当尝试使用Attach()和SaveChanges()组合更新记录时，我也有同样的问题，但我使用的是SQLite DB及其EF提供者(相同的代码在SQLServer DB中工作没有问题)。

I found out, when your DB column has GUID (or UniqueIdentity) in SQLite and your model is nvarchar, SQLIte EF treats it as Binary(i.e., byte[]) by default. So when SQLite EF provider tries to convert GUID into the model (string in my case) it will fail as it will convert to byte[]. The fix is to tell the SQLite EF to treat GUID as TEXT (and therefore conversion is into strings, not byte[]) by defining "BinaryGUID=false;" in the connectionstring (or metadata, if you're using database first) like so:

  <connectionStrings>
    <add name="Entities" connectionString="metadata=res://savetyping...=System.Data.SQLite.EF6;provider connection string=&quot;data source=C:\...\db.sqlite3;Version=3;BinaryGUID=false;App=EntityFramework&quot;" providerName="System.Data.EntityClient" />
  </connectionStrings>

链接到对我有效的解决方案: SQLite实体框架6提供者如何处理指南?

using(var myDb = new MyDbEntities())
{

    user user = new user();
    user.username = "me";
    user.email = "me@me.com";

    myDb.Users.Add(user);
    myDb.users.Attach(user);
    myDb.Entry(user).State = EntityState.Modified;//this is for modiying/update existing entry
    myDb.SaveChanges();
}

你可以使用AddOrUpdate方法:

db.Books.AddOrUpdate(book); //requires using System.Data.Entity.Migrations;
db.SaveChanges();

我知道这个问题已经被回答过几次了，但我喜欢下面的方法。我希望它能帮助到一些人。

//attach object (search for row)
TableName tn = _context.TableNames.Attach(new TableName { PK_COLUMN = YOUR_VALUE});
// set new value
tn.COLUMN_NAME_TO_UPDATE = NEW_COLUMN_VALUE;
// set column as modified
_context.Entry<TableName>(tn).Property(tnp => tnp.COLUMN_NAME_TO_UPDATE).IsModified = true;
// save change
_context.SaveChanges();

这里是这个问题的最佳解决方案:在视图中添加所有的ID(键)。考虑将多个表命名为(First, Second和Third)

@Html.HiddenFor(model=>model.FirstID)
@Html.HiddenFor(model=>model.SecondID)
@Html.HiddenFor(model=>model.Second.SecondID)
@Html.HiddenFor(model=>model.Second.ThirdID)
@Html.HiddenFor(model=>model.Second.Third.ThirdID)

在c#代码中，

[HttpPost]
public ActionResult Edit(First first)
{
  if (ModelState.Isvalid)
  {
    if (first.FirstID > 0)
    {
      datacontext.Entry(first).State = EntityState.Modified;
      datacontext.Entry(first.Second).State = EntityState.Modified;
      datacontext.Entry(first.Second.Third).State = EntityState.Modified;
    }
    else
    {
      datacontext.First.Add(first);
    }
    datacontext.SaveChanges();
    Return RedirectToAction("Index");
  }

 return View(first);
}

最简单的方法是这样的。

var book = new Model.Book
{
    BookNumber =  _book.BookNumber,
    BookName = _book.BookName,
    BookTitle = _book.BookTitle,
};
using (var db = new MyContextDB())
{
    var result = db.Books.SingleOrDefault(b => b.BookNumber == bookNumber);
    if (result != null)
    {
        try
        {
            // you can't attach book since it doesn't exist in the database yet
            // attach result instead
            db.Books.Attach(result);
            result = book; // this will update all the fields at once
            db.SaveChanges();
        }
        catch (Exception ex)
        {
            throw;
        }
    }
}