我如何使用Assert(或其他测试类)来验证在使用MSTest/Microsoft.VisualStudio.TestTools.UnitTesting时抛出了异常?


当前回答

有一个很棒的库叫做NFluent,它可以加速和简化你编写断言的方式。

编写抛出异常的断言非常简单:

    [Test]
    public void given_when_then()
    {
        Check.ThatCode(() => MethodToTest())
            .Throws<Exception>()
            .WithMessage("Process has been failed");
    }

其他回答

FluentAssertions例子

为那些使用该库的用户添加一个使用FluentAssertions的示例。

// act
Action result = () => {
    sut.DoSomething();
};

// assert
result.Should().Throw<Exception>();

异步的例子

// act
Func<Task> result = async () => {
    await sut.DoSomethingAsync();
};

// assert
await result.Should().ThrowAsync<Exception>();

作为一种替代方法,您可以尝试测试异常实际上是在您的测试中的下两行中抛出的。

var testDelegate = () => MyService.Method(params);
Assert.Throws<Exception>(testDelegate);

Even though this is an old question, I would like to add a new thought to the discussion. I have extended the Arrange, Act, Assert pattern to be Expected, Arrange, Act, Assert. You can make an expected exception pointer, then assert it was assigned to. This feels cleaner than doing your Asserts in a catch block, leaving your Act section mostly just for the one line of code to call the method under test. You also don't have to Assert.Fail(); or return from multiple points in the code. Any other exception thrown will cause the test to fail, because it won't be caught, and if an exception of your expected type is thrown, but the it wasn't the one you were expecting, Asserting against the message or other properties of the exception help make sure your test won't pass inadvertently.

[TestMethod]
public void Bar_InvalidDependency_ThrowsInvalidOperationException()
{
    // Expectations
    InvalidOperationException expectedException = null;
    string expectedExceptionMessage = "Bar did something invalid.";

    // Arrange
    IDependency dependency = DependencyMocks.Create();
    Foo foo = new Foo(dependency);

    // Act
    try
    {
        foo.Bar();
    }
    catch (InvalidOperationException ex)
    {
        expectedException = ex;
    }

    // Assert
    Assert.IsNotNull(expectedException);
    Assert.AreEqual(expectedExceptionMessage, expectedException.Message);
}

您可以通过简单的一行代码来实现这一点。

如果你的foo.bar()操作是异步的:

await Assert.ThrowsExceptionAsync<Exception>(() => foo.bar());

如果foo.bar()不是异步的

Assert.ThrowsException<Exception>(() => foo.bar());

有一个很棒的库叫做NFluent,它可以加速和简化你编写断言的方式。

编写抛出异常的断言非常简单:

    [Test]
    public void given_when_then()
    {
        Check.ThatCode(() => MethodToTest())
            .Throws<Exception>()
            .WithMessage("Process has been failed");
    }