问题通过以下方式解决:

 Bundle bundle = new Bundle();
  bundle.putSerializable("data", bigdata);
...
  CacheHelper.saveState(bundle,"DATA");
  Intent intent = new Intent(mActivity, AActivity.class);
  startActivity(intent, bb);// do not put data to intent.

In Activity:
   @Override
   protected void onCreate(Bundle savedInstanceState) {
        Bundle bundle = CacheHelper.getInstance().loadState(Constants.DATA);
        if (bundle != null){
            Intent intent = getIntent();
            intent.putExtras(bundle);
        }
        getIntent().getExtra(..);
        ....
   }
   @Override
    protected void onDestroy() {
        super.onDestroy();
        CacheHelper.clearState("DATA");
    }

public class CacheHelper {

    public static void saveState(Bundle savedInstanceState, String name) {
        Bundle saved = (Bundle) savedInstanceState.clone();
        save(name, saved);
    }
    public Bundle loadState(String name) {

        Object object = load(name);
        if (object != null) {
            Bundle bundle = (Bundle) object;
            return bundle;
        }
        return null;
    }
    private static void save(String fileName, Bundle object) {
        try {
            String path = StorageUtils.getFullPath(fileName);
            File file = new File(path);
            if (file.exists()) {
                file.delete();
            }
            FileOutputStream fos = new FileOutputStream(path, false);

            Parcel p = Parcel.obtain(); //creating empty parcel object
            object.writeToParcel(p, 0); //saving bundle as parcel
            //parcel.writeBundle(bundle);
            fos.write(p.marshall()); //writing parcel to file

            fos.flush();
            fos.close();

        } catch (Exception e) {
            e.printStackTrace();
        }
    }
    private static Bundle load(String fileName) {
        try {
            String path = StorageUtils.getFullPath(fileName);
            FileInputStream fis = new FileInputStream(path);

            byte[] array = new byte[(int) fis.getChannel().size()];
            fis.read(array, 0, array.length);

            Parcel parcel = Parcel.obtain(); //creating empty parcel object
            parcel.unmarshall(array, 0, array.length);
            parcel.setDataPosition(0);
            Bundle out = parcel.readBundle();
            out.putAll(out);

            fis.close();
            parcel.recycle();
            return out;
        } catch (Exception e) {
            e.printStackTrace();
        }
        return null;
    }
public static void clearState(Activity ac) {
    String name = ac.getClass().getName();
    String path = StorageUtils.getFullPath(name);
    File file = new File(path);
    if (file.exists()) {
        file.delete();
    }
}
}

将此添加到您的活动中

@Override
protected void onSaveInstanceState(Bundle oldInstanceState) {
    super.onSaveInstanceState(oldInstanceState);
    oldInstanceState.clear();
}

对我有用，希望对你也有帮助

如果您需要调查哪个包裹导致了崩溃，您应该考虑尝试TooLargeTool。

(我发现这是@Max Spencer在接受答案下的评论，这对我的情况很有帮助。)

确保你没有在Intent对象中放入大容量的数据。在我的情况下，我添加字符串500k大小，然后开始另一个活动。除了这个例外，它总是失败。我通过使用活动的静态变量避免了在活动之间共享数据——你不需要将它们发送到Intent，然后从Intent中提取。

我有的:

String html = new String();//some string of 500K data.
Intent intent = new Intent(MainActivity.this, PageWebView.class);
//this is workaround - I just set static variable and then access it from another    activity.
MainActivity.htmlBody = timelineDb.getHTMLBodyForTweet(tweet);
//This line was present and it actually failed with the same exception you had.
//intent.putExtra("com.gladimdim.offtie.webview", html);

我也面临着这个问题的位图数据从一个活动传递到另一个，但我通过使我的数据作为静态数据的解决方案，这对我来说是完美的工作

在活动中首先:

public static Bitmap bitmap_image;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_first);
   bitmap_image=mybitmap;
}

在第二个活动中:

 @Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_second);
   Bitmap mybitmap=first.bitmap_image;
}

对我来说，TransactionTooLargeException发生时，我试图发送大位图图像从一个活动到另一个通过意图。我通过使用应用程序的全局变量解决了这个问题。

例如，如果你想从活动A发送一个大的位图图像到活动B，那么将这个位图图像存储在全局变量中

((Global) this.getApplication()).setBitmap(bitmap);

然后启动活动B并从全局变量中读取

Bitmap bitmap = ((Global) this.getApplication()).getBitmap();