我正在开发一个应用程序在Android操作系统。我不知道如何检查位置服务是否启用。
我需要一个方法,如果它们被启用,返回“true”,如果没有“false”(所以在最后一种情况下,我可以显示一个对话框来启用它们)。
我正在开发一个应用程序在Android操作系统。我不知道如何检查位置服务是否启用。
我需要一个方法,如果它们被启用,返回“true”,如果没有“false”(所以在最后一种情况下,我可以显示一个对话框来启用它们)。
当前回答
你可以请求位置更新并同时显示对话框,就像GoogleMaps一样。代码如下:
googleApiClient = new GoogleApiClient.Builder(getActivity())
.addApi(LocationServices.API)
.addConnectionCallbacks(this)
.addOnConnectionFailedListener(this).build();
googleApiClient.connect();
LocationRequest locationRequest = LocationRequest.create();
locationRequest.setPriority(LocationRequest.PRIORITY_HIGH_ACCURACY);
locationRequest.setInterval(30 * 1000);
locationRequest.setFastestInterval(5 * 1000);
LocationSettingsRequest.Builder builder = new LocationSettingsRequest.Builder()
.addLocationRequest(locationRequest);
builder.setAlwaysShow(true); //this is the key ingredient
PendingResult<LocationSettingsResult> result = LocationServices.SettingsApi.checkLocationSettings(googleApiClient, builder.build());
result.setResultCallback(new ResultCallback<LocationSettingsResult>() {
@Override
public void onResult(LocationSettingsResult result) {
final Status status = result.getStatus();
final LocationSettingsStates state = result.getLocationSettingsStates();
switch (status.getStatusCode()) {
case LocationSettingsStatusCodes.SUCCESS:
// All location settings are satisfied. The client can initialize location
// requests here.
break;
case LocationSettingsStatusCodes.RESOLUTION_REQUIRED:
// Location settings are not satisfied. But could be fixed by showing the user
// a dialog.
try {
// Show the dialog by calling startResolutionForResult(),
// and check the result in onActivityResult().
status.startResolutionForResult(getActivity(), 1000);
} catch (IntentSender.SendIntentException ignored) {}
break;
case LocationSettingsStatusCodes.SETTINGS_CHANGE_UNAVAILABLE:
// Location settings are not satisfied. However, we have no way to fix the
// settings so we won't show the dialog.
break;
}
}
});
}
如果需要更多信息,请检查LocationRequest类。
其他回答
要检查网络提供者,你只需要将传递给isProviderEnabled的字符串更改为LocationManager。NETWORK_PROVIDER如果你检查GPS提供者和网络提供者的返回值-两个false都表示没有位置服务
You can also use extension function.
------------------------------------
fun Context.isLocationEnabled(): Boolean{
val locationManager = getSystemService(Context.LOCATION_SERVICE) as LocationManager
return LocationManagerCompat.isLocationEnabled(locationManager)}
如果没有启用任何提供程序,则“passive”是返回的最佳提供程序。 参见https://stackoverflow.com/a/4519414/621690
public boolean isLocationServiceEnabled() {
LocationManager lm = (LocationManager)
this.getSystemService(Context.LOCATION_SERVICE);
String provider = lm.getBestProvider(new Criteria(), true);
return (StringUtils.isNotBlank(provider) &&
!LocationManager.PASSIVE_PROVIDER.equals(provider));
}
我使用下面的代码来检查:
public static boolean isLocationEnabled(Context context) {
int locationMode = 0;
String locationProviders;
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT){
try {
locationMode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE);
} catch (SettingNotFoundException e) {
e.printStackTrace();
return false;
}
return locationMode != Settings.Secure.LOCATION_MODE_OFF;
}else{
locationProviders = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.LOCATION_PROVIDERS_ALLOWED);
return !TextUtils.isEmpty(locationProviders);
}
}
要在android谷歌地图中获取当前地理位置,您应该打开设备位置选项。要检查位置是否打开,您可以从onCreate()方法简单地调用此方法。
private void checkGPSStatus() {
LocationManager locationManager = null;
boolean gps_enabled = false;
boolean network_enabled = false;
if ( locationManager == null ) {
locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
}
try {
gps_enabled = locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER);
} catch (Exception ex){}
try {
network_enabled = locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
} catch (Exception ex){}
if ( !gps_enabled && !network_enabled ){
AlertDialog.Builder dialog = new AlertDialog.Builder(MyActivity.this);
dialog.setMessage("GPS not enabled");
dialog.setPositiveButton("Ok", new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int which) {
//this will navigate user to the device location settings screen
Intent intent = new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS);
startActivity(intent);
}
});
AlertDialog alert = dialog.create();
alert.show();
}
}