给定两个日期范围,确定两个日期是否重叠的最简单或最有效的方法是什么?
例如,假设我们有由DateTime变量StartDate1到EndDate1和StartDate2到EndDate2表示的范围。
给定两个日期范围,确定两个日期是否重叠的最简单或最有效的方法是什么?
例如,假设我们有由DateTime变量StartDate1到EndDate1和StartDate2到EndDate2表示的范围。
当前回答
下面的查询给出了提供的日期范围(开始和结束日期)与table_name中的任何日期(开始和终止日期)重叠的ID
select id from table_name where (START_DT_TM >= 'END_DATE_TIME' OR
(END_DT_TM BETWEEN 'START_DATE_TIME' AND 'END_DATE_TIME'))
其他回答
我认为,在以下情况下,两个范围重叠就足够了:
(StartDate1 <= EndDate2) and (StartDate2 <= EndDate1)
记住解决方案的一个简单方法是最小(结束)>最大(开始)
在Microsoft SQL SERVER中-SQL函数
CREATE FUNCTION IsOverlapDates
(
@startDate1 as datetime,
@endDate1 as datetime,
@startDate2 as datetime,
@endDate2 as datetime
)
RETURNS int
AS
BEGIN
DECLARE @Overlap as int
SET @Overlap = (SELECT CASE WHEN (
(@startDate1 BETWEEN @startDate2 AND @endDate2) -- caters for inner and end date outer
OR
(@endDate1 BETWEEN @startDate2 AND @endDate2) -- caters for inner and start date outer
OR
(@startDate2 BETWEEN @startDate1 AND @endDate1) -- only one needed for outer range where dates are inside.
) THEN 1 ELSE 0 END
)
RETURN @Overlap
END
GO
--Execution of the above code
DECLARE @startDate1 as datetime
DECLARE @endDate1 as datetime
DECLARE @startDate2 as datetime
DECLARE @endDate2 as datetime
DECLARE @Overlap as int
SET @startDate1 = '2014-06-01 01:00:00'
SET @endDate1 = '2014-06-01 02:00:00'
SET @startDate2 = '2014-06-01 01:00:00'
SET @endDate2 = '2014-06-01 01:30:00'
SET @Overlap = [dbo].[IsOverlapDates] (@startDate1, @endDate1, @startDate2, @endDate2)
SELECT Overlap = @Overlap
这是我的解决方案,当值不重叠时返回真值:
X开始1Y端1
开始2B端2
TEST1: (X <= A || X >= B)
&&
TEST2: (Y >= B || Y <= A)
&&
TEST3: (X >= B || Y <= A)
X-------------Y
A-----B
TEST1: TRUE
TEST2: TRUE
TEST3: FALSE
RESULT: FALSE
---------------------------------------
X---Y
A---B
TEST1: TRUE
TEST2: TRUE
TEST3: TRUE
RESULT: TRUE
---------------------------------------
X---Y
A---B
TEST1: TRUE
TEST2: TRUE
TEST3: TRUE
RESULT: TRUE
---------------------------------------
X----Y
A---------------B
TEST1: FALSE
TEST2: FALSE
TEST3: FALSE
RESULT: FALSE
为了涵盖PHP/LaravelCarbon包中的所有重叠情况,您可以在Charles的答案中展开逻辑,如下所示。
if ( ($startTime1->between($startTime2, $endTime2, true) || $endTime1->between($startTime2, $endTime2, true)) || (($startTime1 <= $endTime2) && ($endTime2 <= $endTime1)) ){
//Complete Overlap, Partial Left Overlap, Partial Right Overlap.
}
这将检查StartTime1是否在(StartTime2-EndTime2)范围之间,或者EndTime1是否位于(StartTime2-EndTime2的范围之间。
其余部分完全重叠,如其他答案所述。