在c++中是否有跨平台的方法来获取当前的日期和时间?
当前回答
localtime_s()版本:
#include <stdio.h>
#include <time.h>
int main ()
{
time_t current_time;
struct tm local_time;
time ( ¤t_time );
localtime_s(&local_time, ¤t_time);
int Year = local_time.tm_year + 1900;
int Month = local_time.tm_mon + 1;
int Day = local_time.tm_mday;
int Hour = local_time.tm_hour;
int Min = local_time.tm_min;
int Sec = local_time.tm_sec;
return 0;
}
其他回答
这适用于g++,我不确定这是否对你有帮助。 项目输出:
The current time is 11:43:41 am
The current date is 6-18-2015 June Wednesday
Day of month is 17 and the Month of year is 6,
also the day of year is 167 & our Weekday is 3.
The current year is 2015.
代码:
#include <ctime>
#include <iostream>
#include <string>
#include <stdio.h>
#include <time.h>
using namespace std;
const std::string currentTime() {
time_t now = time(0);
struct tm tstruct;
char buf[80];
tstruct = *localtime(&now);
strftime(buf, sizeof(buf), "%H:%M:%S %P", &tstruct);
return buf;
}
const std::string currentDate() {
time_t now = time(0);
struct tm tstruct;
char buf[80];
tstruct = *localtime(&now);
strftime(buf, sizeof(buf), "%B %A ", &tstruct);
return buf;
}
int main() {
cout << "\033[2J\033[1;1H";
std:cout << "The current time is " << currentTime() << std::endl;
time_t t = time(0); // get time now
struct tm * now = localtime( & t );
cout << "The current date is " << now->tm_mon + 1 << '-'
<< (now->tm_mday + 1) << '-'
<< (now->tm_year + 1900)
<< " " << currentDate() << endl;
cout << "Day of month is " << (now->tm_mday)
<< " and the Month of year is " << (now->tm_mon)+1 << "," << endl;
cout << "also the day of year is " << (now->tm_yday)
<< " & our Weekday is " << (now->tm_wday) << "." << endl;
cout << "The current year is " << (now->tm_year)+1900 << "."
<< endl;
return 0;
}
从c++ 11开始,你可以使用std::chrono::system_clock::now()
示例(复制自en.cppreference.com):
#include <iostream>
#include <chrono>
#include <ctime>
int main()
{
auto start = std::chrono::system_clock::now();
// Some computation here
auto end = std::chrono::system_clock::now();
std::chrono::duration<double> elapsed_seconds = end-start;
std::time_t end_time = std::chrono::system_clock::to_time_t(end);
std::cout << "finished computation at " << std::ctime(&end_time)
<< "elapsed time: " << elapsed_seconds.count() << "s"
<< std::endl;
}
这应该打印如下内容:
finished computation at Mon Oct 2 00:59:08 2017
elapsed time: 1.88232s
ctime std::
为什么到目前为止只有评论提到了ctime ?
#include <ctime>
#include <iostream>
int main()
{
std::time_t result = std::time(nullptr);
std::cout << std::ctime(&result);
}
输出
周二 12月 27 5:21:29 PM 2011
(给谷歌人)
还有Boost::date_time:
#include <boost/date_time/posix_time/posix_time.hpp>
boost::posix_time::ptime date_time = boost::posix_time::microsec_clock::universal_time();
http://www.cplusplus.com/reference/ctime/strftime/
这个内置功能似乎提供了一组合理的选项。
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