这对我很有用，

if(inputStream != null){
                ByteArrayOutputStream contentStream = readSourceContent(inputStream);
                String stringContent = contentStream.toString();
                byte[] byteArr = encodeString(stringContent);
            }

readSourceContent ()

public static ByteArrayOutputStream readSourceContent(InputStream inputStream) throws IOException {
        ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
        int nextChar;
        try {
            while ((nextChar = inputStream.read()) != -1) {
                outputStream.write(nextChar);
            }
            outputStream.flush();
        } catch (IOException e) {
            throw new IOException("Exception occurred while reading content", e);
        }

        return outputStream;
    }

encodeString（）

public static byte[] encodeString(String content) throws UnsupportedEncodingException {
        byte[] bytes;
        try {
            bytes = content.getBytes();

        } catch (UnsupportedEncodingException e) {
            String msg = ENCODING + " is unsupported encoding type";
            log.error(msg,e);
            throw new UnsupportedEncodingException(msg, e);
        }
        return bytes;
    }

你可以完全避免缓冲。

从http://www.exampledepot.com/egs/java.io/File2ByteArray.html复制的代码(是的，它非常冗长，但需要的内存大小是其他解决方案的一半)。

// Returns the contents of the file in a byte array.
public static byte[] getBytesFromFile(File file) throws IOException {
    InputStream is = new FileInputStream(file);

    // Get the size of the file
    long length = file.length();

    // You cannot create an array using a long type.
    // It needs to be an int type.
    // Before converting to an int type, check
    // to ensure that file is not larger than Integer.MAX_VALUE.
    if (length > Integer.MAX_VALUE) {
        // File is too large
    }

    // Create the byte array to hold the data
    byte[] bytes = new byte[(int)length];

    // Read in the bytes
    int offset = 0;
    int numRead = 0;
    while (offset < bytes.length
           && (numRead=is.read(bytes, offset, bytes.length-offset)) >= 0) {
        offset += numRead;
    }

    // Ensure all the bytes have been read in
    if (offset < bytes.length) {
        throw new IOException("Could not completely read file "+file.getName());
    }

    // Close the input stream and return bytes
    is.close();
    return bytes;
}

/*InputStream class_InputStream = null;
I am reading class from DB 
class_InputStream = rs.getBinaryStream(1);
Your Input stream could be from any source
*/
int thisLine;
ByteArrayOutputStream bos = new ByteArrayOutputStream();
while ((thisLine = class_InputStream.read()) != -1) {
    bos.write(thisLine);
}
bos.flush();
byte [] yourBytes = bos.toByteArray();

/*Don't forget in the finally block to close ByteArrayOutputStream & InputStream
 In my case the IS is from resultset so just closing the rs will do it*/

if (bos != null){
    bos.close();
}

Java 8方式(感谢BufferedReader和Adam Bien)

private static byte[] readFully(InputStream input) throws IOException {
    try (BufferedReader buffer = new BufferedReader(new InputStreamReader(input))) {
        return buffer.lines().collect(Collectors.joining("\n")).getBytes(<charset_can_be_specified>);
    }
}

注意，这个解决方案删除回车符('\r')，可能是不合适的。

Java 7及以上版本:

import sun.misc.IOUtils;
...
InputStream in = ...;
byte[] buf = IOUtils.readFully(in, -1, false);

你真的需要图像作为字节[]吗?你在字节[]中到底期望什么-图像文件的完整内容，以图像文件的任何格式编码，或RGB像素值?

这里的其他答案向您展示了如何将文件读入字节[]。您的字节[]将包含文件的确切内容，并且您需要对其进行解码才能对图像数据进行处理。

用于读取(和写入)图像的Java标准API是ImageIO API，您可以在javax.imageio包中找到它。你可以用一行代码从文件中读入一张图片:

BufferedImage image = ImageIO.read(new File("image.jpg"));

这将给您一个BufferedImage，而不是一个字节[]。要获取图像数据，可以在BufferedImage上调用getRaster()。这将为您提供一个光栅对象，该对象具有访问像素数据的方法(它有几个getPixel() / getPixels()方法)。

查找javax.imageio的API文档。ImageIO java.awt.image。BufferedImage, java。awt。image。raster等等。

ImageIO默认支持多种图像格式:JPEG, PNG, BMP, WBMP和GIF。可以添加对更多格式的支持(您需要一个实现ImageIO服务提供程序接口的插件)。

另请参阅下面的教程:使用图像