什么是最有效的方式来克隆一个JavaScript对象?我已经看到obj = eval(uneval(o));被使用,但它是非标准的,仅支持Firefox.我做了事情,如obj = JSON.parse(JSON.stringify(o));但质疑效率。
当前回答
因为回归只是太昂贵的JavaScript,我发现的大多数答案是使用回归,而JSON方法将错过非JSON转换部分(功能等)。所以我做了一些研究,并发现这个拖拉机技术避免它。
/*
* Trampoline to avoid recursion in JavaScript, see:
* https://www.integralist.co.uk/posts/functional-recursive-javascript-programming/
*/
function trampoline() {
var func = arguments[0];
var args = [];
for (var i = 1; i < arguments.length; i++) {
args[i - 1] = arguments[i];
}
var currentBatch = func.apply(this, args);
var nextBatch = [];
while (currentBatch && currentBatch.length > 0) {
currentBatch.forEach(function(eachFunc) {
var ret = eachFunc();
if (ret && ret.length > 0) {
nextBatch = nextBatch.concat(ret);
}
});
currentBatch = nextBatch;
nextBatch = [];
}
};
/*
* Deep clone an object using the trampoline technique.
*
* @param target {Object} Object to clone
* @return {Object} Cloned object.
*/
function clone(target) {
if (typeof target !== 'object') {
return target;
}
if (target == null || Object.keys(target).length == 0) {
return target;
}
function _clone(b, a) {
var nextBatch = [];
for (var key in b) {
if (typeof b[key] === 'object' && b[key] !== null) {
if (b[key] instanceof Array) {
a[key] = [];
}
else {
a[key] = {};
}
nextBatch.push(_clone.bind(null, b[key], a[key]));
}
else {
a[key] = b[key];
}
}
return nextBatch;
};
var ret = target instanceof Array ? [] : {};
(trampoline.bind(null, _clone))(target, ret);
return ret;
};
其他回答
代码:
// extends 'from' object with members from 'to'. If 'to' is null, a deep clone of 'from' is returned
function extend(from, to)
{
if (from == null || typeof from != "object") return from;
if (from.constructor != Object && from.constructor != Array) return from;
if (from.constructor == Date || from.constructor == RegExp || from.constructor == Function ||
from.constructor == String || from.constructor == Number || from.constructor == Boolean)
return new from.constructor(from);
to = to || new from.constructor();
for (var name in from)
{
to[name] = typeof to[name] == "undefined" ? extend(from[name], null) : to[name];
}
return to;
}
测试:
var obj =
{
date: new Date(),
func: function(q) { return 1 + q; },
num: 123,
text: "asdasd",
array: [1, "asd"],
regex: new RegExp(/aaa/i),
subobj:
{
num: 234,
text: "asdsaD"
}
}
var clone = extend(obj);
对象的克隆一直是JS的担忧,但在ES6之前,我列出了在下面的JavaScript中复制对象的不同方式,想象你有下面的对象,我希望有一个深刻的副本:
var obj = {a:1, b:2, c:3, d:4};
有几种方法可以复制这个对象,而不会改变其起源:
ES5+,使用一个简单的函数来为您进行复制:函数 deepCopyObj(obj) {如果(null == obj <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk> <unk>
希望这些帮助......
Object.assign({},sourceObj)只有在其属性没有参考类型密钥时才会克隆对象。
obj={a:"lol",b:["yes","no","maybe"]}
clonedObj = Object.assign({},obj);
clonedObj.b.push("skip")// changes will reflected to the actual obj as well because of its reference type.
obj.b //will also console => yes,no,maybe,skip
因此,对于深度克隆,不可能以这种方式实现。
最有效的解决方案是
var obj = Json.stringify(yourSourceObj)
var cloned = Json.parse(obj);
单线 ECMAScript 6 解决方案(特殊对象类型如 Date/Regex 未处理):
const clone = (o) => typeof o === 'object' && o!== null? // only clone objects (Array.isArray(o)? // if cloning an array o.map(e => clone(e)) : // clone each of its elements Object.keys(o).reduce( // otherwise reduce every key in the object (r, k) => (r[k] = clone(o[k]), r), {} // and save its cloned value
如果沒有任何內建一個,你可以嘗試:
function clone(obj) {
if (obj === null || typeof (obj) !== 'object' || 'isActiveClone' in obj)
return obj;
if (obj instanceof Date)
var temp = new obj.constructor(); //or new Date(obj);
else
var temp = obj.constructor();
for (var key in obj) {
if (Object.prototype.hasOwnProperty.call(obj, key)) {
obj['isActiveClone'] = null;
temp[key] = clone(obj[key]);
delete obj['isActiveClone'];
}
}
return temp;
}