如果有两个变量:
Object obj;
String methodName = "getName";
在不知道obj的类的情况下,我如何调用由methodName识别的方法?
被调用的方法没有参数,只有一个String返回值。它是Java bean的getter。
如果有两个变量:
Object obj;
String methodName = "getName";
在不知道obj的类的情况下,我如何调用由methodName识别的方法?
被调用的方法没有参数,只有一个String返回值。它是Java bean的getter。
当前回答
这里是准备使用的方法:
调用一个不带参数的方法:
public static void callMethodByName(Object object, String methodName) throws IllegalAccessException, InvocationTargetException, NoSuchMethodException {
object.getClass().getDeclaredMethod(methodName).invoke(object);
}
使用Arguments调用一个方法:
public static void callMethodByName(Object object, String methodName, int i, String s) throws IllegalAccessException, InvocationTargetException, NoSuchMethodException {
object.getClass().getDeclaredMethod(methodName, int.class, String.class).invoke(object, i, s);
}
使用上述方法如下:
package practice;
import java.io.IOException;
import java.lang.reflect.InvocationTargetException;
public class MethodInvoke {
public static void main(String[] args) throws ClassNotFoundException, NoSuchMethodException, SecurityException, IllegalAccessException, IllegalArgumentException, InvocationTargetException, IOException {
String methodName1 = "methodA";
String methodName2 = "methodB";
MethodInvoke object = new MethodInvoke();
callMethodByName(object, methodName1);
callMethodByName(object, methodName2, 1, "Test");
}
public static void callMethodByName(Object object, String methodName) throws IllegalAccessException, InvocationTargetException, NoSuchMethodException {
object.getClass().getDeclaredMethod(methodName).invoke(object);
}
public static void callMethodByName(Object object, String methodName, int i, String s) throws IllegalAccessException, InvocationTargetException, NoSuchMethodException {
object.getClass().getDeclaredMethod(methodName, int.class, String.class).invoke(object, i, s);
}
void methodA() {
System.out.println("Method A");
}
void methodB(int i, String s) {
System.out.println("Method B: "+"\n\tParam1 - "+i+"\n\tParam 2 - "+s);
}
}
输出:
Method A Method B: Param1 - 1 Param 2 - Test
其他回答
//Step1 - Using string funClass to convert to class
String funClass = "package.myclass";
Class c = Class.forName(funClass);
//Step2 - instantiate an object of the class abov
Object o = c.newInstance();
//Prepare array of the arguments that your function accepts, lets say only one string here
Class[] paramTypes = new Class[1];
paramTypes[0]=String.class;
String methodName = "mymethod";
//Instantiate an object of type method that returns you method name
Method m = c.getDeclaredMethod(methodName, paramTypes);
//invoke method with actual params
m.invoke(o, "testparam");
从通俗的角度来说,它应该是这样的:
java.lang.reflect.Method method;
try {
method = obj.getClass().getMethod(methodName, param1.class, param2.class, ..);
} catch (SecurityException e) { ... }
catch (NoSuchMethodException e) { ... }
参数确定你需要的非常具体的方法(如果有几个重载可用,如果方法没有参数,只给出methodName)。
然后通过调用调用该方法
try {
method.invoke(obj, arg1, arg2,...);
} catch (IllegalArgumentException e) { ... }
catch (IllegalAccessException e) { ... }
catch (InvocationTargetException e) { ... }
同样,如果没有.invoke中的参数,请省略。但是是的。阅读Java反射
使用import java.lang.reflect.*;
public static Object launchProcess(String className, String methodName, Class<?>[] argsTypes, Object[] methodArgs)
throws Exception {
Class<?> processClass = Class.forName(className); // convert string classname to class
Object process = processClass.newInstance(); // invoke empty constructor
Method aMethod = process.getClass().getMethod(methodName,argsTypes);
Object res = aMethod.invoke(process, methodArgs); // pass arg
return(res);
}
下面是你如何使用它:
String className = "com.example.helloworld";
String methodName = "print";
Class<?>[] argsTypes = {String.class, String.class};
Object[] methArgs = { "hello", "world" };
launchProcess(className, methodName, argsTypes, methArgs);
Method method = someVariable.class.getMethod(SomeClass);
String status = (String) method.invoke(method);
SomeClass是类,somvariable是变量。
Object obj;
Method method = obj.getClass().getMethod("methodName", null);
method.invoke(obj, null);