安全解决方案(正确关闭流):

Java 9及更新版本: 最终字节[]字节; try (inputStream) { 字节= inputStream.readAllBytes(); ｝

Java 8 and older: public static byte[] readAllBytes(InputStream inputStream) throws IOException { final int bufLen = 4 * 0x400; // 4KB byte[] buf = new byte[bufLen]; int readLen; IOException exception = null; try { try (ByteArrayOutputStream outputStream = new ByteArrayOutputStream()) { while ((readLen = inputStream.read(buf, 0, bufLen)) != -1) outputStream.write(buf, 0, readLen); return outputStream.toByteArray(); } } catch (IOException e) { exception = e; throw e; } finally { if (exception == null) inputStream.close(); else try { inputStream.close(); } catch (IOException e) { exception.addSuppressed(e); } } }

Kotlin(当Java 9+不可访问时): @Throws (IOException::类) fun InputStream.readAllBytes(): ByteArray { val bufLen = 4 * 0x400 // 4KB val buf = ByteArray(bufLen) var readLen: Int = 0 ByteArrayOutputStream()。使用{o -> 这一点。使用{I -> i.read(buf, 0, bufLen)。{readLen = it} != -1) o.write(buf, 0, readLen) ｝ 返回o.toByteArray () ｝ ｝ 避免嵌套使用请看这里。

Scala(当Java 9+不可访问时)(By @Joan。Thx): def readAllBytes(inputStream: inputStream): Array[Byte] = Stream.continually (read)。takeWhile(_ != -1).map(_. tobyte).toArray . take (_

我知道已经太迟了，但我认为这里有更清晰的解决方案，更易于阅读……

/**
 * method converts {@link InputStream} Object into byte[] array.
 * 
 * @param stream the {@link InputStream} Object.
 * @return the byte[] array representation of received {@link InputStream} Object.
 * @throws IOException if an error occurs.
 */
public static byte[] streamToByteArray(InputStream stream) throws IOException {

    byte[] buffer = new byte[1024];
    ByteArrayOutputStream os = new ByteArrayOutputStream();

    int line = 0;
    // read bytes from stream, and store them in buffer
    while ((line = stream.read(buffer)) != -1) {
        // Writes bytes from byte array (buffer) into output stream.
        os.write(buffer, 0, line);
    }
    stream.close();
    os.flush();
    os.close();
    return os.toByteArray();
}

这对我很有用，

if(inputStream != null){
                ByteArrayOutputStream contentStream = readSourceContent(inputStream);
                String stringContent = contentStream.toString();
                byte[] byteArr = encodeString(stringContent);
            }

readSourceContent ()

public static ByteArrayOutputStream readSourceContent(InputStream inputStream) throws IOException {
        ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
        int nextChar;
        try {
            while ((nextChar = inputStream.read()) != -1) {
                outputStream.write(nextChar);
            }
            outputStream.flush();
        } catch (IOException e) {
            throw new IOException("Exception occurred while reading content", e);
        }

        return outputStream;
    }

encodeString（）

public static byte[] encodeString(String content) throws UnsupportedEncodingException {
        byte[] bytes;
        try {
            bytes = content.getBytes();

        } catch (UnsupportedEncodingException e) {
            String msg = ENCODING + " is unsupported encoding type";
            log.error(msg,e);
            throw new UnsupportedEncodingException(msg, e);
        }
        return bytes;
    }

如果由于某种原因，它不在表中，则将其包装在DataInputStream中，只需使用read来锤击它，直到它给您一个-1或您所要求的整个块。

public int readFully(InputStream in, byte[] data) throws IOException {
    int offset = 0;
    int bytesRead;
    boolean read = false;
    while ((bytesRead = in.read(data, offset, data.length - offset)) != -1) {
        read = true;
        offset += bytesRead;
        if (offset >= data.length) {
            break;
        }
    }
    return (read) ? offset : -1;
}

/*InputStream class_InputStream = null;
I am reading class from DB 
class_InputStream = rs.getBinaryStream(1);
Your Input stream could be from any source
*/
int thisLine;
ByteArrayOutputStream bos = new ByteArrayOutputStream();
while ((thisLine = class_InputStream.read()) != -1) {
    bos.write(thisLine);
}
bos.flush();
byte [] yourBytes = bos.toByteArray();

/*Don't forget in the finally block to close ByteArrayOutputStream & InputStream
 In my case the IS is from resultset so just closing the rs will do it*/

if (bos != null){
    bos.close();
}

如果您不想使用Apache common -io库，则此代码片段取自sun.misc.IOUtils类。它的速度几乎是使用ByteBuffers的普通实现的两倍:

public static byte[] readFully(InputStream is, int length, boolean readAll)
        throws IOException {
    byte[] output = {};
    if (length == -1) length = Integer.MAX_VALUE;
    int pos = 0;
    while (pos < length) {
        int bytesToRead;
        if (pos >= output.length) { // Only expand when there's no room
            bytesToRead = Math.min(length - pos, output.length + 1024);
            if (output.length < pos + bytesToRead) {
                output = Arrays.copyOf(output, pos + bytesToRead);
            }
        } else {
            bytesToRead = output.length - pos;
        }
        int cc = is.read(output, pos, bytesToRead);
        if (cc < 0) {
            if (readAll && length != Integer.MAX_VALUE) {
                throw new EOFException("Detect premature EOF");
            } else {
                if (output.length != pos) {
                    output = Arrays.copyOf(output, pos);
                }
                break;
            }
        }
        pos += cc;
    }
    return output;
}