rails + arel，一个更清晰的方式:

# Table name: messages
#
# sender_id:    integer
# recipient_id: integer
# content:      text

class Message < ActiveRecord::Base
  scope :by_participant, ->(user_id) do
    left  = arel_table[:sender_id].eq(user_id)
    right = arel_table[:recipient_id].eq(user_id)

    where(Arel::Nodes::Or.new(left, right))
  end
end

生产:

$ Message.by_participant(User.first.id).to_sql 
=> SELECT `messages`.* 
     FROM `messages` 
    WHERE `messages`.`sender_id` = 1 
       OR `messages`.`recipient_id` = 1

MetaWhere插件非常棒。

轻松混合OR's和and 's，任何关联的连接条件，甚至指定OUTER join 's!

Post.where({sharing_level: Post::Sharing[:everyone]} | ({sharing_level: Post::Sharing[:friends]} & {user: {followers: current_user} }).joins(:user.outer => :followers.outer}

rails + arel，一个更清晰的方式:

# Table name: messages
#
# sender_id:    integer
# recipient_id: integer
# content:      text

class Message < ActiveRecord::Base
  scope :by_participant, ->(user_id) do
    left  = arel_table[:sender_id].eq(user_id)
    right = arel_table[:recipient_id].eq(user_id)

    where(Arel::Nodes::Or.new(left, right))
  end
end

生产:

$ Message.by_participant(User.first.id).to_sql 
=> SELECT `messages`.* 
     FROM `messages` 
    WHERE `messages`.`sender_id` = 1 
       OR `messages`.`recipient_id` = 1

如果你想使用数组作为参数，下面的代码在Rails 4中工作:

query = Order.where(uuid: uuids, id: ids)
Order.where(query.where_values.map(&:to_sql).join(" OR "))
#=> Order Load (0.7ms)  SELECT "orders".* FROM "orders" WHERE ("orders"."uuid" IN ('5459eed8350e1b472bfee48375034103', '21313213jkads', '43ujrefdk2384us') OR "orders"."id" IN (2, 3, 4))

更多信息:在Rails 4中使用数组作为参数的OR查询。

Rails/ActiveRecord的更新版本可能原生支持此语法。它看起来类似于:

Foo.where(foo: 'bar').or.where(bar: 'bar')

如此拉请求https://github.com/rails/rails/pull/9052中所述

现在，只要坚持下面的方法就可以了:

Foo.where('foo= ? OR bar= ?', 'bar', 'bar')

更新:根据https://github.com/rails/rails/pull/16052, or特性将在Rails 5中可用

更新:特性已经合并到Rails 5分支

我想添加这是一个解决方案搜索一个ActiveRecord的多个属性。自

.where(A: param[:A], B: param[:B])

会搜索A和B。