给定两个日期范围,确定两个日期是否重叠的最简单或最有效的方法是什么?
例如,假设我们有由DateTime变量StartDate1到EndDate1和StartDate2到EndDate2表示的范围。
给定两个日期范围,确定两个日期是否重叠的最简单或最有效的方法是什么?
例如,假设我们有由DateTime变量StartDate1到EndDate1和StartDate2到EndDate2表示的范围。
当前回答
这里有一个可以在本地使用的通用方法。
// Takes a list and returns all records that have overlapping time ranges.
public static IEnumerable<T> GetOverlappedTimes<T>(IEnumerable<T> list, Func<T, bool> filter, Func<T,DateTime> start, Func<T, DateTime> end)
{
// Selects all records that match filter() on left side and returns all records on right side that overlap.
var overlap = from t1 in list
where filter(t1)
from t2 in list
where !object.Equals(t1, t2) // Don't match the same record on right side.
let in1 = start(t1)
let out1 = end(t1)
let in2 = start(t2)
let out2 = end(t2)
where in1 <= out2 && out1 >= in2
let totover = GetMins(in1, out1, in2, out2)
select t2;
return overlap;
}
public static void TestOverlap()
{
var tl1 = new TempTimeEntry() { ID = 1, Name = "Bill", In = "1/1/08 1:00pm".ToDate(), Out = "1/1/08 4:00pm".ToDate() };
var tl2 = new TempTimeEntry() { ID = 2, Name = "John", In = "1/1/08 5:00pm".ToDate(), Out = "1/1/08 6:00pm".ToDate() };
var tl3 = new TempTimeEntry() { ID = 3, Name = "Lisa", In = "1/1/08 7:00pm".ToDate(), Out = "1/1/08 9:00pm".ToDate() };
var tl4 = new TempTimeEntry() { ID = 4, Name = "Joe", In = "1/1/08 3:00pm".ToDate(), Out = "1/1/08 8:00pm".ToDate() };
var tl5 = new TempTimeEntry() { ID = 1, Name = "Bill", In = "1/1/08 8:01pm".ToDate(), Out = "1/1/08 8:00pm".ToDate() };
var list = new List<TempTimeEntry>() { tl1, tl2, tl3, tl4, tl5 };
var overlap = GetOverlappedTimes(list, (TempTimeEntry t1)=>t1.ID==1, (TempTimeEntry tIn) => tIn.In, (TempTimeEntry tOut) => tOut.Out);
Console.WriteLine("\nRecords overlap:");
foreach (var tl in overlap)
Console.WriteLine("Name:{0} T1In:{1} T1Out:{2}", tl.Name, tl.In, tl.Out);
Console.WriteLine("Done");
/* Output:
Records overlap:
Name:Joe T1In:1/1/2008 3:00:00 PM T1Out:1/1/2008 8:00:00 PM
Name:Lisa T1In:1/1/2008 7:00:00 PM T1Out:1/1/2008 9:00:00 PM
Done
*/
}
其他回答
if (StartDate1 > StartDate2) swap(StartDate, EndDate);
(StartDate1 <= EndDate2) and (StartDate2 <= EndDate1);
简单的解决方案:
compare the two dates:
A = the one with smaller start date, B = the one with bigger start date
if(A.end < B.start)
return false
return true
如果重叠本身也需要计算,可以使用以下公式:
overlap = max(0, min(EndDate1, EndDate2) - max(StartDate1, StartDate2))
if (overlap > 0) {
...
}
记住解决方案的一个简单方法是最小(结束)>最大(开始)
public static class NumberExtensionMethods
{
public static Boolean IsBetween(this Int64 value, Int64 Min, Int64 Max)
{
if (value >= Min && value <= Max) return true;
else return false;
}
public static Boolean IsBetween(this DateTime value, DateTime Min, DateTime Max)
{
Int64 numricValue = value.Ticks;
Int64 numericStartDate = Min.Ticks;
Int64 numericEndDate = Max.Ticks;
if (numricValue.IsBetween(numericStartDate, numericEndDate) )
{
return true;
}
return false;
}
}
public static Boolean IsOverlap(DateTime startDate1, DateTime endDate1, DateTime startDate2, DateTime endDate2)
{
Int64 numericStartDate1 = startDate1.Ticks;
Int64 numericEndDate1 = endDate1.Ticks;
Int64 numericStartDate2 = startDate2.Ticks;
Int64 numericEndDate2 = endDate2.Ticks;
if (numericStartDate2.IsBetween(numericStartDate1, numericEndDate1) ||
numericEndDate2.IsBetween(numericStartDate1, numericEndDate1) ||
numericStartDate1.IsBetween(numericStartDate2, numericEndDate2) ||
numericEndDate1.IsBetween(numericStartDate2, numericEndDate2))
{
return true;
}
return false;
}
if (IsOverlap(startdate1, enddate1, startdate2, enddate2))
{
Console.WriteLine("IsOverlap");
}