是的，你可以检查以下是代码:

public boolean isGPSEnabled(Context mContext) 
{
    LocationManager lm = (LocationManager)
    mContext.getSystemService(Context.LOCATION_SERVICE);
    return lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
}

在manifest文件中的权限下:

<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION" />

要在android谷歌地图中获取当前地理位置，您应该打开设备位置选项。要检查位置是否打开，您可以从onCreate()方法简单地调用此方法。

private void checkGPSStatus() {
    LocationManager locationManager = null;
    boolean gps_enabled = false;
    boolean network_enabled = false;
    if ( locationManager == null ) {
        locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
    }
    try {
        gps_enabled = locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER);
    } catch (Exception ex){}
    try {
        network_enabled = locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
    } catch (Exception ex){}
    if ( !gps_enabled && !network_enabled ){
        AlertDialog.Builder dialog = new AlertDialog.Builder(MyActivity.this);
        dialog.setMessage("GPS not enabled");
        dialog.setPositiveButton("Ok", new DialogInterface.OnClickListener() {

            @Override
            public void onClick(DialogInterface dialog, int which) {
                //this will navigate user to the device location settings screen
                Intent intent = new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS);
                startActivity(intent);
            }
        });
        AlertDialog alert = dialog.create();
        alert.show();
    }
}

根据上面的答案，在API 23中，你需要添加“危险”权限检查以及检查系统本身:

public static boolean isLocationServicesAvailable(Context context) {
    int locationMode = 0;
    String locationProviders;
    boolean isAvailable = false;

    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT){
        try {
            locationMode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE);
        } catch (Settings.SettingNotFoundException e) {
            e.printStackTrace();
        }

        isAvailable = (locationMode != Settings.Secure.LOCATION_MODE_OFF);
    } else {
        locationProviders = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.LOCATION_PROVIDERS_ALLOWED);
        isAvailable = !TextUtils.isEmpty(locationProviders);
    }

    boolean coarsePermissionCheck = (ContextCompat.checkSelfPermission(context, Manifest.permission.ACCESS_COARSE_LOCATION) == PackageManager.PERMISSION_GRANTED);
    boolean finePermissionCheck = (ContextCompat.checkSelfPermission(context, Manifest.permission.ACCESS_FINE_LOCATION) == PackageManager.PERMISSION_GRANTED);

    return isAvailable && (coarsePermissionCheck || finePermissionCheck);
}

到2020年

最近，最好和最短的方法是

@SuppressWarnings("deprecation")
public static Boolean isLocationEnabled(Context context) {
    if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.P) {
        // This is a new method provided in API 28
        LocationManager lm = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
        return lm.isLocationEnabled();
    } else {
        // This was deprecated in API 28
        int mode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE,
                Settings.Secure.LOCATION_MODE_OFF);
        return (mode != Settings.Secure.LOCATION_MODE_OFF);
    }
}

你可以请求位置更新并同时显示对话框，就像GoogleMaps一样。代码如下:

googleApiClient = new GoogleApiClient.Builder(getActivity())
                .addApi(LocationServices.API)
                .addConnectionCallbacks(this)
                .addOnConnectionFailedListener(this).build();
googleApiClient.connect();

LocationRequest locationRequest = LocationRequest.create();
locationRequest.setPriority(LocationRequest.PRIORITY_HIGH_ACCURACY);
locationRequest.setInterval(30 * 1000);
locationRequest.setFastestInterval(5 * 1000);
LocationSettingsRequest.Builder builder = new LocationSettingsRequest.Builder()
                    .addLocationRequest(locationRequest);

builder.setAlwaysShow(true); //this is the key ingredient

PendingResult<LocationSettingsResult> result = LocationServices.SettingsApi.checkLocationSettings(googleApiClient, builder.build());
result.setResultCallback(new ResultCallback<LocationSettingsResult>() {
    @Override
    public void onResult(LocationSettingsResult result) {
        final Status status = result.getStatus();
        final LocationSettingsStates state = result.getLocationSettingsStates();
        switch (status.getStatusCode()) {
            case LocationSettingsStatusCodes.SUCCESS:
                // All location settings are satisfied. The client can initialize location
                // requests here.
                break;
            case LocationSettingsStatusCodes.RESOLUTION_REQUIRED:
                // Location settings are not satisfied. But could be fixed by showing the user
                // a dialog.
                try {
                    // Show the dialog by calling startResolutionForResult(),
                    // and check the result in onActivityResult().
                    status.startResolutionForResult(getActivity(), 1000);
                } catch (IntentSender.SendIntentException ignored) {}
                break;
            case LocationSettingsStatusCodes.SETTINGS_CHANGE_UNAVAILABLE:
                // Location settings are not satisfied. However, we have no way to fix the
                // settings so we won't show the dialog.
                break;
            }
        }
    });
}

如果需要更多信息，请检查LocationRequest类。

迁移到AndroidX并使用

implementation 'androidx.appcompat:appcompat:1.3.0'

并使用LocationManagerCompat

在Java中

private boolean isLocationEnabled(Context context) {
    LocationManager locationManager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
    return LocationManagerCompat.isLocationEnabled(locationManager);
}

在Kotlin

private fun isLocationEnabled(context: Context): Boolean {
    val locationManager = context.getSystemService(Context.LOCATION_SERVICE) as LocationManager
    return LocationManagerCompat.isLocationEnabled(locationManager)
}