如何删除没有唯一行id存在的重复行?

我的座位是

col1  col2 col3 col4 col5 col6 col7
john  1    1    1    1    1    1 
john  1    1    1    1    1    1
sally 2    2    2    2    2    2
sally 2    2    2    2    2    2

我想留下以下重复删除后:

john  1    1    1    1    1    1
sally 2    2    2    2    2    2

我尝试了一些查询,但我认为他们取决于有一个行id,因为我没有得到想要的结果。例如:

DELETE
FROM table
WHERE col1 IN (
    SELECT id
    FROM table
    GROUP BY id
    HAVING (COUNT(col1) > 1)
)

当前回答

从一个巨大的(几百万条记录)表中删除重复项可能需要很长时间。我建议将所选行的批量插入到临时表中,而不是删除。

--REWRITING YOUR CODE(TAKE NOTE OF THE 3RD LINE) WITH CTE AS(SELECT NAME,ROW_NUMBER() 
OVER (PARTITION BY NAME ORDER BY NAME) ID FROM @TB) SELECT * INTO #unique_records FROM 
CTE WHERE ID =1;

其他回答

DELETE from search
where id not in (
   select min(id) from search
   group by url
   having count(*)=1

   union

   SELECT min(id) FROM search
   group by url
   having count(*) > 1
)

要在SQL Server中删除表中的重复行,请执行以下步骤:

使用GROUP BY子句或ROW_NUMBER()函数查找重复的行。 使用DELETE语句删除重复的行。

设置一个示例表

DROP TABLE IF EXISTS contacts;

CREATE TABLE contacts(
    contact_id INT IDENTITY(1,1) PRIMARY KEY,
    first_name NVARCHAR(100) NOT NULL,
    last_name NVARCHAR(100) NOT NULL,
    email NVARCHAR(255) NOT NULL,
);

插入的值

INSERT INTO contacts
    (first_name,last_name,email) 
VALUES
    ('Syed','Abbas','syed.abbas@example.com'),
    ('Catherine','Abel','catherine.abel@example.com'),
    ('Kim','Abercrombie','kim.abercrombie@example.com'),
    ('Kim','Abercrombie','kim.abercrombie@example.com'),
    ('Kim','Abercrombie','kim.abercrombie@example.com'),
    ('Hazem','Abolrous','hazem.abolrous@example.com'),
    ('Hazem','Abolrous','hazem.abolrous@example.com'),
    ('Humberto','Acevedo','humberto.acevedo@example.com'),
    ('Humberto','Acevedo','humberto.acevedo@example.com'),
    ('Pilar','Ackerman','pilar.ackerman@example.com');

查询

    SELECT 
   contact_id, 
   first_name, 
   last_name, 
   email
FROM 
   contacts;

从表中删除重复的行

   WITH cte AS (
    SELECT 
        contact_id, 
        first_name, 
        last_name, 
        email, 
        ROW_NUMBER() OVER (
            PARTITION BY 
                first_name, 
                last_name, 
                email
            ORDER BY 
                first_name, 
                last_name, 
                email
        ) row_num
     FROM 
        contacts
)
DELETE FROM cte
WHERE row_num > 1;

现在要删除记录吗

试着使用:

SELECT linkorder
    ,Row_Number() OVER (
        PARTITION BY linkorder ORDER BY linkorder DESC
        ) AS RowNum
FROM u_links

我喜欢CTE和ROW_NUMBER,因为两者结合起来可以让我们看到哪些行被删除(或更新),因此只需更改DELETE FROM CTE…SELECT * FROM CTE:

WITH CTE AS(
   SELECT [col1], [col2], [col3], [col4], [col5], [col6], [col7],
       RN = ROW_NUMBER()OVER(PARTITION BY col1 ORDER BY col1)
   FROM dbo.Table1
)
DELETE FROM CTE WHERE RN > 1

DEMO(结果不同;我想这是由于你的打字错误。

COL1    COL2    COL3    COL4    COL5    COL6    COL7
john    1        1       1       1       1       1
sally   2        2       2       2       2       2

由于使用了PARTITION by col1,这个例子通过一个列col1来确定重复项。如果你想包含多个列,只需将它们添加到PARTITION BY:

ROW_NUMBER()OVER(PARTITION BY Col1, Col2, ... ORDER BY OrderColumn)

微软有一个关于如何删除重复文件的非常简洁的指南。查看http://support.microsoft.com/kb/139444

简而言之,当你只有几行要删除时,下面是删除重复项的最简单方法:

SET rowcount 1;
DELETE FROM t1 WHERE myprimarykey=1;

Myprimarykey是行标识符。

我将rowcount设置为1,因为我只有两行复制。如果我复制了3行,那么我就会将rowcount设置为2,这样它就会删除它看到的前两行,只在表t1中留下一行。