如果有两个变量:
Object obj;
String methodName = "getName";
在不知道obj的类的情况下,我如何调用由methodName识别的方法?
被调用的方法没有参数,只有一个String返回值。它是Java bean的getter。
如果有两个变量:
Object obj;
String methodName = "getName";
在不知道obj的类的情况下,我如何调用由methodName识别的方法?
被调用的方法没有参数,只有一个String返回值。它是Java bean的getter。
从反射使用方法调用:
Class<?> c = Class.forName("class name");
Method method = c.getDeclaredMethod("method name", parameterTypes);
method.invoke(objectToInvokeOn, params);
地点:
“class name”是类的名称 objectToInvokeOn类型为Object,是您希望在其上调用方法的对象 "method name"是你想要调用的方法的名称 parameterTypes的类型是Class[],声明方法所接受的参数 params类型为Object[],声明要传递给方法的参数
这听起来像是Java Reflection包可以做到的事情。
http://java.sun.com/developer/technicalArticles/ALT/Reflection/index.html
特别是在按名称调用方法下面:
进口数组;*;
public class method2 {
public int add(int a, int b)
{
return a + b;
}
public static void main(String args[])
{
try {
Class cls = Class.forName("method2");
Class partypes[] = new Class[2];
partypes[0] = Integer.TYPE;
partypes[1] = Integer.TYPE;
Method meth = cls.getMethod(
"add", partypes);
method2 methobj = new method2();
Object arglist[] = new Object[2];
arglist[0] = new Integer(37);
arglist[1] = new Integer(47);
Object retobj
= meth.invoke(methobj, arglist);
Integer retval = (Integer)retobj;
System.out.println(retval.intValue());
}
catch (Throwable e) {
System.err.println(e);
}
}
}
Object obj;
Method method = obj.getClass().getMethod("methodName", null);
method.invoke(obj, null);
从通俗的角度来说,它应该是这样的:
java.lang.reflect.Method method;
try {
method = obj.getClass().getMethod(methodName, param1.class, param2.class, ..);
} catch (SecurityException e) { ... }
catch (NoSuchMethodException e) { ... }
参数确定你需要的非常具体的方法(如果有几个重载可用,如果方法没有参数,只给出methodName)。
然后通过调用调用该方法
try {
method.invoke(obj, arg1, arg2,...);
} catch (IllegalArgumentException e) { ... }
catch (IllegalAccessException e) { ... }
catch (InvocationTargetException e) { ... }
同样,如果没有.invoke中的参数,请省略。但是是的。阅读Java反射
可以像这样调用该方法。还有更多的可能性(检查反射api),但这是最简单的一个:
import java.lang.reflect.InvocationTargetException;
import java.lang.reflect.Method;
import org.junit.Assert;
import org.junit.Test;
public class ReflectionTest {
private String methodName = "length";
private String valueObject = "Some object";
@Test
public void testGetMethod() throws SecurityException, NoSuchMethodException, IllegalArgumentException,
IllegalAccessException, InvocationTargetException {
Method m = valueObject.getClass().getMethod(methodName, new Class[] {});
Object ret = m.invoke(valueObject, new Object[] {});
Assert.assertEquals(11, ret);
}
}
为了完成我同事的回答,你可能需要密切关注以下问题:
static or instance calls (in one case, you do not need an instance of the class, in the other, you might need to rely on an existing default constructor that may or may not be there) public or non-public method call (for the latter,you need to call setAccessible on the method within an doPrivileged block, other findbugs won't be happy) encapsulating into one more manageable applicative exception if you want to throw back the numerous java system exceptions (hence the CCException in the code below)
下面是一个旧的java1.4代码,它考虑了这些要点:
/**
* Allow for instance call, avoiding certain class circular dependencies. <br />
* Calls even private method if java Security allows it.
* @param aninstance instance on which method is invoked (if null, static call)
* @param classname name of the class containing the method
* (can be null - ignored, actually - if instance if provided, must be provided if static call)
* @param amethodname name of the method to invoke
* @param parameterTypes array of Classes
* @param parameters array of Object
* @return resulting Object
* @throws CCException if any problem
*/
public static Object reflectionCall(final Object aninstance, final String classname, final String amethodname, final Class[] parameterTypes, final Object[] parameters) throws CCException
{
Object res;// = null;
try {
Class aclass;// = null;
if(aninstance == null)
{
aclass = Class.forName(classname);
}
else
{
aclass = aninstance.getClass();
}
//Class[] parameterTypes = new Class[]{String[].class};
final Method amethod = aclass.getDeclaredMethod(amethodname, parameterTypes);
AccessController.doPrivileged(new PrivilegedAction() {
public Object run() {
amethod.setAccessible(true);
return null; // nothing to return
}
});
res = amethod.invoke(aninstance, parameters);
} catch (final ClassNotFoundException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+CLASS, e);
} catch (final SecurityException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+GenericConstants.HASH_DIESE+ amethodname + METHOD_SECURITY_ISSUE, e);
} catch (final NoSuchMethodException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+GenericConstants.HASH_DIESE+ amethodname + METHOD_NOT_FOUND, e);
} catch (final IllegalArgumentException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+GenericConstants.HASH_DIESE+ amethodname + METHOD_ILLEGAL_ARGUMENTS+String.valueOf(parameters)+GenericConstants.CLOSING_ROUND_BRACKET, e);
} catch (final IllegalAccessException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+GenericConstants.HASH_DIESE+ amethodname + METHOD_ACCESS_RESTRICTION, e);
} catch (final InvocationTargetException e) {
throw new CCException.Error(PROBLEM_TO_ACCESS+classname+GenericConstants.HASH_DIESE+ amethodname + METHOD_INVOCATION_ISSUE, e);
}
return res;
}
首先,不要。避免使用这类代码。它往往是非常糟糕的代码,也不安全(请参阅安全编码指南的第6节) Java编程语言,版本2.0)。
如果你必须这样做,你更喜欢java。豆子要反射。Beans包装反射,允许相对安全和常规的访问。
对我来说,一个非常简单和愚蠢的方法是简单地创建一个方法调用者,就像这样:
public static object methodCaller(String methodName)
{
if(methodName.equals("getName"))
return className.getName();
}
然后当你需要调用这个方法时,简单地输入如下内容
//calling a toString method is unnessary here, but i use it to have my programs to both rigid and self-explanitory
System.out.println(methodCaller(methodName).toString());
//Step1 - Using string funClass to convert to class
String funClass = "package.myclass";
Class c = Class.forName(funClass);
//Step2 - instantiate an object of the class abov
Object o = c.newInstance();
//Prepare array of the arguments that your function accepts, lets say only one string here
Class[] paramTypes = new Class[1];
paramTypes[0]=String.class;
String methodName = "mymethod";
//Instantiate an object of type method that returns you method name
Method m = c.getDeclaredMethod(methodName, paramTypes);
//invoke method with actual params
m.invoke(o, "testparam");
对于那些想要Java 7中简单的代码示例的人:
狗类:
package com.mypackage.bean;
public class Dog {
private String name;
private int age;
public Dog() {
// empty constructor
}
public Dog(String name, int age) {
this.name = name;
this.age = age;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public void printDog(String name, int age) {
System.out.println(name + " is " + age + " year(s) old.");
}
}
ReflectionDemo类:
package com.mypackage.demo;
import java.lang.reflect.*;
public class ReflectionDemo {
public static void main(String[] args) throws Exception {
String dogClassName = "com.mypackage.bean.Dog";
Class<?> dogClass = Class.forName(dogClassName); // convert string classname to class
Object dog = dogClass.newInstance(); // invoke empty constructor
String methodName = "";
// with single parameter, return void
methodName = "setName";
Method setNameMethod = dog.getClass().getMethod(methodName, String.class);
setNameMethod.invoke(dog, "Mishka"); // pass arg
// without parameters, return string
methodName = "getName";
Method getNameMethod = dog.getClass().getMethod(methodName);
String name = (String) getNameMethod.invoke(dog); // explicit cast
// with multiple parameters
methodName = "printDog";
Class<?>[] paramTypes = {String.class, int.class};
Method printDogMethod = dog.getClass().getMethod(methodName, paramTypes);
printDogMethod.invoke(dog, name, 3); // pass args
}
}
输出: 米什卡3岁了。
你可以用这种方法调用带形参的构造函数:
Constructor<?> dogConstructor = dogClass.getConstructor(String.class, int.class);
Object dog = dogConstructor.newInstance("Hachiko", 10);
或者,您可以删除
String dogClassName = "com.mypackage.bean.Dog";
Class<?> dogClass = Class.forName(dogClassName);
Object dog = dogClass.newInstance();
,做
Dog dog = new Dog();
Method method = Dog.class.getMethod(methodName, ...);
method.invoke(dog, ...);
推荐阅读:创建新类实例
您应该使用reflection - init一个类对象,然后是该类中的一个方法,然后在具有可选参数的对象上调用此方法。记住将下面的代码段封装在try-catch块中
希望能有所帮助!
Class<?> aClass = Class.forName(FULLY_QUALIFIED_CLASS_NAME);
Method method = aClass.getMethod(methodName, YOUR_PARAM_1.class, YOUR_PARAM_2.class);
method.invoke(OBJECT_TO_RUN_METHOD_ON, YOUR_PARAM_1, YOUR_PARAM_2);
这对我来说很有效:
public class MethodInvokerClass {
public static void main(String[] args) throws NoSuchMethodException, SecurityException, IllegalAccessException, IllegalArgumentException, ClassNotFoundException, InvocationTargetException, InstantiationException {
Class c = Class.forName(MethodInvokerClass.class.getName());
Object o = c.newInstance();
Class[] paramTypes = new Class[1];
paramTypes[0]=String.class;
String methodName = "countWord";
Method m = c.getDeclaredMethod(methodName, paramTypes);
m.invoke(o, "testparam");
}
public void countWord(String input){
System.out.println("My input "+input);
}
}
输出:
我的输入testparam
我可以通过将其名称传递给另一个方法(如main)来调用该方法。
请参考以下代码,可能对您有帮助。
public static Method method[];
public static MethodClass obj;
public static String testMethod="A";
public static void main(String args[])
{
obj=new MethodClass();
method=obj.getClass().getMethods();
try
{
for(int i=0;i<method.length;i++)
{
String name=method[i].getName();
if(name==testMethod)
{
method[i].invoke(name,"Test Parameters of A");
}
}
}
catch(Exception ex)
{
System.out.println(ex.getMessage());
}
}
谢谢……
try {
YourClass yourClass = new YourClass();
Method method = YourClass.class.getMethod("yourMethodName", ParameterOfThisMethod.class);
method.invoke(yourClass, parameter);
} catch (Exception e) {
e.printStackTrace();
}
使用import java.lang.reflect.*;
public static Object launchProcess(String className, String methodName, Class<?>[] argsTypes, Object[] methodArgs)
throws Exception {
Class<?> processClass = Class.forName(className); // convert string classname to class
Object process = processClass.newInstance(); // invoke empty constructor
Method aMethod = process.getClass().getMethod(methodName,argsTypes);
Object res = aMethod.invoke(process, methodArgs); // pass arg
return(res);
}
下面是你如何使用它:
String className = "com.example.helloworld";
String methodName = "print";
Class<?>[] argsTypes = {String.class, String.class};
Object[] methArgs = { "hello", "world" };
launchProcess(className, methodName, argsTypes, methArgs);
Method method = someVariable.class.getMethod(SomeClass);
String status = (String) method.invoke(method);
SomeClass是类,somvariable是变量。
如果多次调用,则可以使用Java 7中引入的新方法句柄。现在我们开始你的方法返回一个字符串:
Object obj = new Point( 100, 200 );
String methodName = "toString";
Class<String> resultType = String.class;
MethodType mt = MethodType.methodType( resultType );
MethodHandle methodHandle = MethodHandles.lookup().findVirtual( obj.getClass(), methodName, mt );
String result = resultType.cast( methodHandle.invoke( obj ) );
System.out.println( result ); // java.awt.Point[x=100,y=200]
Student.java
class Student{
int rollno;
String name;
void m1(int x,int y){
System.out.println("add is" +(x+y));
}
private void m3(String name){
this.name=name;
System.out.println("danger yappa:"+name);
}
void m4(){
System.out.println("This is m4");
}
}
StudentTest.java
import java.lang.reflect.Method;
public class StudentTest{
public static void main(String[] args){
try{
Class cls=Student.class;
Student s=(Student)cls.newInstance();
String x="kichha";
Method mm3=cls.getDeclaredMethod("m3",String.class);
mm3.setAccessible(true);
mm3.invoke(s,x);
Method mm1=cls.getDeclaredMethod("m1",int.class,int.class);
mm1.invoke(s,10,20);
}
catch(Exception e){
e.printStackTrace();
}
}
}
这里是准备使用的方法:
调用一个不带参数的方法:
public static void callMethodByName(Object object, String methodName) throws IllegalAccessException, InvocationTargetException, NoSuchMethodException {
object.getClass().getDeclaredMethod(methodName).invoke(object);
}
使用Arguments调用一个方法:
public static void callMethodByName(Object object, String methodName, int i, String s) throws IllegalAccessException, InvocationTargetException, NoSuchMethodException {
object.getClass().getDeclaredMethod(methodName, int.class, String.class).invoke(object, i, s);
}
使用上述方法如下:
package practice;
import java.io.IOException;
import java.lang.reflect.InvocationTargetException;
public class MethodInvoke {
public static void main(String[] args) throws ClassNotFoundException, NoSuchMethodException, SecurityException, IllegalAccessException, IllegalArgumentException, InvocationTargetException, IOException {
String methodName1 = "methodA";
String methodName2 = "methodB";
MethodInvoke object = new MethodInvoke();
callMethodByName(object, methodName1);
callMethodByName(object, methodName2, 1, "Test");
}
public static void callMethodByName(Object object, String methodName) throws IllegalAccessException, InvocationTargetException, NoSuchMethodException {
object.getClass().getDeclaredMethod(methodName).invoke(object);
}
public static void callMethodByName(Object object, String methodName, int i, String s) throws IllegalAccessException, InvocationTargetException, NoSuchMethodException {
object.getClass().getDeclaredMethod(methodName, int.class, String.class).invoke(object, i, s);
}
void methodA() {
System.out.println("Method A");
}
void methodB(int i, String s) {
System.out.println("Method B: "+"\n\tParam1 - "+i+"\n\tParam 2 - "+s);
}
}
输出:
Method A Method B: Param1 - 1 Param 2 - Test
索引(快)
您可以使用FunctionalInterface将方法保存在容器中以索引它们。您可以使用数组容器通过数字调用它们,或者使用hashmap通过字符串调用它们。通过这个技巧,可以为方法建立索引,从而更快地动态调用它们。
@FunctionalInterface
public interface Method {
double execute(int number);
}
public class ShapeArea {
private final static double PI = 3.14;
private Method[] methods = {
this::square,
this::circle
};
private double square(int number) {
return number * number;
}
private double circle(int number) {
return PI * number * number;
}
public double run(int methodIndex, int number) {
return methods[methodIndex].execute(number);
}
}
λ语法
你也可以使用lambda语法:
public class ShapeArea {
private final static double PI = 3.14;
private Method[] methods = {
number -> {
return number * number;
},
number -> {
return PI * number * number;
},
};
public double run(int methodIndex, int number) {
return methods[methodIndex].execute(number);
}
}
编辑2022
刚才我在想为你提供一个通用的解决方案,与所有可能的方法与变量数:
@FunctionalInterface
public interface Method {
Object execute(Object ...args);
}
public class Methods {
private Method[] methods = {
this::square,
this::rectangle
};
private double square(int number) {
return number * number;
}
private double rectangle(int width, int height) {
return width * height;
}
public Method run(int methodIndex) {
return methods[methodIndex];
}
}
用法:
methods.run(1).execute(width, height);
对于jooR,它仅仅是:
on(obj).call(methodName /*params*/).get()
这里有一个更详细的例子:
public class TestClass {
public int add(int a, int b) { return a + b; }
private int mul(int a, int b) { return a * b; }
static int sub(int a, int b) { return a - b; }
}
import static org.joor.Reflect.*;
public class JoorTest {
public static void main(String[] args) {
int add = on(new TestClass()).call("add", 1, 2).get(); // public
int mul = on(new TestClass()).call("mul", 3, 4).get(); // private
int sub = on(TestClass.class).call("sub", 6, 5).get(); // static
System.out.println(add + ", " + mul + ", " + sub);
}
}
这个打印:
3, 12, 1
对于那些在同一个类中调用非静态方法的方法,请参见下面的代码:
class Person {
public void method1() {
try {
Method m2 = this.getClass().getDeclaredMethod("method2");
m1.invoke(this);
} catch (NoSuchMethodException e) {
e.printStackTrace();
} catch (IllegalAccessException e) {
e.printStackTrace();
} catch (InvocationTargetException e) {
e.printStackTrace();
}
}
public void method2() {
// Do something
}
}
假设您从同一个类中的一个静态方法调用一个静态方法。为此,您可以对以下代码进行示例。
class MainClass
{
public static int foo()
{
return 123;
}
public static void main(String[] args)
{
Method method = MainClass.class.getMethod("foo");
int result = (int) method.invoke(null); // answer evaluates to 123
}
}
为了解释一下,因为我们在这里不打算执行真正的面向对象编程,因此避免创建不必要的对象,所以我们将利用class属性来调用getMethod()。
然后,我们将为invoke()方法传入null,因为我们没有对象来执行此操作。
最后,因为我们程序员,知道我们期待的是一个整数,那么 我们显式地将invoke()调用的返回值转换为一个整数。
现在您可能想知道:“用Java进行所有这些非面向对象的编程到底有什么意义?”
我的用例是用Java解决Project Euler问题。我有一个包含所有解决方案的Java源文件,我想传入命令行参数,以确定要运行哪个Project Euler问题。