如果我在Bash中有一个这样的数组:

FOO=( a b c )

如何用逗号连接元素?例如,生成a b c。


当前回答

这里有一个单行,有点奇怪,但适用于多字符分隔符,并支持任何值(包括包含空格或任何东西):

ar=(abc "foo bar" 456)
delim=" | "
printf "%s\n$delim\n" "${ar[@]}" | head -n-1 | paste -sd ''

这将在控制台显示为

abc | foo bar | 456

注意:注意一些解决方案是如何使用${ar[*]}和${ar[@]}的printf ?

带@的使用printf特性,通过重复格式模板来支持多个参数。

带*的不应该使用。它们实际上不需要打印,而是依赖于操作字段分隔符和bash的单词展开。这些方法同样适用于echo、cat等——这些解决方案可能使用printf,因为作者并不真正理解他们在做什么……

其他回答

还有另一个解决方案:

#!/bin/bash
foo=('foo bar' 'foo baz' 'bar baz')
bar=$(printf ",%s" "${foo[@]}")
bar=${bar:1}

echo $bar

编辑:相同,但用于多字符可变长度分隔符:

#!/bin/bash
separator=")|(" # e.g. constructing regex, pray it does not contain %s
foo=('foo bar' 'foo baz' 'bar baz')
regex="$( printf "${separator}%s" "${foo[@]}" )"
regex="${regex:${#separator}}" # remove leading separator
echo "${regex}"
# Prints: foo bar)|(foo baz)|(bar baz
awk -v sep=. 'BEGIN{ORS=OFS="";for(i=1;i<ARGC;i++){print ARGV[i],ARGC-i-1?sep:""}}' "${arr[@]}"

or

$ a=(1 "a b" 3)
$ b=$(IFS=, ; echo "${a[*]}")
$ echo $b
1,a b,3

感谢@gniourf_gniourf对我迄今为止的最佳世界组合的详细评论。很抱歉发布的代码没有完全设计和测试。这是一个更好的尝试。

# join with separator
join_ws() { local d=$1 s=$2; shift 2 && printf %s "$s${@/#/$d}"; }

这种概念上的美是

(still) 100% pure bash ( thanks for explicitly pointing out that printf is a builtin as well. I wasn't aware about this before ... ) works with multi-character delimiters more compact and more complete and this time carefully thought over and long-term stress-tested with random substrings from shell scripts amongst others, covering use of shell special characters or control characters or no characters in both separator and / or parameters, and edge cases, and corner cases and other quibbles like no arguments at all. That doesn't guarantee there is no more bug, but it will be a little harder challenge to find one. BTW, even the currently top voted answers and related suffer from such things like that -e bug ...

附加的例子:

$ join_ws '' a b c
abc
$ join_ws ':' {1,7}{A..C}
1A:1B:1C:7A:7B:7C
$ join_ws -e -e
-e
$ join_ws $'\033[F' $'\n\n\n'  1.  2.  3.  $'\n\n\n\n'
3.
2.
1.
$ join_ws $ 
$
$ foo=(a "b c" d)
$ bar=$(IFS=, ; echo "${foo[*]}")
$ echo "$bar"
a,b c,d

结合所有最好的世界到目前为止与以下的想法。

# join with separator
join_ws()  { local IFS=; local s="${*/#/$1}"; echo "${s#"$1$1$1"}"; }

这个小杰作是

100%纯bash(参数扩展,暂时不设置IFS,没有外部调用,没有printf…) 紧凑、完整和完美(适用于单字符和多字符限制符,适用于包含空格、换行符和其他shell特殊字符的限制符,适用于空分隔符) 高效(无子shell,无数组复制) 简单而愚蠢,但在某种程度上,也很漂亮,很有教育意义

例子:

$ join_ws , a b c
a,b,c
$ join_ws '' a b c
abc
$ join_ws $'\n' a b c
a
b
c
$ join_ws ' \/ ' A B C
A \/ B \/ C