你可以这样做:

Person.where("name = ? OR age = ?", 'Pearl', 24)

或者更优雅一点，安装rails_or gem并像这样做:

Person.where(:name => 'Pearl').or(:age => 24)

在Rails 3中，应该是这样

Model.where("column = ? or other_column = ?", value, other_value)

这也包括原始sql，但我不认为有一种方式在ActiveRecord做或操作。你的问题不是新手的问题。

Rails 5添加了或，所以现在在Rails版本大于5的应用程序中更容易做到这一点:

Model.where(column: value).or(Model.where(other_column: other_value)

这也可以处理nil值

用服装

t = Post.arel_table

results = Post.where(
  t[:author].eq("Someone").
  or(t[:title].matches("%something%"))
)

结果SQL:

ree-1.8.7-2010.02 > puts Post.where(t[:author].eq("Someone").or(t[:title].matches("%something%"))).to_sql
SELECT     "posts".* FROM       "posts"  WHERE     (("posts"."author" = 'Someone' OR "posts"."title" LIKE '%something%'))

Rails最近将其添加到ActiveRecord中。它将在Rails 5中发布。已致力于掌握:

https://github.com/rails/rails/commit/9e42cf019f2417473e7dcbfcb885709fa2709f89

Post.where(column: 'something').or(Post.where(other: 'else'))

# => SELECT * FROM posts WHERE (column = 'something') OR (other = 'else)

只要在条件中添加一个OR

Model.find(:all, :conditions => ["column = ? OR other_column = ?",value, other_value])

MetaWhere插件非常棒。

轻松混合OR's和and 's，任何关联的连接条件，甚至指定OUTER join 's!

Post.where({sharing_level: Post::Sharing[:everyone]} | ({sharing_level: Post::Sharing[:friends]} & {user: {followers: current_user} }).joins(:user.outer => :followers.outer}