看到了另一个VBA答案-这可以在excel-vba中用1行UDF完成:

Function GetColLetter(ByVal colID As Integer) As String
    If colID > Columns.Count Then
        Err.Raise 9, , "Column index out of bounds"
    Else
        GetColLetter = Split(Cells(1, colID).Address, "$")(1)
    End If
End Function

我正在尝试在Java中做同样的事情… 我写了以下代码:

private String getExcelColumnName(int columnNumber) {

    int dividend = columnNumber;
    String columnName = "";
    int modulo;

    while (dividend > 0)
    {
        modulo = (dividend - 1) % 26;

        char val = Character.valueOf((char)(65 + modulo));

        columnName += val;

        dividend = (int)((dividend - modulo) / 26);
    } 

    return columnName;
}

现在，一旦我用columnNumber = 29运行它，它给我的结果=“CA”(而不是“AC”) 有什么意见吗? 我知道我可以通过StringBuilder....反转它但看着格雷厄姆的回答，我有点困惑....

另一个解决方案:

private void Foo()
{
   l_ExcelApp = new Excel.ApplicationClass();
   l_ExcelApp.ReferenceStyle = Excel.XlReferenceStyle.xlR1C1;
   // ... now reference by R[row]C[column], Ex. A1 <==> R1C1, C6 <==> R3C6, ...
}

在这里查看更多- Excel中的单元格引用!作者:Nitin Paranjape博士

我的解决方案基于Graham, Herman Kan和desseim的回答，使用StringBuilder:

internal class Program
{
    #region get_excel_col_name
    /// <summary>
    /// Returns the name of the column by its number
    /// </summary>
    /// <param name="col_num">Column number</param>
    /// <returns>Column name</returns>
    /// <remarks>Numbering columns from zero</remarks>
    private static string get_excel_col_name(int col_num)
    {
        StringBuilder sb = new StringBuilder(2);
        if (col_num >= 0)
        {
            do
            {
                sb.Insert(0, (char)(col_num % 26 + 65));
                col_num /= 26;
            }
            while (--col_num >= 0);
        }
        return sb.ToString();
    }
    #endregion

    private static void Main(string[] args)
    {
        Console.WriteLine(get_excel_col_name(34));//outputs AI
        Console.ReadKey(true);
    }
}

在Java中实现相同

public String getExcelColumnName (int columnNumber) 
    {     
        int dividend = columnNumber;   
        int i;
        String columnName = "";     
        int modulo;     
        while (dividend > 0)     
        {        
            modulo = (dividend - 1) % 26;         
            i = 65 + modulo;
            columnName = new Character((char)i).toString() + columnName;        
            dividend = (int)((dividend - modulo) / 26);    
        }       
        return columnName; 
    }  

以下是Graham在Powershell中的代码:

function ConvertTo-ExcelColumnID {
param (
    [parameter(Position = 0,
        HelpMessage = "A 1-based index to convert to an excel column ID. e.g. 2 => 'B', 29 => 'AC'",
        Mandatory = $true)]
    [int]$index
);

[string]$result = '';
if ($index -le 0 ) {
    return $result;
}

while ($index -gt 0) {
    [int]$modulo = ($index - 1) % 26;
    $character = [char]($modulo + [int][char]'A');
    $result = $character + $result;
    [int]$index = ($index - $modulo) / 26;
}

return $result;

}