你可以在你的路由类上实现routerOnActivate()方法，它会提供之前路由的信息。

routerOnActivate(nextInstruction: ComponentInstruction, prevInstruction: ComponentInstruction) : any

然后你可以使用router.navigateByUrl()并传递ComponentInstruction生成的数据。例如:

this._router.navigateByUrl(prevInstruction.urlPath);

实际上，你可以利用内置的位置服务，它拥有一个“返回”API。

这里(TypeScript中):

import {Component} from '@angular/core';
import {Location} from '@angular/common';

@Component({
  // component's declarations here
})
class SomeComponent {

  constructor(private _location: Location) 
  {}

  backClicked() {
    this._location.back();
  }
}

编辑:正如@charith所提到的。Location应该从@angular/common中导入，所以从@angular/common中导入{Location};线条很重要。

从beta 18开始:

import {Location} from 'angular /platform/common';

RC4:

import {Location} from '@angular/common';

在Angular 2的最终版本中。X / 4。x -这里是文档https://angular.io/api/common/Location

/* typescript */

import { Location } from '@angular/common';
// import stuff here

@Component({
// declare component here
})
export class MyComponent {

  // inject location into component constructor
  constructor(private location: Location) { }

  cancel() {
    this.location.back(); // <-- go back to previous location on cancel
  }
}

我这样做的方式，而导航到不同的页面添加一个查询参数通过传递当前位置

this.router.navigate(["user/edit"], { queryParams: { returnUrl: this.router.url }

读取组件中的这个查询参数

this.router.queryParams.subscribe((params) => {
    this.returnUrl = params.returnUrl;
});

如果returnUrl存在，则启用后退按钮，当用户单击后退按钮时

this.router.navigateByUrl(this.returnUrl); // Hint taken from Sasxa

这应该能够导航到前一页。而不是使用位置。我觉得上面的方法是更安全的考虑情况下，用户直接登陆到你的页面，如果他按后退按钮的位置。回到它将重定向用户到前一页，这将不是你的网页。

在angular 4中使用preserveQueryParams，例如:

url: /list?page=1

<a [routerLink]="['edit',id]" [preserveQueryParams]="true"></a>

当点击链接时，您将被重定向编辑/10?Page =1，保留参数

裁判:https://angular.io/docs/ts/latest/guide/router.html # !# link-parameters-array

也为我工作时，我需要移动回文件系统。 P.S. @angular: "^5.0.0"

<button type="button" class="btn btn-primary" routerLink="../">Back</button>

我做了一个按钮，我可以在我的应用程序的任何地方重复使用。

创建这个组件

import { Location } from '@angular/common';
import { Component, Input } from '@angular/core';

@Component({
    selector: 'back-button',
    template: `<button mat-button (click)="goBack()" [color]="color">Back</button>`,
})
export class BackButtonComponent {
    @Input()color: string;

  constructor(private location: Location) { }

  goBack() {
    this.location.back();
  }
}

然后在需要后退按钮时将其添加到任何模板中。

<back-button color="primary"></back-button>

注意:这里使用的是Angular材质，如果你不使用这个库，那么移除垫子按钮和颜色。

用Angular 5.2.9测试过

如果你使用锚而不是按钮，你必须使用href="javascript:void(0)"将其设置为被动链接，以使Angular Location正常工作。

app.component.ts

import { Component } from '@angular/core';
import { Location } from '@angular/common';

@Component({
  selector: 'app-root',
  templateUrl: './app.component.html',
  styleUrls: [ './app.component.css' ]
})
export class AppComponent {

  constructor( private location: Location ) { 
  }

  goBack() {
    // window.history.back();
    this.location.back();

    console.log( 'goBack()...' );
  }
}

app.component.html

<!-- anchor must be a passive link -->
<a href="javascript:void(0)" (click)="goBack()">
  <-Back
</a>

另一个解决方案

window.history.back ();

<按钮返回按钮>返回</button>

你可以把它放到一个指令中，这个指令可以附加到任何可点击的元素上:

import { Directive, HostListener } from '@angular/core';
import { Location } from '@angular/common';

@Directive({
    selector: '[backButton]'
})
export class BackButtonDirective {
    constructor(private location: Location) { }

    @HostListener('click')
    onClick() {
        this.location.back();
    }
}

用法:

<button backButton>BACK</button>

在这些精彩的答案之后，我希望我的答案能找到一些人，并帮助他们。我编写了一个小服务来跟踪路线历史。开始了。

import { Injectable } from '@angular/core';
import { NavigationEnd, Router } from '@angular/router';
import { filter } from 'rxjs/operators';

@Injectable()
export class RouteInterceptorService {
  private _previousUrl: string;
  private _currentUrl: string;
  private _routeHistory: string[];

  constructor(router: Router) {
    this._routeHistory = [];
    router.events
      .pipe(filter(event => event instanceof NavigationEnd))
      .subscribe((event: NavigationEnd) => {
        this._setURLs(event);
      });
  }

  private _setURLs(event: NavigationEnd): void {
    const tempUrl = this._currentUrl;
    this._previousUrl = tempUrl;
    this._currentUrl = event.urlAfterRedirects;
    this._routeHistory.push(event.urlAfterRedirects);
  }

  get previousUrl(): string {
    return this._previousUrl;
  }

  get currentUrl(): string {
    return this._currentUrl;
  }

  get routeHistory(): string[] {
    return this._routeHistory;
  }
}

要返回而不刷新页面，我们可以像下面这样在html中做 javascript: history.back ()

<a class="btn btn-danger" href="javascript:history.back()">Go Back</a>

是的，你能做到。在你的typescript组件上编写这段代码，然后享受吧!

import { Location } from '@angular/common'
import { Component, Input } from '@angular/core'

@Component({
    selector: 'return_page',
    template: `<button mat-button (click)="onReturn()">Back</button>`,
})
export class ReturnPageComponent {
  constructor(private location: Location) { }

  onReturn() {
    this.location.back();
  }
}

也许你想检查之前的历史点是否在你的应用程序中。例如，如果你直接进入你的应用程序并执行location.back()(例如，通过按下工具栏中的<- back按钮)，你会回到浏览器的主页面，而不是去应用程序中的其他地方。

这是我检查这个的方法:

import { Component } from '@angular/core';
import { ActivatedRoute, Router } from '@angular/router';
import { Location } from '@angular/common';

@Component({
  selector: 'app-foo',
  template: ''
})
export class FooComponent {

  private readonly canGoBack: boolean;

  constructor(
    private readonly route: ActivatedRoute,
    private readonly router: Router,
    private readonly location: Location
  ) {
    // This is where the check is done. Make sure to do this
    // here in the constructor, otherwise `getCurrentNavigation()`
    // will return null. 
    this.canGoBack = !!(this.router.getCurrentNavigation()?.previousNavigation);
  }

  goBack(): void {
    if (this.canGoBack) {
      // We can safely go back to the previous location as
      // we know it's within our app.
      this.location.back();
    } else {
      // There's no previous navigation.
      // Here we decide where to go. For example, let's say the
      // upper level is the index page, so we go up one level.
      this.router.navigate(['..'], {relativeTo: this.route});
    }
  }

}

我们检查加载当前路由的导航是否有前一个兄弟。这必须在导航过程仍处于活动状态时在构造函数中完成。

但也有一些注意事项:

即使之前的位置实际上在我们的应用程序中，但页面被刷新，canGoBack也将为false。 用户可能想通过点击浏览器的返回按钮“返回”到上一页(goBack()发生的地方)，但由于应用程序返回历史而不是按一个新的位置，用户将会返回得更远，可能会感到困惑。

我是这么说的:

import { Location } from '@angular/common'
import { Component, Input } from '@angular/core'

@Component({
    selector: 'Back_page',
    template: `<button  (click)="onBack()">Back</button>`,
})
export class BackPageComponent {
  constructor(private location: Location) { }

  onBack() {
    this.location.back();// <-- go back to previous location
  }
}

此外，您还可以在历史记录为空的情况下使用此服务与回退功能

url-back.service.ts

import { Injectable } from '@angular/core';
import { Location } from '@angular/common';

import { Router } from '@angular/router';

const EMPTY_HISTORY_LENGTH = 2;

/**
 * This service helps to Navigate back to the prev page, and if no prev page,
 * will redirect to the fallback url.
 */
@Injectable()
export class UrlBackService {
  constructor(private router: Router, private location: Location) {}

  /**
   * This method will back you to the previous page,
   * if no previous page exists, will redirect you to the fallback url.
   * @param href - url, if tryNativeFirst is provided, this is fallback url
   * @param tryNativeFirst - try to go back natively using browser history state.
   */
  back(href: string, tryNativeFirst: boolean = false) {
    if (tryNativeFirst) {
      if (history.length === EMPTY_HISTORY_LENGTH) {
        this.router.navigate(UrlBackService.urlToArray(href));
      } else {
        this.location.back();
      }
    } else {
      this.router.navigate(UrlBackService.urlToArray(href));
    }
  }

  /**
   * In case that router.navigate method tries to escape all '/' in the string,
   * was decided to split string to array, and if URL starts or ends with slash - remove them, eg:
   * /my/url will be split to ['', 'my', 'url'], so we need to remove empty spaces use filter function.
   * @param href
   * @private
   */
  private static urlToArray(href: string) {
    return href.split('/').filter((notEmpty) => notEmpty);
  }
}

url-back.service.spec.ts

import { TestBed } from '@angular/core/testing';

import { UrlBackService } from './url-back.service';
import { Router } from '@angular/router';
import { Location } from '@angular/common';
import { RouterTestingModule } from '@angular/router/testing';

describe('UrlBackService', () => {
  let service: UrlBackService;
  let router: Router;
  let location: Location;

  beforeEach(() => {
    TestBed.configureTestingModule({
      imports: [RouterTestingModule],
      providers: [UrlBackService],
    });
    service = TestBed.inject(UrlBackService);
    router = TestBed.inject(Router);
    location = TestBed.inject(Location);
  });

  it('should be created', () => {
    expect(service).toBeTruthy();
  });

  it('no meter what history state is, it should be redirected to the /my/url', () => {
    spyOn(router, 'navigate');
    service.back('/my/url');
    expect(router.navigate).toHaveBeenCalledWith(['my', 'url']);
  });

  it('in case history is empty push to /my/url', () => {
    spyOn(router, 'navigate');
    service.back('/my/url', true);
    expect(router.navigate).toHaveBeenCalledWith(['my', 'url']);
  });

  it('in case history is NOT empty push to url1', () => {
    spyOn(location, 'back');
    window.history.pushState(null, '', 'url1');

    service.back('/my/url', true);
    expect(location.back).toHaveBeenCalled();
  });
});

如果你使用的是最新的Angular/TypeScript，请确保你显式导入

import { Location } from '@angular/common';

and

 onCancel() {
    this.location.back();
  }

试试routerLink = " - LASTPAGE”

2022 利用你的应用程序路由-更多的是一种“角度方法”，而不是访问浏览器的位置对象来获取导航历史。 想想你为什么需要用户返回，以及“返回”在应用程序及其路由的更广泛的上下文中意味着什么。

例如，从子路由返回到父路由

  this.router.navigate(['..'], {relativeTo: this.route});

您还可以阅读以前的导航

previousNavigation:先前成功的导航对象。只有 一个先前的导航是可用的，因此这个先前的 Navigation对象的previousNavigation为空值。

这是我想出来的，你也可以查一下是否有上一页。 确保在你的appComponent中使用了这个服务。

import { Injectable } from '@angular/core';
import { Location } from '@angular/common';
import { NavigationEnd, Router } from '@angular/router';

interface HistoryData {
  previousPage: string | null,
  currentPage: string | null,
}

@Injectable({ providedIn: 'root' })
export class GoBackService {

  private historyData: HistoryData = { previousPage: null, currentPage: null };

  constructor(private router: Router, private location: Location) {
    this.router.events.subscribe((event) => {
      if (event instanceof NavigationEnd) {
        this.historyData.previousPage = this.historyData.currentPage;
        this.historyData.currentPage = event.urlAfterRedirects;
      }
    });
  }

  public goBack(): void {
    if (this.historyData.previousPage) this.location.back();
  }

  public canGoBack(): boolean {
    return Boolean(this.historyData.previousPage);
  }

}

只需使用Location，这是一个Angular服务，应用程序可以使用它与浏览器的URL进行交互。

导入:

import { Location } from '@angular/common';

注射:

constructor(private location: Location) { }

简单地使用它:

goBack() {
    this.location.back(); // Navigates back in the platform's history
}

检测到的未更改组件的@Parziphal答案版本:

  import { Location } from '@angular/common';
  import { Router } from '@angular/router';

  constructor(private readonly router: Router, private readonly location: Location) {
    location.onUrlChange(() => this.canGoBack = !!this.router.getCurrentNavigation()?.previousNavigation);
  }

  goBack(): void {
    if (this.canGoBack) {
      this.location.back();
    }
  }

进口:

import { Location } from '@angular/common';
import { Router } from '@angular/router';

构造函数:

constructor(private readonly router: Router, private readonly location: Location) {
  location.onUrlChange(() => this.canGoBack = !!this.router.getCurrentNavigation()?.previousNavigation);
}

可选，避免返回到应用程序之外:

private canGoBack: boolean = false;

constructor(private router:Router,private location:Location){
  this.canGoBack = !!(this.router.getCurrentNavigation()?.previousNavigation);
}

返回:

goBack(): void {
  if (this.canGoBack) {
    this.location.back();
  }
}

Html:

<button (click)="goBack()"></button>