对于字符串

$string = 'OOO.OOO.OOO.S';
$search = 'OOO';
$replace = 'B';

//replace ONLY FIRST occurance of "OOO" with "B"
    $string = substr_replace($string,$replace,0,strlen($search));
    //$string => B.OOO.OOO.S

//replace ONLY LAST occurance of "OOOO" with "B"
    $string = substr_replace($string,$replace,strrpos($string,$search),strlen($search)) 
    //$string => OOO.OOO.B.S

    //replace ONLY LAST occurance of "OOOO" with "B"
    $string = strrev(implode(strrev($replace),explode(strrev($search),strrev($string),2)))
    //$string => OOO.OOO.B.S

对于单个字符

$string[strpos($string,$search)] = $replace;


//EXAMPLE

$string = 'O.O.O.O.S';
$search = 'O';
$replace = 'B';

//replace ONLY FIRST occurance of "O" with "B" 
    $string[strpos($string,$search)] = $replace;  
    //$string => B.O.O.O.S

//replace ONLY LAST occurance of "O" with "B" 
    $string[strrpos($string,$search)] = $replace; 
    // $string => B.O.O.B.S

$string = 'this is my world, not my world';
$find = 'world';
$replace = 'farm';
$result = preg_replace("/$find/",$replace,$string,1);
echo $result;

For循环解决方案

<?php
echo replaceFirstMatchedChar("&", "?", "/property/details&id=202&test=123#tab-6");

function replaceFirstMatchedChar($searchChar, $replaceChar, $str)
{
    for ($i = 0; $i < strlen($str); $i++) {

        if ($str[$i] == $searchChar) {
            $str[$i] = $replaceChar;
            break;
        }
    }
    return $str;
}

不幸的是，我不知道任何PHP函数可以做到这一点。 你可以像这样很容易地自己卷:

function replace_first($find, $replace, $subject) {
    // stolen from the comments at PHP.net/str_replace
    // Splits $subject into an array of 2 items by $find,
    // and then joins the array with $replace
    return implode($replace, explode($find, $subject, 2));
}

补充一下人们所说的，记住整个字符串是一个数组:

$string = "Lorem ipsum lá lá lá";

$string[0] = "B";

echo $string;

“Borem ipsum there there”

编辑:两个答案都已更新，现在是正确的。我将把答案留下，因为函数时间仍然是有用的。

“僵尸”和“太多php”的答案很不幸是不正确的。这是对僵尸发布的答案的修正(因为我没有足够的声誉来发表评论):

$pos = strpos($haystack,$needle);
if ($pos !== false) {
    $newstring = substr_replace($haystack,$replace,$pos,strlen($needle));
}

注意strlen($needle)，而不是strlen($replace)。Zombat的例子只有在针头和替代物长度相同的情况下才能正确工作。

下面是与PHP自己的str_replace具有相同签名的函数中的相同函数:

function str_replace_first($search, $replace, $subject) {
    $pos = strpos($subject, $search);
    if ($pos !== false) {
        return substr_replace($subject, $replace, $pos, strlen($search));
    }
    return $subject;
}

这是修改后的“too much php”的答案:

implode($replace, explode($search, $subject, 2));

注意最后的2而不是1。或函数格式:

function str_replace_first($search, $replace, $subject) {
    return implode($replace, explode($search, $subject, 2));
}

我对这两个函数进行了计时，当没有找到匹配时，第一个函数的速度是原来的两倍。当找到匹配时，它们的速度是一样的。