我使用下面的代码来检查:

public static boolean isLocationEnabled(Context context) {
    int locationMode = 0;
    String locationProviders;

    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT){
        try {
            locationMode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE);

        } catch (SettingNotFoundException e) {
            e.printStackTrace();
            return false;
        }

        return locationMode != Settings.Secure.LOCATION_MODE_OFF;

    }else{
        locationProviders = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.LOCATION_PROVIDERS_ALLOWED);
        return !TextUtils.isEmpty(locationProviders);
    }


} 

kotlin的

 private fun isLocationEnabled(mContext: Context): Boolean {
    val lm = mContext.getSystemService(Context.LOCATION_SERVICE) as LocationManager
    return lm.isProviderEnabled(LocationManager.GPS_PROVIDER) || lm.isProviderEnabled(
            LocationManager.NETWORK_PROVIDER)
 }

对话框

private fun showLocationIsDisabledAlert() {
    alert("We can't show your position because you generally disabled the location service for your device.") {
        yesButton {
        }
        neutralPressed("Settings") {
            startActivity(Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS))
        }
    }.show()
}

像这样调用

 if (!isLocationEnabled(this.context)) {
        showLocationIsDisabledAlert()
 }

提示:对话框需要以下导入(android studio应该为你处理这个)

import org.jetbrains.anko.alert
import org.jetbrains.anko.noButton

在清单中，您需要以下权限

<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION"/>
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"/>

要检查网络提供者，你只需要将传递给isProviderEnabled的字符串更改为LocationManager。NETWORK_PROVIDER如果你检查GPS提供者和网络提供者的返回值-两个false都表示没有位置服务

如果你正在使用AndroidX，使用下面的代码来检查位置服务是否启用:

fun isNetworkServiceEnabled(context: Context) = LocationManagerCompat.isLocationEnabled(context.getSystemService(LocationManager::class.java))

您可以使用此代码引导用户到设置，在那里他们可以启用GPS:

    locationManager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
    if( !locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER) ) {
        new AlertDialog.Builder(context)
            .setTitle(R.string.gps_not_found_title)  // GPS not found
            .setMessage(R.string.gps_not_found_message) // Want to enable?
            .setPositiveButton(R.string.yes, new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialogInterface, int i) {
                    owner.startActivity(new Intent(android.provider.Settings.ACTION_LOCATION_SOURCE_SETTINGS));
                }
            })
            .setNegativeButton(R.string.no, null)
            .show();
    }

我使用这样的方式NETWORK_PROVIDER，但你可以添加和GPS。

LocationManager locationManager;

在onCreate中

   isLocationEnabled();
   if(!isLocationEnabled()) {
        AlertDialog.Builder builder = new AlertDialog.Builder(MainActivity.this);
        builder.setTitle(R.string.network_not_enabled)
                .setMessage(R.string.open_location_settings)
                .setPositiveButton(R.string.yes,
                        new DialogInterface.OnClickListener() {
                            public void onClick(DialogInterface dialog, int id) {
                                startActivity(new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS));
                            }
                        })
                .setNegativeButton(R.string.cancel,
                        new DialogInterface.OnClickListener() {
                            public void onClick(DialogInterface dialog, int id) {
                                dialog.cancel();
                            }
                        });
        AlertDialog alert = builder.create();
        alert.show();
    } 

检查方法

protected boolean isLocationEnabled(){
    String le = Context.LOCATION_SERVICE;
    locationManager = (LocationManager) getSystemService(le);
    if(!locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER)){
        return false;
    } else {
        return true;
    }
}