是否有可能找到给定包中的所有类或接口?(快速看了一下e.g. Package,似乎没有。)
当前回答
基于@Staale的回答,为了不依赖第三方库,我将通过检查第一个包的物理位置来实现文件系统方法:
import java.io.File;
import java.io.FileFilter;
import java.util.ArrayList;
...
Class<?>[] foundClasses = new Class<?>[0];
final ArrayList<Class<?>> foundClassesDyn = new ArrayList<Class<?>>();
new java.io.File(
klass.getResource(
"/" + curPackage.replace( "." , "/")
).getFile()
).listFiles(
new java.io.FileFilter() {
public boolean accept(java.io.File file) {
final String classExtension = ".class";
if ( file.isFile()
&& file.getName().endsWith(classExtension)
// avoid inner classes
&& ! file.getName().contains("$") )
{
try {
String className = file.getName();
className = className.substring(0, className.length() - classExtension.length());
foundClassesDyn.add( Class.forName( curPackage + "." + className ) );
} catch (ClassNotFoundException e) {
e.printStackTrace(System.out);
}
}
return false;
}
}
);
foundClasses = foundClassesDyn.toArray(foundClasses);
其他回答
几乎所有的答案要么使用reflection,要么从文件系统读取类文件。如果尝试从文件系统读取类,则在将应用程序打包为JAR或其他格式时可能会出错。此外,您可能不想为此目的使用单独的库。
这里有另一种方法,它是纯java,不依赖于文件系统。
import javax.tools.JavaFileObject;
import javax.tools.StandardJavaFileManager;
import javax.tools.StandardLocation;
import javax.tools.ToolProvider;
import java.io.File;
import java.util.ArrayList;
import java.util.Collection;
import java.util.Collections;
import java.util.regex.Pattern;
import java.util.stream.Collectors;
import java.util.stream.StreamSupport;
public class PackageUtil {
public static Collection<Class> getClasses(final String pack) throws Exception {
final StandardJavaFileManager fileManager = ToolProvider.getSystemJavaCompiler().getStandardFileManager(null, null, null);
return StreamSupport.stream(fileManager.list(StandardLocation.CLASS_PATH, pack, Collections.singleton(JavaFileObject.Kind.CLASS), false).spliterator(), false)
.map(javaFileObject -> {
try {
final String[] split = javaFileObject.getName()
.replace(".class", "")
.replace(")", "")
.split(Pattern.quote(File.separator));
final String fullClassName = pack + "." + split[split.length - 1];
return Class.forName(fullClassName);
} catch (ClassNotFoundException e) {
throw new RuntimeException(e);
}
})
.collect(Collectors.toCollection(ArrayList::new));
}
}
Java 8不是必须的。你可以使用for循环代替流。 你可以这样测试
public static void main(String[] args) throws Exception {
final String pack = "java.nio.file"; // Or any other package
PackageUtil.getClasses(pack).stream().forEach(System.out::println);
}
基于@Staale的回答,为了不依赖第三方库,我将通过检查第一个包的物理位置来实现文件系统方法:
import java.io.File;
import java.io.FileFilter;
import java.util.ArrayList;
...
Class<?>[] foundClasses = new Class<?>[0];
final ArrayList<Class<?>> foundClassesDyn = new ArrayList<Class<?>>();
new java.io.File(
klass.getResource(
"/" + curPackage.replace( "." , "/")
).getFile()
).listFiles(
new java.io.FileFilter() {
public boolean accept(java.io.File file) {
final String classExtension = ".class";
if ( file.isFile()
&& file.getName().endsWith(classExtension)
// avoid inner classes
&& ! file.getName().contains("$") )
{
try {
String className = file.getName();
className = className.substring(0, className.length() - classExtension.length());
foundClassesDyn.add( Class.forName( curPackage + "." + className ) );
} catch (ClassNotFoundException e) {
e.printStackTrace(System.out);
}
}
return false;
}
}
);
foundClasses = foundClassesDyn.toArray(foundClasses);
我无法为如此简单的东西找到一个简短的工作片段。所以在这里,我自己做了一段时间后:
Reflections reflections =
new Reflections(new ConfigurationBuilder()
.filterInputsBy(new FilterBuilder().includePackage(packagePath))
.setUrls(ClasspathHelper.forPackage(packagePath))
.setScanners(new SubTypesScanner(false)));
Set<String> typeList = reflections.getAllTypes();
它使用组织反射。
我是这样做的。我扫描所有的子文件夹(子包),我不尝试加载匿名类:
/**
* Attempts to list all the classes in the specified package as determined
* by the context class loader, recursively, avoiding anonymous classes
*
* @param pckgname
* the package name to search
* @return a list of classes that exist within that package
* @throws ClassNotFoundException
* if something went wrong
*/
private static List<Class> getClassesForPackage(String pckgname) throws ClassNotFoundException {
// This will hold a list of directories matching the pckgname. There may be more than one if a package is split over multiple jars/paths
ArrayList<File> directories = new ArrayList<File>();
String packageToPath = pckgname.replace('.', '/');
try {
ClassLoader cld = Thread.currentThread().getContextClassLoader();
if (cld == null) {
throw new ClassNotFoundException("Can't get class loader.");
}
// Ask for all resources for the packageToPath
Enumeration<URL> resources = cld.getResources(packageToPath);
while (resources.hasMoreElements()) {
directories.add(new File(URLDecoder.decode(resources.nextElement().getPath(), "UTF-8")));
}
} catch (NullPointerException x) {
throw new ClassNotFoundException(pckgname + " does not appear to be a valid package (Null pointer exception)");
} catch (UnsupportedEncodingException encex) {
throw new ClassNotFoundException(pckgname + " does not appear to be a valid package (Unsupported encoding)");
} catch (IOException ioex) {
throw new ClassNotFoundException("IOException was thrown when trying to get all resources for " + pckgname);
}
ArrayList<Class> classes = new ArrayList<Class>();
// For every directoryFile identified capture all the .class files
while (!directories.isEmpty()){
File directoryFile = directories.remove(0);
if (directoryFile.exists()) {
// Get the list of the files contained in the package
File[] files = directoryFile.listFiles();
for (File file : files) {
// we are only interested in .class files
if ((file.getName().endsWith(".class")) && (!file.getName().contains("$"))) {
// removes the .class extension
int index = directoryFile.getPath().indexOf(packageToPath);
String packagePrefix = directoryFile.getPath().substring(index).replace('/', '.');;
try {
String className = packagePrefix + '.' + file.getName().substring(0, file.getName().length() - 6);
classes.add(Class.forName(className));
} catch (NoClassDefFoundError e)
{
// do nothing. this class hasn't been found by the loader, and we don't care.
}
} else if (file.isDirectory()){ // If we got to a subdirectory
directories.add(new File(file.getPath()));
}
}
} else {
throw new ClassNotFoundException(pckgname + " (" + directoryFile.getPath() + ") does not appear to be a valid package");
}
}
return classes;
}
这是不可能的,因为包中的所有类都可能不会被加载,而你总是知道一个类的包。
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