(int, (v.split("."))))

>>> versiontuple("2.3.1") > versiontuple("10.1.1")
False

我正在寻找一个解决方案，不会增加任何新的依赖。检查以下(Python 3)解决方案:

class VersionManager:

    @staticmethod
    def compare_version_tuples(
            major_a, minor_a, bugfix_a,
            major_b, minor_b, bugfix_b,
    ):

        """
        Compare two versions a and b, each consisting of 3 integers
        (compare these as tuples)

        version_a: major_a, minor_a, bugfix_a
        version_b: major_b, minor_b, bugfix_b

        :param major_a: first part of a
        :param minor_a: second part of a
        :param bugfix_a: third part of a

        :param major_b: first part of b
        :param minor_b: second part of b
        :param bugfix_b: third part of b

        :return:    1 if a  > b
                    0 if a == b
                   -1 if a  < b
        """
        tuple_a = major_a, minor_a, bugfix_a
        tuple_b = major_b, minor_b, bugfix_b
        if tuple_a > tuple_b:
            return 1
        if tuple_b > tuple_a:
            return -1
        return 0

    @staticmethod
    def compare_version_integers(
            major_a, minor_a, bugfix_a,
            major_b, minor_b, bugfix_b,
    ):
        """
        Compare two versions a and b, each consisting of 3 integers
        (compare these as integers)

        version_a: major_a, minor_a, bugfix_a
        version_b: major_b, minor_b, bugfix_b

        :param major_a: first part of a
        :param minor_a: second part of a
        :param bugfix_a: third part of a

        :param major_b: first part of b
        :param minor_b: second part of b
        :param bugfix_b: third part of b

        :return:    1 if a  > b
                    0 if a == b
                   -1 if a  < b
        """
        # --
        if major_a > major_b:
            return 1
        if major_b > major_a:
            return -1
        # --
        if minor_a > minor_b:
            return 1
        if minor_b > minor_a:
            return -1
        # --
        if bugfix_a > bugfix_b:
            return 1
        if bugfix_b > bugfix_a:
            return -1
        # --
        return 0

    @staticmethod
    def test_compare_versions():
        functions = [
            (VersionManager.compare_version_tuples, "VersionManager.compare_version_tuples"),
            (VersionManager.compare_version_integers, "VersionManager.compare_version_integers"),
        ]
        data = [
            # expected result, version a, version b
            (1, 1, 0, 0, 0, 0, 1),
            (1, 1, 5, 5, 0, 5, 5),
            (1, 1, 0, 5, 0, 0, 5),
            (1, 0, 2, 0, 0, 1, 1),
            (1, 2, 0, 0, 1, 1, 0),
            (0, 0, 0, 0, 0, 0, 0),
            (0, -1, -1, -1, -1, -1, -1),  # works even with negative version numbers :)
            (0, 2, 2, 2, 2, 2, 2),
            (-1, 5, 5, 0, 6, 5, 0),
            (-1, 5, 5, 0, 5, 9, 0),
            (-1, 5, 5, 5, 5, 5, 6),
            (-1, 2, 5, 7, 2, 5, 8),
        ]
        count = len(data)
        index = 1
        for expected_result, major_a, minor_a, bugfix_a, major_b, minor_b, bugfix_b in data:
            for function_callback, function_name in functions:
                actual_result = function_callback(
                    major_a=major_a, minor_a=minor_a, bugfix_a=bugfix_a,
                    major_b=major_b, minor_b=minor_b, bugfix_b=bugfix_b,
                )
                outcome = expected_result == actual_result
                message = "{}/{}: {}: {}: a={}.{}.{} b={}.{}.{} expected={} actual={}".format(
                    index, count,
                    "ok" if outcome is True else "fail",
                    function_name,
                    major_a, minor_a, bugfix_a,
                    major_b, minor_b, bugfix_b,
                    expected_result, actual_result
                )
                print(message)
                assert outcome is True
                index += 1
        # test passed!


if __name__ == '__main__':
    VersionManager.test_compare_versions()

编辑:添加变量与元组比较。当然，具有元组比较的变体更好，但我正在寻找具有整数比较的变体

将版本字符串转换为元组并从那里开始有什么问题?对我来说已经够优雅了

>>> (2,3,1) < (10,1,1)
True
>>> (2,3,1) < (10,1,1,1)
True
>>> (2,3,1,10) < (10,1,1,1)
True
>>> (10,3,1,10) < (10,1,1,1)
False
>>> (10,3,1,10) < (10,4,1,1)
True

@kindall的解决方案是一个简单的例子，说明代码看起来有多好。

setuptools的方法是使用pkg_resources。parse_version函数。它应该符合PEP440标准。

例子:

#! /usr/bin/python
# -*- coding: utf-8 -*-
"""Example comparing two PEP440 formatted versions
"""
import pkg_resources

VERSION_A = pkg_resources.parse_version("1.0.1-beta.1")
VERSION_B = pkg_resources.parse_version("v2.67-rc")
VERSION_C = pkg_resources.parse_version("2.67rc")
VERSION_D = pkg_resources.parse_version("2.67rc1")
VERSION_E = pkg_resources.parse_version("1.0.0")

print(VERSION_A)
print(VERSION_B)
print(VERSION_C)
print(VERSION_D)

print(VERSION_A==VERSION_B) #FALSE
print(VERSION_B==VERSION_C) #TRUE
print(VERSION_C==VERSION_D) #FALSE
print(VERSION_A==VERSION_E) #FALSE

简单的few-liner:

import sys
if (sys.version_info.major, sys.version_info.minor) >= (3, 9):
    ...
else:
    ...