我如何使用Assert(或其他测试类)来验证在使用MSTest/Microsoft.VisualStudio.TestTools.UnitTesting时抛出了异常?
当前回答
通常你的测试框架会给出答案。但如果它不够灵活,你可以这样做:
try {
somethingThatShouldThrowAnException();
Assert.Fail(); // If it gets to this line, no exception was thrown
} catch (GoodException) { }
正如@Jonas指出的,这并不适用于捕捉基本异常:
try {
somethingThatShouldThrowAnException();
Assert.Fail(); // raises AssertionException
} catch (Exception) {
// Catches the assertion exception, and the test passes
}
如果绝对必须捕获Exception,则需要重新抛出Assert.Fail()。但实际上,这是一个你不应该手写的信号;检查测试框架中的选项,或者查看是否可以抛出更有意义的异常进行测试。
catch (AssertionException) { throw; }
您应该能够根据自己的需要调整这种方法——包括指定要捕获的异常类型。如果你只期望某些类型,完成catch块:
} catch (GoodException) {
} catch (Exception) {
// not the right kind of exception
Assert.Fail();
}
其他回答
我知道这个帖子很老了,有很多很好的答案,但值得一提的是,局部函数可以以一种非常简单的方式提供帮助。
//Arrange
//Act
void LocalFunction() => mr.ActualMethod(params);
//Assert
Assert.Throws<Exception>(LocalFunction);
在VS内置单元测试中,如果你只是想验证抛出了“任何异常”,但你不知道类型,你可以使用catch all:
[TestMethod]
[ExpectedException(typeof(Exception), AllowDerivedTypes = true)]
public void ThrowExceptionTest()
{
//...
}
Even though this is an old question, I would like to add a new thought to the discussion. I have extended the Arrange, Act, Assert pattern to be Expected, Arrange, Act, Assert. You can make an expected exception pointer, then assert it was assigned to. This feels cleaner than doing your Asserts in a catch block, leaving your Act section mostly just for the one line of code to call the method under test. You also don't have to Assert.Fail(); or return from multiple points in the code. Any other exception thrown will cause the test to fail, because it won't be caught, and if an exception of your expected type is thrown, but the it wasn't the one you were expecting, Asserting against the message or other properties of the exception help make sure your test won't pass inadvertently.
[TestMethod]
public void Bar_InvalidDependency_ThrowsInvalidOperationException()
{
// Expectations
InvalidOperationException expectedException = null;
string expectedExceptionMessage = "Bar did something invalid.";
// Arrange
IDependency dependency = DependencyMocks.Create();
Foo foo = new Foo(dependency);
// Act
try
{
foo.Bar();
}
catch (InvalidOperationException ex)
{
expectedException = ex;
}
// Assert
Assert.IsNotNull(expectedException);
Assert.AreEqual(expectedExceptionMessage, expectedException.Message);
}
这取决于您使用的测试框架?
例如,在MbUnit中,您可以用一个属性指定预期的异常,以确保您得到的是真正预期的异常。
[ExpectedException(typeof(ArgumentException))]
通常你的测试框架会给出答案。但如果它不够灵活,你可以这样做:
try {
somethingThatShouldThrowAnException();
Assert.Fail(); // If it gets to this line, no exception was thrown
} catch (GoodException) { }
正如@Jonas指出的,这并不适用于捕捉基本异常:
try {
somethingThatShouldThrowAnException();
Assert.Fail(); // raises AssertionException
} catch (Exception) {
// Catches the assertion exception, and the test passes
}
如果绝对必须捕获Exception,则需要重新抛出Assert.Fail()。但实际上,这是一个你不应该手写的信号;检查测试框架中的选项,或者查看是否可以抛出更有意义的异常进行测试。
catch (AssertionException) { throw; }
您应该能够根据自己的需要调整这种方法——包括指定要捕获的异常类型。如果你只期望某些类型,完成catch块:
} catch (GoodException) {
} catch (Exception) {
// not the right kind of exception
Assert.Fail();
}
推荐文章
- 实体框架核心:在上一个操作完成之前,在此上下文中开始的第二个操作
- 如何为构造函数定制Visual Studio的私有字段生成快捷方式?
- 为什么Visual Studio 2015/2017/2019测试运行器没有发现我的xUnit v2测试
- 如何使用JSON确保字符串是有效的JSON。网
- AppSettings从.config文件中获取值
- 通过HttpClient向REST API发布一个空体
- 如何检查IEnumerable是否为空或空?
- 自动化invokerrequired代码模式
- 在c#代码中设置WPF文本框的背景颜色
- 在c#中,什么是单子?
- 单元测试反模式目录
- c#和Java中的泛型有什么不同?和模板在c++ ?
- c#线程安全快速(est)计数器
- 如何将此foreach代码转换为Parallel.ForEach?
- 如何分裂()一个分隔字符串到一个列表<字符串>