检测到的未更改组件的@Parziphal答案版本:

  import { Location } from '@angular/common';
  import { Router } from '@angular/router';

  constructor(private readonly router: Router, private readonly location: Location) {
    location.onUrlChange(() => this.canGoBack = !!this.router.getCurrentNavigation()?.previousNavigation);
  }

  goBack(): void {
    if (this.canGoBack) {
      this.location.back();
    }
  }

另一个解决方案

window.history.back ();

在angular 4中使用preserveQueryParams，例如:

url: /list?page=1

<a [routerLink]="['edit',id]" [preserveQueryParams]="true"></a>

当点击链接时，您将被重定向编辑/10?Page =1，保留参数

裁判:https://angular.io/docs/ts/latest/guide/router.html # !# link-parameters-array

进口:

import { Location } from '@angular/common';
import { Router } from '@angular/router';

构造函数:

constructor(private readonly router: Router, private readonly location: Location) {
  location.onUrlChange(() => this.canGoBack = !!this.router.getCurrentNavigation()?.previousNavigation);
}

可选，避免返回到应用程序之外:

private canGoBack: boolean = false;

constructor(private router:Router,private location:Location){
  this.canGoBack = !!(this.router.getCurrentNavigation()?.previousNavigation);
}

返回:

goBack(): void {
  if (this.canGoBack) {
    this.location.back();
  }
}

Html:

<button (click)="goBack()"></button>

是的，你能做到。在你的typescript组件上编写这段代码，然后享受吧!

import { Location } from '@angular/common'
import { Component, Input } from '@angular/core'

@Component({
    selector: 'return_page',
    template: `<button mat-button (click)="onReturn()">Back</button>`,
})
export class ReturnPageComponent {
  constructor(private location: Location) { }

  onReturn() {
    this.location.back();
  }
}

RC4:

import {Location} from '@angular/common';