我正在开发一个应用程序在Android操作系统。我不知道如何检查位置服务是否启用。

我需要一个方法,如果它们被启用,返回“true”,如果没有“false”(所以在最后一种情况下,我可以显示一个对话框来启用它们)。


当前回答

我使用第一个代码开始创建方法isLocationEnabled

 private LocationManager locationManager ;

protected boolean isLocationEnabled(){
        String le = Context.LOCATION_SERVICE;
        locationManager = (LocationManager) getSystemService(le);
        if(!locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER)){
            return false;
        } else {
            return true;
        }
    }

和我检查条件,如果true打开地图和false给意图ACTION_LOCATION_SOURCE_SETTINGS

    if (isLocationEnabled()) {
        SupportMapFragment mapFragment = (SupportMapFragment) getSupportFragmentManager()
                .findFragmentById(R.id.map);
        mapFragment.getMapAsync(this);

        locationClient = getFusedLocationProviderClient(this);
        locationClient.getLastLocation()
                .addOnSuccessListener(new OnSuccessListener<Location>() {
                    @Override
                    public void onSuccess(Location location) {
                        // GPS location can be null if GPS is switched off
                        if (location != null) {
                            onLocationChanged(location);

                            Log.e("location", String.valueOf(location.getLongitude()));
                        }
                    }
                })
                .addOnFailureListener(new OnFailureListener() {
                    @Override
                    public void onFailure(@NonNull Exception e) {
                        Log.e("MapDemoActivity", e.toString());
                        e.printStackTrace();
                    }
                });


        startLocationUpdates();

    }
    else {
        new AlertDialog.Builder(this)
                .setTitle("Please activate location")
                .setMessage("Click ok to goto settings else exit.")
                .setPositiveButton(android.R.string.yes, new DialogInterface.OnClickListener() {
                    public void onClick(DialogInterface dialog, int which) {
                        Intent intent = new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS);
                        startActivity(intent);
                    }
                })
                .setNegativeButton(android.R.string.no, new DialogInterface.OnClickListener() {
                    public void onClick(DialogInterface dialog, int which) {
                        System.exit(0);
                    }
                })
                .show();
    }

其他回答

kotlin的

 private fun isLocationEnabled(mContext: Context): Boolean {
    val lm = mContext.getSystemService(Context.LOCATION_SERVICE) as LocationManager
    return lm.isProviderEnabled(LocationManager.GPS_PROVIDER) || lm.isProviderEnabled(
            LocationManager.NETWORK_PROVIDER)
 }

对话框

private fun showLocationIsDisabledAlert() {
    alert("We can't show your position because you generally disabled the location service for your device.") {
        yesButton {
        }
        neutralPressed("Settings") {
            startActivity(Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS))
        }
    }.show()
}

像这样调用

 if (!isLocationEnabled(this.context)) {
        showLocationIsDisabledAlert()
 }

提示:对话框需要以下导入(android studio应该为你处理这个)

import org.jetbrains.anko.alert
import org.jetbrains.anko.noButton

在清单中,您需要以下权限

<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION"/>
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"/>

迁移到AndroidX并使用

implementation 'androidx.appcompat:appcompat:1.3.0'

并使用LocationManagerCompat

在Java中

private boolean isLocationEnabled(Context context) {
    LocationManager locationManager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
    return LocationManagerCompat.isLocationEnabled(locationManager);
}

在Kotlin

private fun isLocationEnabled(context: Context): Boolean {
    val locationManager = context.getSystemService(Context.LOCATION_SERVICE) as LocationManager
    return LocationManagerCompat.isLocationEnabled(locationManager)
}

根据上面的答案,在API 23中,你需要添加“危险”权限检查以及检查系统本身:

public static boolean isLocationServicesAvailable(Context context) {
    int locationMode = 0;
    String locationProviders;
    boolean isAvailable = false;

    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT){
        try {
            locationMode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE);
        } catch (Settings.SettingNotFoundException e) {
            e.printStackTrace();
        }

        isAvailable = (locationMode != Settings.Secure.LOCATION_MODE_OFF);
    } else {
        locationProviders = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.LOCATION_PROVIDERS_ALLOWED);
        isAvailable = !TextUtils.isEmpty(locationProviders);
    }

    boolean coarsePermissionCheck = (ContextCompat.checkSelfPermission(context, Manifest.permission.ACCESS_COARSE_LOCATION) == PackageManager.PERMISSION_GRANTED);
    boolean finePermissionCheck = (ContextCompat.checkSelfPermission(context, Manifest.permission.ACCESS_FINE_LOCATION) == PackageManager.PERMISSION_GRANTED);

    return isAvailable && (coarsePermissionCheck || finePermissionCheck);
}
    LocationManager lm = (LocationManager)this.getSystemService(Context.LOCATION_SERVICE);
    boolean gps_enabled = false;
    boolean network_enabled = false;

    try {
        gps_enabled = lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
    } catch(Exception e){
         e.printStackTrace();
    }

    try {
        network_enabled = lm.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
    } catch(Exception e){
         e.printStackTrace();
    }

    if(!gps_enabled && !network_enabled) {
        // notify user
        new AlertDialog.Builder(this)
                .setMessage("Please turn on Location to continue")
                .setPositiveButton("Open Location Settings", new DialogInterface.OnClickListener() {
                    @Override
                    public void onClick(DialogInterface paramDialogInterface, int paramInt) {
                        startActivity(new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS));
                    }

                }).
                setNegativeButton("Cancel",null)
                .show();
    }

我使用这样的方式NETWORK_PROVIDER,但你可以添加和GPS。

LocationManager locationManager;

在onCreate中

   isLocationEnabled();
   if(!isLocationEnabled()) {
        AlertDialog.Builder builder = new AlertDialog.Builder(MainActivity.this);
        builder.setTitle(R.string.network_not_enabled)
                .setMessage(R.string.open_location_settings)
                .setPositiveButton(R.string.yes,
                        new DialogInterface.OnClickListener() {
                            public void onClick(DialogInterface dialog, int id) {
                                startActivity(new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS));
                            }
                        })
                .setNegativeButton(R.string.cancel,
                        new DialogInterface.OnClickListener() {
                            public void onClick(DialogInterface dialog, int id) {
                                dialog.cancel();
                            }
                        });
        AlertDialog alert = builder.create();
        alert.show();
    } 

检查方法

protected boolean isLocationEnabled(){
    String le = Context.LOCATION_SERVICE;
    locationManager = (LocationManager) getSystemService(le);
    if(!locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER)){
        return false;
    } else {
        return true;
    }
}