在我看来，这个if子句很容易检查位置服务是否可用:

LocationManager locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
if(!locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER) && !locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER)) {
        //All location services are disabled

}

根据上面的答案，在API 23中，你需要添加“危险”权限检查以及检查系统本身:

public static boolean isLocationServicesAvailable(Context context) {
    int locationMode = 0;
    String locationProviders;
    boolean isAvailable = false;

    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT){
        try {
            locationMode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE);
        } catch (Settings.SettingNotFoundException e) {
            e.printStackTrace();
        }

        isAvailable = (locationMode != Settings.Secure.LOCATION_MODE_OFF);
    } else {
        locationProviders = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.LOCATION_PROVIDERS_ALLOWED);
        isAvailable = !TextUtils.isEmpty(locationProviders);
    }

    boolean coarsePermissionCheck = (ContextCompat.checkSelfPermission(context, Manifest.permission.ACCESS_COARSE_LOCATION) == PackageManager.PERMISSION_GRANTED);
    boolean finePermissionCheck = (ContextCompat.checkSelfPermission(context, Manifest.permission.ACCESS_FINE_LOCATION) == PackageManager.PERMISSION_GRANTED);

    return isAvailable && (coarsePermissionCheck || finePermissionCheck);
}

能用最简单的方法做吗

private boolean isLocationEnabled(Context context){
int mode =Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE,
                        Settings.Secure.LOCATION_MODE_OFF);
                final boolean enabled = (mode != android.provider.Settings.Secure.LOCATION_MODE_OFF);
return enabled;
}

迁移到AndroidX并使用

implementation 'androidx.appcompat:appcompat:1.3.0'

并使用LocationManagerCompat

在Java中

private boolean isLocationEnabled(Context context) {
    LocationManager locationManager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
    return LocationManagerCompat.isLocationEnabled(locationManager);
}

在Kotlin

private fun isLocationEnabled(context: Context): Boolean {
    val locationManager = context.getSystemService(Context.LOCATION_SERVICE) as LocationManager
    return LocationManagerCompat.isLocationEnabled(locationManager)
}

要在android谷歌地图中获取当前地理位置，您应该打开设备位置选项。要检查位置是否打开，您可以从onCreate()方法简单地调用此方法。

private void checkGPSStatus() {
    LocationManager locationManager = null;
    boolean gps_enabled = false;
    boolean network_enabled = false;
    if ( locationManager == null ) {
        locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
    }
    try {
        gps_enabled = locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER);
    } catch (Exception ex){}
    try {
        network_enabled = locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
    } catch (Exception ex){}
    if ( !gps_enabled && !network_enabled ){
        AlertDialog.Builder dialog = new AlertDialog.Builder(MyActivity.this);
        dialog.setMessage("GPS not enabled");
        dialog.setPositiveButton("Ok", new DialogInterface.OnClickListener() {

            @Override
            public void onClick(DialogInterface dialog, int which) {
                //this will navigate user to the device location settings screen
                Intent intent = new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS);
                startActivity(intent);
            }
        });
        AlertDialog alert = dialog.create();
        alert.show();
    }
}

在我看来，这个if子句很容易检查位置服务是否可用:

LocationManager locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
if(!locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER) && !locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER)) {
        //All location services are disabled

}