在c++中是否有跨平台的方法来获取当前的日期和时间?


当前回答

localtime_s()版本:

#include <stdio.h>
#include <time.h>

int main ()
{
  time_t current_time;
  struct tm  local_time;

  time ( &current_time );
  localtime_s(&local_time, &current_time);

  int Year   = local_time.tm_year + 1900;
  int Month  = local_time.tm_mon + 1;
  int Day    = local_time.tm_mday;

  int Hour   = local_time.tm_hour;
  int Min    = local_time.tm_min;
  int Sec    = local_time.tm_sec;

  return 0;
} 

其他回答

这为我在Linux (RHEL)和Windows (x64)上编译,目标是g++和OpenMP:

#include <ctime>
#include <iostream>
#include <string>
#include <locale>

////////////////////////////////////////////////////////////////////////////////
//
//  Reports a time-stamped update to the console; format is:
//       Name: Update: Year-Month-Day_of_Month Hour:Minute:Second
//
////////////////////////////////////////////////////////////////////////////////
//
//  [string] strName  :  name of the update object
//  [string] strUpdate:  update descripton
//          
////////////////////////////////////////////////////////////////////////////////

void ReportTimeStamp(string strName, string strUpdate)
{
    try
    {
        #ifdef _WIN64
            //  Current time
            const time_t tStart = time(0);
            //  Current time structure
            struct tm tmStart;

            localtime_s(&tmStart, &tStart);

            //  Report
            cout << strName << ": " << strUpdate << ": " << (1900 + tmStart.tm_year) << "-" << tmStart.tm_mon << "-" << tmStart.tm_mday << " " << tmStart.tm_hour << ":" << tmStart.tm_min << ":" << tmStart.tm_sec << "\n\n";
        #else
            //  Current time
            const time_t tStart = time(0);
            //  Current time structure
            struct tm* tmStart;

            tmStart = localtime(&tStart);

            //  Report
            cout << strName << ": " << strUpdate << ": " << (1900 + tmStart->tm_year) << "-" << tmStart->tm_mon << "-" << tmStart->tm_mday << " " << tmStart->tm_hour << ":" << tmStart->tm_min << ":" << tmStart->tm_sec << "\n\n";
        #endif

    }
    catch (exception ex)
    {
        cout << "ERROR [ReportTimeStamp] Exception Code:  " << ex.what() << "\n";
    }

    return;
}

你可以使用boost和chrono库:

#include <iostream>
#include <chrono>
#include <boost/date_time/posix_time/posix_time.hpp>

using boost::posix_time::to_iso_extended_string;
using boost::posix_time::from_time_t;
using std::chrono::system_clock;

int main()
{
  auto now = system_clock::now();
  std::cout << to_iso_extended_string(from_time_t(system_clock::to_time_t(now)));
}

我需要一种方法在每次更新列表时插入当前日期-时间。 简单地说,这似乎很有效。

#include<bits/stdc++.h>
#include<unistd.h>
using namespace std;
int main()
{   //initialize variables
    time_t now; 
    //blah..blah
    /*each time I want the updated stamp*/
    now=time(0);cout<<ctime(&now)<<"blah_blah";
}

std C库提供time()。 这是从纪元开始的秒数,可以使用标准C函数转换为日期和H:M:S。Boost还有一个时间/日期库供您检查。

time_t  timev;
time(&timev);

c++与C共享它的日期/时间函数。tm结构可能是c++程序员最容易使用的结构——下面打印今天的日期:

#include <ctime>
#include <iostream>

int main() {
    std::time_t t = std::time(0);   // get time now
    std::tm* now = std::localtime(&t);
    std::cout << (now->tm_year + 1900) << '-' 
         << (now->tm_mon + 1) << '-'
         <<  now->tm_mday
         << "\n";
}