我有一个React组件，在组件的渲染方法中，我有这样的东西:
render() {
return (
<div>
<div>
// removed for brevity
</div>
{ switch(...) {} }
<div>
// removed for brevity
</div>
</div>
);
}
Now the point is that I have two div elements, one at the top and one at the bottom, that are fixed. In the middle I want to have a switch statement, and according to a value in my state I want to render a different component. So basically, I want the two div elements to be fixed always, and just in the middle to render a different component each time. I'm using this to implement a multi-step payment procedure). Though, as is the code currently it doesn't work, as it gives me an error saying that switch is unexpected. Any ideas how to achieve what I want?
你不能在渲染中有开关。放置访问一个元素的对象文字的伪切换方法并不理想，因为它会导致所有视图都要处理，并且可能导致在该状态下不存在的道具的依赖错误。
这里有一个很好的干净的方法来做到这一点，不需要每个视图提前渲染:
render () {
const viewState = this.getViewState();
return (
<div>
{viewState === ViewState.NO_RESULTS && this.renderNoResults()}
{viewState === ViewState.LIST_RESULTS && this.renderResults()}
{viewState === ViewState.SUCCESS_DONE && this.renderCompleted()}
</div>
)
如果视图状态的条件不只基于一个简单的属性——比如每行有多个条件，那么枚举和getViewState函数封装条件是分离条件逻辑和清理呈现的好方法。
我正在使用这个帮助器，它允许我在JSX中有开关语句
// in helpers folder
const switchTrue = (object) => {
const { default: defaultValue, ...rest } = object;
const obj = { default: defaultValue, ...rest };
const result = Object.keys(obj).reduce((acc, cur) => {
return {
...acc,
[cur === 'default' ? 'true' : cur]: obj[cur],
};
}, {});
return result['true'];
};
const Sample = () => {
const isDataLoading = false;
return (
<div>
{
switchTrue({
[`${isDataLoading}`]: <div>Loading</div>,
[`${!isDataLoading}`]: <div>Data Ready</div>,
default: <div>Default</div>,
})
}
</div>
)
}
ReactDOM.render(
<Sample/>,
document.getElementById("react")
);
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/16.6.3/umd/react.production.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react-dom/16.6.3/umd/react-dom.production.min.js"></script>
<div id="react"></div>
尽管这是另一种方法，但如果您已经完全使用了钩子，则可以利用useCallback来生成一个只在必要时重新创建的函数。
假设你有一个组件，它应该根据状态道具来呈现。使用钩子，你可以这样实现:
const MyComponent = ({ status }) => {
const renderContent = React.useCallback(() => {
switch(status) {
case 'CONNECTING':
return <p className="connecting">Connecting...</p>;
case 'CONNECTED':
return <p className="success">Connected Successfully!</p>
default:
return null;
}
}, [status]);
return (
<div className="container">
{renderContent()}
</div>
);
};
我喜欢这个是因为:
It's obvious what is going on - a function is created, and then later called (the immediately invoked anonymous function method looks a little odd, and can potentially confuse newer developers)
The useCallback hook ensures that the renderContent callback is reused between renders, unless the depedency status changes
The renderContent function uses a closure to access the necessary props passed in to the component. A separate function (like the accepted answer) requires the passing of the props into it, which can be burdensome (especially when using TypeScript, as the parameters should also be typed correctly)
