从@Reid得到这个想法，在应该被移动的项目的地方推动一些东西，以保持数组大小不变。这确实简化了计算。此外，推入空对象还有一个额外的好处，就是以后能够惟一地搜索它。这是因为两个对象在引用同一个对象之前是不相等的。

({}) == ({}); // false

这个函数接收源数组，以及源和目标索引。你可以把它添加到数组中。原型(如果需要的话)。

function moveObjectAtIndex(array, sourceIndex, destIndex) {
    var placeholder = {};
    // remove the object from its initial position and
    // plant the placeholder object in its place to
    // keep the array length constant
    var objectToMove = array.splice(sourceIndex, 1, placeholder)[0];
    // place the object in the desired position
    array.splice(destIndex, 0, objectToMove);
    // take out the temporary object
    array.splice(array.indexOf(placeholder), 1);
}

面向对象，可表达，可调试，无突变，已测试。

class Sorter {
    sortItem(array, fromIndex, toIndex) {
        const reduceItems = () => {
            const startingItems = array.slice(0, fromIndex);
            const endingItems = array.slice(fromIndex + 1);
            return startingItems.concat(endingItems);
        }
        const addMovingItem = (movingItem, reducedItems) => {
            const startingNewItems = reducedItems.slice(0, toIndex);
            const endingNewItems = reducedItems.slice(toIndex);
            const newItems = startingNewItems.concat([movingItem]).concat(endingNewItems);
            return newItems;
        }
        const movingItem = array[fromIndex];
        const reducedItems = reduceItems();
        const newItems = addMovingItem(movingItem, reducedItems);
        return newItems;
    }
}

const sorter = new Sorter();
export default sorter;

import sorter from 'src/common/Sorter';

test('sortItem first item forward', () => {
    const startingArray = ['a', 'b', 'c', 'd'];
    const expectedArray = ['b', 'a', 'c', 'd'];
    expect(sorter.sortItem(startingArray, 0, 1)).toStrictEqual(expectedArray);
});
test('sortItem middle item forward', () => {
    const startingArray = ['a', 'b', 'c', 'd'];
    const expectedArray = ['a', 'c', 'b', 'd'];
    expect(sorter.sortItem(startingArray, 1, 2)).toStrictEqual(expectedArray);
});
test('sortItem middle item backward', () => {
    const startingArray = ['a', 'b', 'c', 'd'];
    const expectedArray = ['a', 'c', 'b', 'd'];
    expect(sorter.sortItem(startingArray, 2, 1)).toStrictEqual(expectedArray);
});
test('sortItem last item backward', () => {
    const startingArray = ['a', 'b', 'c', 'd'];
    const expectedArray = ['a', 'b', 'd', 'c'];
    expect(sorter.sortItem(startingArray, 3, 2)).toStrictEqual(expectedArray);
});

该方法将保留原始数组，并检查边界错误。

const move = (from, to, arr) => {
    to = Math.max(to,0)
    from > to 
        ? [].concat(
            arr.slice(0,to), 
            arr[from], 
            arr.filter((x,i) => i != from).slice(to)) 
        : to > from
            ? [].concat(
                arr.slice(0, from), 
                arr.slice(from + 1, to + 1), 
                arr[from], 
                arr.slice(to + 1))
            : arr}

我以为这是个交换问题，但其实不是。下面是我的一句话解决方案:

const move = (arr, from, to) => arr.map((item, i) => i === to ? arr[from] : (i >= Math.min(from, to) && i <= Math.max(from, to) ? arr[i + Math.sign(to - from)] : item));

下面是一个小测试:

let test = ['a', 'b', 'c', 'd', 'e'];
console.log(move(test, 0, 2)); // [ 'b', 'c', 'a', 'd', 'e' ]
console.log(move(test, 1, 3)); // [ 'a', 'c', 'd', 'b', 'e' ]
console.log(move(test, 2, 4)); // [ 'a', 'b', 'd', 'e', 'c' ]
console.log(move(test, 2, 0)); // [ 'c', 'a', 'b', 'd', 'e' ]
console.log(move(test, 3, 1)); // [ 'a', 'd', 'b', 'c', 'e' ]
console.log(move(test, 4, 2)); // [ 'a', 'b', 'e', 'c', 'd' ]
console.log(move(test, 4, 0)); // [ 'e', 'a', 'b', 'c', 'd' ]

我使用了@Reid这个不错的答案，但是很难将一个元素从数组的末尾移动到开头(就像在循环中一样)。 例如[a, b, c的)应该成为[' c ', ' ', ' b ']通过调用.move(2、3)

我通过改变new_index >= this.length来实现这一点。

Array.prototype.move = function (old_index, new_index) {
        console.log(old_index + " " + new_index);
        while (old_index < 0) {
            old_index += this.length;
        }
        while (new_index < 0) {
            new_index += this.length;
        }
        if (new_index >= this.length) {
            new_index = new_index % this.length;
        }
        this.splice(new_index, 0, this.splice(old_index, 1)[0]);
        return this; // for testing purposes
    };

如果对象是嵌套的:

  let array = ['a', 'b', 'c', 'd', 'e'];
  let existingElement = JSON.parse(JSON.stringify(array[3]));
  array.splice(1, 0, existingElement);
  array.splice(4, 1);
  console.log(array)