我如何使用Assert(或其他测试类)来验证在使用MSTest/Microsoft.VisualStudio.TestTools.UnitTesting时抛出了异常?
当前回答
通常你的测试框架会给出答案。但如果它不够灵活,你可以这样做:
try {
somethingThatShouldThrowAnException();
Assert.Fail(); // If it gets to this line, no exception was thrown
} catch (GoodException) { }
正如@Jonas指出的,这并不适用于捕捉基本异常:
try {
somethingThatShouldThrowAnException();
Assert.Fail(); // raises AssertionException
} catch (Exception) {
// Catches the assertion exception, and the test passes
}
如果绝对必须捕获Exception,则需要重新抛出Assert.Fail()。但实际上,这是一个你不应该手写的信号;检查测试框架中的选项,或者查看是否可以抛出更有意义的异常进行测试。
catch (AssertionException) { throw; }
您应该能够根据自己的需要调整这种方法——包括指定要捕获的异常类型。如果你只期望某些类型,完成catch块:
} catch (GoodException) {
} catch (Exception) {
// not the right kind of exception
Assert.Fail();
}
其他回答
查看nUnit文档中的例子:
[ExpectedException( typeof( ArgumentException ) )]
在我正在做的一个项目中,我们有另一个解决方案。
首先,我不喜欢ExpectedExceptionAttribute,因为它确实考虑了导致异常的方法调用。
我用一个helper方法来代替它。
Test
[TestMethod]
public void AccountRepository_ThrowsExceptionIfFileisCorrupt()
{
var file = File.Create("Accounts.bin");
file.WriteByte(1);
file.Close();
IAccountRepository repo = new FileAccountRepository();
TestHelpers.AssertThrows<SerializationException>(()=>repo.GetAll());
}
HelperMethod
public static TException AssertThrows<TException>(Action action) where TException : Exception
{
try
{
action();
}
catch (TException ex)
{
return ex;
}
Assert.Fail("Expected exception was not thrown");
return null;
}
很整洁,不是吗?)
你可以从Nuget下载一个包,使用:PM> Install-Package MSTestExtensions将Assert.Throws()语法以nUnit/xUnit的风格添加到MsTest。
高级指令:从BaseTest下载程序集并继承,您可以使用Assert.Throws()语法。
Throws实现的主要方法如下所示:
public static void Throws<T>(Action task, string expectedMessage, ExceptionMessageCompareOptions options) where T : Exception
{
try
{
task();
}
catch (Exception ex)
{
AssertExceptionType<T>(ex);
AssertExceptionMessage(ex, expectedMessage, options);
return;
}
if (typeof(T).Equals(new Exception().GetType()))
{
Assert.Fail("Expected exception but no exception was thrown.");
}
else
{
Assert.Fail(string.Format("Expected exception of type {0} but no exception was thrown.", typeof(T)));
}
}
披露:我整理了这个包。
更多信息:http://www.bradoncode.com/blog/2012/01/asserting-exceptions-in-mstest-with.html
我最喜欢的实现方法是编写一个名为Throws的方法,并像使用其他Assert方法一样使用它。不幸的是,.NET不允许你编写静态扩展方法,所以你不能像使用Assert类中的构建一样使用这个方法;创建另一个MyAssert或类似的东西。类看起来像这样:
using System;
using Microsoft.VisualStudio.TestTools.UnitTesting;
namespace YourProject.Tests
{
public static class MyAssert
{
public static void Throws<T>( Action func ) where T : Exception
{
var exceptionThrown = false;
try
{
func.Invoke();
}
catch ( T )
{
exceptionThrown = true;
}
if ( !exceptionThrown )
{
throw new AssertFailedException(
String.Format("An exception of type {0} was expected, but not thrown", typeof(T))
);
}
}
}
}
这意味着你的单元测试看起来是这样的:
[TestMethod()]
public void ExceptionTest()
{
String testStr = null;
MyAssert.Throws<NullReferenceException>(() => testStr.ToUpper());
}
它的外观和行为更像单元测试语法的其余部分。
Even though this is an old question, I would like to add a new thought to the discussion. I have extended the Arrange, Act, Assert pattern to be Expected, Arrange, Act, Assert. You can make an expected exception pointer, then assert it was assigned to. This feels cleaner than doing your Asserts in a catch block, leaving your Act section mostly just for the one line of code to call the method under test. You also don't have to Assert.Fail(); or return from multiple points in the code. Any other exception thrown will cause the test to fail, because it won't be caught, and if an exception of your expected type is thrown, but the it wasn't the one you were expecting, Asserting against the message or other properties of the exception help make sure your test won't pass inadvertently.
[TestMethod]
public void Bar_InvalidDependency_ThrowsInvalidOperationException()
{
// Expectations
InvalidOperationException expectedException = null;
string expectedExceptionMessage = "Bar did something invalid.";
// Arrange
IDependency dependency = DependencyMocks.Create();
Foo foo = new Foo(dependency);
// Act
try
{
foo.Bar();
}
catch (InvalidOperationException ex)
{
expectedException = ex;
}
// Assert
Assert.IsNotNull(expectedException);
Assert.AreEqual(expectedExceptionMessage, expectedException.Message);
}
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