我想要str_replace()的一个版本,它只替换$subject中第一次出现的$search。有一个简单的解决方案,还是我需要一个hack的解决方案?


当前回答

如果你的字符串不包含任何多字节字符,如果你只想替换一个字符,你可以简单地使用strpos

这里是处理错误的函数

/**
 * Replace the first occurence of given string
 *
 * @param  string $search  a char to search in `$subject`
 * @param  string $replace a char to replace in `$subject`
 * @param  string $subject
 * @return string
 *
 * @throws InvalidArgumentException if `$search` or `$replace` are invalid or if `$subject` is a multibytes string
 */
function str_replace_first(string $search , string $replace , string $subject) : string {
    // check params
    if(strlen($replace) != 1 || strlen($search) != 1) {
        throw new InvalidArgumentException('$search & $replace must be char');
    }elseif(mb_strlen($subject) != strlen($subject)){
        throw new InvalidArgumentException('$subject is an multibytes string');
    }
    // search 
    $pos = strpos($subject, $search);
    if($pos === false) {
        // not found
        return $subject;
    }

    // replace
    $subject[$replace] = $subject;

    return $subject;
}

其他回答

我会用孕妇代替。它有一个LIMIT参数,你可以将它设置为1

preg_replace (regex, subst, string, limit) // default is -1

对于字符串

$string = 'OOO.OOO.OOO.S';
$search = 'OOO';
$replace = 'B';

//replace ONLY FIRST occurance of "OOO" with "B"
    $string = substr_replace($string,$replace,0,strlen($search));
    //$string => B.OOO.OOO.S

//replace ONLY LAST occurance of "OOOO" with "B"
    $string = substr_replace($string,$replace,strrpos($string,$search),strlen($search)) 
    //$string => OOO.OOO.B.S

    //replace ONLY LAST occurance of "OOOO" with "B"
    $string = strrev(implode(strrev($replace),explode(strrev($search),strrev($string),2)))
    //$string => OOO.OOO.B.S

对于单个字符

$string[strpos($string,$search)] = $replace;


//EXAMPLE

$string = 'O.O.O.O.S';
$search = 'O';
$replace = 'B';

//replace ONLY FIRST occurance of "O" with "B" 
    $string[strpos($string,$search)] = $replace;  
    //$string => B.O.O.O.S

//replace ONLY LAST occurance of "O" with "B" 
    $string[strrpos($string,$search)] = $replace; 
    // $string => B.O.O.B.S

根据我的测试结果,我想投票给karim79提供的regular_express。(我现在没有足够的声誉去投票!)

僵尸的解决方案使用了太多的函数调用,我甚至简化了代码。我使用PHP 5.4运行这两个解决方案10万次,结果如下:

$str = 'Hello abc, have a nice day abc! abc!';
$pos = strpos($str, 'abc');
$str = substr_replace($str, '123', $pos, 3);

1.85秒

$str = 'Hello abc, have a nice day abc! abc!';
$str = preg_replace('/abc/', '123', $str, 1);

1.35秒

如你所见。preg_replace的性能并不像很多人想象的那么差。所以如果你的常规快递不是很复杂的话,我建议你用一个漂亮的解决方案。

为了扩展zombat的答案(我认为这是最好的答案),我创建了他的函数的递归版本,该函数接受$limit参数来指定要替换的次数。

function str_replace_limit($haystack, $needle, $replace, $limit, $start_pos = 0) {
    if ($limit <= 0) {
        return $haystack;
    } else {
        $pos = strpos($haystack,$needle,$start_pos);
        if ($pos !== false) {
            $newstring = substr_replace($haystack, $replace, $pos, strlen($needle));
            return str_replace_limit($newstring, $needle, $replace, $limit-1, $pos+strlen($replace));
        } else {
            return $haystack;
        }
    }
}

=> CODE已被修订,所以考虑一些太旧的注释

感谢大家帮助我改进这一点 有任何BUG,请与我沟通;我马上就去做

那么,让我们开始:

将第一个o替换为ea,例如:

$s='I love you';
$s=str_replace_first('o','ea',$s);
echo $s;

//output: I leave you

功能:

function str_replace_first($this,$that,$s)
{
    $w=strpos($s,$this);
    if($w===false)return $s;
    return substr($s,0,$w).$that.substr($s,$w+strlen($this));
}