我正在开发一个应用程序在Android操作系统。我不知道如何检查位置服务是否启用。

我需要一个方法,如果它们被启用,返回“true”,如果没有“false”(所以在最后一种情况下,我可以显示一个对话框来启用它们)。


当前回答

您可以使用此代码引导用户到设置,在那里他们可以启用GPS:

    locationManager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
    if( !locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER) ) {
        new AlertDialog.Builder(context)
            .setTitle(R.string.gps_not_found_title)  // GPS not found
            .setMessage(R.string.gps_not_found_message) // Want to enable?
            .setPositiveButton(R.string.yes, new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialogInterface, int i) {
                    owner.startActivity(new Intent(android.provider.Settings.ACTION_LOCATION_SOURCE_SETTINGS));
                }
            })
            .setNegativeButton(R.string.no, null)
            .show();
    }

其他回答

您可以使用此代码引导用户到设置,在那里他们可以启用GPS:

    locationManager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
    if( !locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER) ) {
        new AlertDialog.Builder(context)
            .setTitle(R.string.gps_not_found_title)  // GPS not found
            .setMessage(R.string.gps_not_found_message) // Want to enable?
            .setPositiveButton(R.string.yes, new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialogInterface, int i) {
                    owner.startActivity(new Intent(android.provider.Settings.ACTION_LOCATION_SOURCE_SETTINGS));
                }
            })
            .setNegativeButton(R.string.no, null)
            .show();
    }
private boolean isGpsEnabled()
{
    LocationManager service = (LocationManager) getSystemService(LOCATION_SERVICE);
    return service.isProviderEnabled(LocationManager.GPS_PROVIDER)&&service.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
}

如果你正在使用AndroidX,使用下面的代码来检查位置服务是否启用:

fun isNetworkServiceEnabled(context: Context) = LocationManagerCompat.isLocationEnabled(context.getSystemService(LocationManager::class.java))

到2020年

最近,最好和最短的方法是

@SuppressWarnings("deprecation")
public static Boolean isLocationEnabled(Context context) {
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.P) {
        // This is a new method provided in API 28
        LocationManager lm = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
        return lm.isLocationEnabled();
    } else {
        // This was deprecated in API 28
        int mode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE,
                Settings.Secure.LOCATION_MODE_OFF);
        return (mode != Settings.Secure.LOCATION_MODE_OFF);
    }
}

这是一个非常有用的方法,如果启用了Location服务,它将返回“true”:

public static boolean locationServicesEnabled(Context context) {
        LocationManager lm = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
        boolean gps_enabled = false;
        boolean net_enabled = false;

        try {
            gps_enabled = lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
        } catch (Exception ex) {
            Log.e(TAG,"Exception gps_enabled");
        }

        try {
            net_enabled = lm.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
        } catch (Exception ex) {
            Log.e(TAG,"Exception network_enabled");
        }
        return gps_enabled || net_enabled;
}