一种方法是使用splice()从数组中删除项，然后再次使用splice()方法将删除的项插入到目标索引中。

Const array = ['a'， 'b'， 'c'， 'd'， 'e'] const newArray = moveItem(array, 3,1) //将元素从索引3移动到索引1 函数moveItem(arr, fromIndex, toIndex){ let itemRemoved = arr。splice(fromIndex, 1) //将删除的项赋值为数组 加勒比海盗。splice(toIndex, 0, itemRemoved[0]) //将itemRemoved插入目标索引 返回加勒比海盗 ｝ console.log (newArray)

let ar = ['a', 'b', 'c', 'd'];

function change( old_array, old_index , new_index ){

  return old_array.map(( item , index, array )=>{
    if( index === old_index ) return array[ new_index ];
    else if( index === new_index ) return array[ old_index ];
    else return item;
  });

}

let result = change( ar, 0, 1 );

console.log( result );

结果:

["b", "a", "c", "d"]

我使用了@Reid这个不错的答案，但是很难将一个元素从数组的末尾移动到开头(就像在循环中一样)。 例如[a, b, c的)应该成为[' c ', ' ', ' b ']通过调用.move(2、3)

我通过改变new_index >= this.length来实现这一点。

Array.prototype.move = function (old_index, new_index) {
        console.log(old_index + " " + new_index);
        while (old_index < 0) {
            old_index += this.length;
        }
        while (new_index < 0) {
            new_index += this.length;
        }
        if (new_index >= this.length) {
            new_index = new_index % this.length;
        }
        this.splice(new_index, 0, this.splice(old_index, 1)[0]);
        return this; // for testing purposes
    };

    Array.prototype.moveUp = function (value, by) {
        var index = this.indexOf(value),
            newPos = index - (by || 1);

        if (index === -1)
            throw new Error("Element not found in array");

        if (newPos < 0)
            newPos = 0;

        this.splice(index, 1);
        this.splice(newPos, 0, value);
    };

    Array.prototype.moveDown = function (value, by) {
        var index = this.indexOf(value),
            newPos = index + (by || 1);

        if (index === -1)
            throw new Error("Element not found in array");

        if (newPos >= this.length)
            newPos = this.length;

        this.splice(index, 1);
        this.splice(newPos, 0, value);
    };



    var arr = ['banana', 'curyWurst', 'pc', 'remembaHaruMembaru'];

    alert('withiout changes= '+arr[0]+' ||| '+arr[1]+' ||| '+arr[2]+' ||| '+arr[3]);
    arr.moveDown(arr[2]);


    alert('third word moved down= '+arr[0] + ' ||| ' + arr[1] + ' ||| ' + arr[2] + ' ||| ' + arr[3]);
    arr.moveUp(arr[2]);
    alert('third word moved up= '+arr[0] + ' ||| ' + arr[1] + ' ||| ' + arr[2] + ' ||| ' + arr[3]);

http://plnkr.co/edit/JaiAaO7FQcdPGPY6G337?p=preview

我的2摄氏度。易读，有效，快速，不需要创建新数组。

function move(array, from, to) {
  if( to === from ) return array;

  var target = array[from];                         
  var increment = to < from ? -1 : 1;

  for(var k = from; k != to; k += increment){
    array[k] = array[k + increment];
  }
  array[to] = target;
  return array;
}

我使用不可变性助手库解决了我的问题。

import update from 'immutability-helper';

const move = (arr: any[], from: number, to: number) => update(arr, {
  $splice: [
    [from, 1],
    [to, 0, arr[from] as string],
  ],
});

const testArray = ['a', 'b', 'c', 'd', 'e'];
console.log(move(testArray, 1, 3)); // [ 'c', 'b', 'c', 'd', 'e' ]
console.log(move(testArray, 4, 0)); // [ 'e', 'b', 'c', 'd', 'a' ]