索引(快)

您可以使用FunctionalInterface将方法保存在容器中以索引它们。您可以使用数组容器通过数字调用它们，或者使用hashmap通过字符串调用它们。通过这个技巧，可以为方法建立索引，从而更快地动态调用它们。

@FunctionalInterface
public interface Method {
    double execute(int number);
}

public class ShapeArea {
    private final static double PI = 3.14;

    private Method[] methods = {
        this::square,
        this::circle
    };

    private double square(int number) {
        return number * number;
    }

    private double circle(int number) {
        return PI * number * number;
    }

    public double run(int methodIndex, int number) {
        return methods[methodIndex].execute(number);
    }
}

λ语法

你也可以使用lambda语法:

public class ShapeArea {
    private final static double PI = 3.14;

    private Method[] methods = {
        number -> {
            return number * number;
        },
        number -> {
            return PI * number * number;
        },
    };

    public double run(int methodIndex, int number) {
        return methods[methodIndex].execute(number);
    }
}

编辑2022

刚才我在想为你提供一个通用的解决方案，与所有可能的方法与变量数:

@FunctionalInterface
public interface Method {
    Object execute(Object ...args);
}

public class Methods {
    private Method[] methods = {
        this::square,
        this::rectangle
    };

    private double square(int number) {
        return number * number;
    }

    private double rectangle(int width, int height) {
        return width * height;
    }

    public Method run(int methodIndex) {
        return methods[methodIndex];
    }
}

用法:

methods.run(1).execute(width, height);

索引(快)

您可以使用FunctionalInterface将方法保存在容器中以索引它们。您可以使用数组容器通过数字调用它们，或者使用hashmap通过字符串调用它们。通过这个技巧，可以为方法建立索引，从而更快地动态调用它们。

@FunctionalInterface
public interface Method {
    double execute(int number);
}

public class ShapeArea {
    private final static double PI = 3.14;

    private Method[] methods = {
        this::square,
        this::circle
    };

    private double square(int number) {
        return number * number;
    }

    private double circle(int number) {
        return PI * number * number;
    }

    public double run(int methodIndex, int number) {
        return methods[methodIndex].execute(number);
    }
}

λ语法

你也可以使用lambda语法:

public class ShapeArea {
    private final static double PI = 3.14;

    private Method[] methods = {
        number -> {
            return number * number;
        },
        number -> {
            return PI * number * number;
        },
    };

    public double run(int methodIndex, int number) {
        return methods[methodIndex].execute(number);
    }
}

编辑2022

刚才我在想为你提供一个通用的解决方案，与所有可能的方法与变量数:

@FunctionalInterface
public interface Method {
    Object execute(Object ...args);
}

public class Methods {
    private Method[] methods = {
        this::square,
        this::rectangle
    };

    private double square(int number) {
        return number * number;
    }

    private double rectangle(int width, int height) {
        return width * height;
    }

    public Method run(int methodIndex) {
        return methods[methodIndex];
    }
}

用法:

methods.run(1).execute(width, height);

您应该使用reflection - init一个类对象，然后是该类中的一个方法，然后在具有可选参数的对象上调用此方法。记住将下面的代码段封装在try-catch块中

希望能有所帮助!

Class<?> aClass = Class.forName(FULLY_QUALIFIED_CLASS_NAME);
Method method = aClass.getMethod(methodName, YOUR_PARAM_1.class, YOUR_PARAM_2.class);
method.invoke(OBJECT_TO_RUN_METHOD_ON, YOUR_PARAM_1, YOUR_PARAM_2);

//Step1 - Using string funClass to convert to class
String funClass = "package.myclass";
Class c = Class.forName(funClass);

//Step2 - instantiate an object of the class abov
Object o = c.newInstance();
//Prepare array of the arguments that your function accepts, lets say only one string here
Class[] paramTypes = new Class[1];
paramTypes[0]=String.class;
String methodName = "mymethod";
//Instantiate an object of type method that returns you method name
 Method m = c.getDeclaredMethod(methodName, paramTypes);
//invoke method with actual params
m.invoke(o, "testparam");

这对我来说很有效:

public class MethodInvokerClass {
    public static void main(String[] args) throws NoSuchMethodException, SecurityException, IllegalAccessException, IllegalArgumentException, ClassNotFoundException, InvocationTargetException, InstantiationException {
        Class c = Class.forName(MethodInvokerClass.class.getName());
        Object o = c.newInstance();
        Class[] paramTypes = new Class[1];
        paramTypes[0]=String.class;
        String methodName = "countWord";
         Method m = c.getDeclaredMethod(methodName, paramTypes);
         m.invoke(o, "testparam");
}
public void countWord(String input){
    System.out.println("My input "+input);
}

}

输出:

我的输入testparam

我可以通过将其名称传递给另一个方法(如main)来调用该方法。

这听起来像是Java Reflection包可以做到的事情。

http://java.sun.com/developer/technicalArticles/ALT/Reflection/index.html

特别是在按名称调用方法下面:

进口数组;*;

public class method2 {
  public int add(int a, int b)
  {
     return a + b;
  }

  public static void main(String args[])
  {
     try {
       Class cls = Class.forName("method2");
       Class partypes[] = new Class[2];
        partypes[0] = Integer.TYPE;
        partypes[1] = Integer.TYPE;
        Method meth = cls.getMethod(
          "add", partypes);
        method2 methobj = new method2();
        Object arglist[] = new Object[2];
        arglist[0] = new Integer(37);
        arglist[1] = new Integer(47);
        Object retobj 
          = meth.invoke(methobj, arglist);
        Integer retval = (Integer)retobj;
        System.out.println(retval.intValue());
     }
     catch (Throwable e) {
        System.err.println(e);
     }
  }
}