如何将整个输入流读到字节数组?


当前回答

你可以试试仙人掌:

byte[] array = new BytesOf(stream).bytes();

其他回答

/*InputStream class_InputStream = null;
I am reading class from DB 
class_InputStream = rs.getBinaryStream(1);
Your Input stream could be from any source
*/
int thisLine;
ByteArrayOutputStream bos = new ByteArrayOutputStream();
while ((thisLine = class_InputStream.read()) != -1) {
    bos.write(thisLine);
}
bos.flush();
byte [] yourBytes = bos.toByteArray();

/*Don't forget in the finally block to close ByteArrayOutputStream & InputStream
 In my case the IS is from resultset so just closing the rs will do it*/

if (bos != null){
    bos.close();
}

您需要从InputStream中读取每个字节,并将其写入ByteArrayOutputStream。

然后你可以通过调用toByteArray()来检索底层的字节数组:

InputStream is = ...
ByteArrayOutputStream buffer = new ByteArrayOutputStream();

int nRead;
byte[] data = new byte[16384];

while ((nRead = is.read(data, 0, data.length)) != -1) {
  buffer.write(data, 0, nRead);
}

return buffer.toByteArray();

另一种情况是在发送请求到服务器并等待响应后,通过流获得正确的字节数组。

/**
         * Begin setup TCP connection to PC app
         * to open integrate connection between mobile app and pc app (or mobile app)
         */
        mSocket = new Socket(IP, port);
       // mSocket.setSoTimeout(30000);

        DataOutputStream mDos = new DataOutputStream(mSocket.getOutputStream());

        String str = "MobileRequest#" + params[0] + "#<EOF>";

        mDos.write(str.getBytes());

        try {
            Thread.sleep(1000);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }

        /* Since data are accepted as byte, all of them will be collected in the
        following byte array which initialised with accepted data length. */
        DataInputStream mDis = new DataInputStream(mSocket.getInputStream());
        byte[] data = new byte[mDis.available()];

        // Collecting data into byte array
        for (int i = 0; i < data.length; i++)
            data[i] = mDis.readByte();

        // Converting collected data in byte array into String.
        String RESPONSE = new String(data);

我用这个。

public static byte[] toByteArray(InputStream is) throws IOException {
        ByteArrayOutputStream output = new ByteArrayOutputStream();
        try {
            byte[] b = new byte[4096];
            int n = 0;
            while ((n = is.read(b)) != -1) {
                output.write(b, 0, n);
            }
            return output.toByteArray();
        } finally {
            output.close();
        }
    }

您可以使用Apache Commons IO来处理这个任务和类似的任务。

IOUtils类型有一个静态方法来读取InputStream并返回一个字节[]。

InputStream is;
byte[] bytes = IOUtils.toByteArray(is);

这将在内部创建一个ByteArrayOutputStream并将字节复制到输出,然后调用toByteArray()。它通过以4KiB为块复制字节来处理大文件。