Try

import matplotlib.pyplot as plt
plt.plot([1,2,3])
plt.show(block=False)
# other code
# [...]

# Put
plt.show()
# at the very end of your script to make sure Python doesn't bail out
# before you finished examining.

show()文档说:

在非交互模式下，显示所有图形并阻塞直到图形关闭;在交互模式下，除非在从非交互模式切换到交互模式之前创建了图形，否则没有效果(不推荐)。在这种情况下，它会显示数字，但不会阻塞。 单个实验关键字参数block可以被设置为True或False以覆盖上面描述的阻塞行为。

嗯，我在搞清楚非阻塞命令方面遇到了很大的困难……但最后，我成功地重做了“Cookbook/Matplotlib/Animations -动画选定的绘图元素”的例子，所以它可以在Ubuntu 10.04的Python 2.6.5上与线程一起工作(并通过全局变量或多进程管道在线程之间传递数据)。

脚本可以在这里找到:Animating_selected_plot_elements-thread.py -否则粘贴在下面(注释更少)以供参考:

import sys
import gtk, gobject
import matplotlib
matplotlib.use('GTKAgg')
import pylab as p
import numpy as nx 
import time

import threading 



ax = p.subplot(111)
canvas = ax.figure.canvas

# for profiling
tstart = time.time()

# create the initial line
x = nx.arange(0,2*nx.pi,0.01)
line, = ax.plot(x, nx.sin(x), animated=True)

# save the clean slate background -- everything but the animated line
# is drawn and saved in the pixel buffer background
background = canvas.copy_from_bbox(ax.bbox)


# just a plain global var to pass data (from main, to plot update thread)
global mypass

# http://docs.python.org/library/multiprocessing.html#pipes-and-queues
from multiprocessing import Pipe
global pipe1main, pipe1upd
pipe1main, pipe1upd = Pipe()


# the kind of processing we might want to do in a main() function,
# will now be done in a "main thread" - so it can run in
# parallel with gobject.idle_add(update_line)
def threadMainTest():
    global mypass
    global runthread
    global pipe1main

    print "tt"

    interncount = 1

    while runthread: 
        mypass += 1
        if mypass > 100: # start "speeding up" animation, only after 100 counts have passed
            interncount *= 1.03
        pipe1main.send(interncount)
        time.sleep(0.01)
    return


# main plot / GUI update
def update_line(*args):
    global mypass
    global t0
    global runthread
    global pipe1upd

    if not runthread:
        return False 

    if pipe1upd.poll(): # check first if there is anything to receive
        myinterncount = pipe1upd.recv()

    update_line.cnt = mypass

    # restore the clean slate background
    canvas.restore_region(background)
    # update the data
    line.set_ydata(nx.sin(x+(update_line.cnt+myinterncount)/10.0))
    # just draw the animated artist
    ax.draw_artist(line)
    # just redraw the axes rectangle
    canvas.blit(ax.bbox)

    if update_line.cnt>=500:
        # print the timing info and quit
        print 'FPS:' , update_line.cnt/(time.time()-tstart)

        runthread=0
        t0.join(1)   
        print "exiting"
        sys.exit(0)

    return True



global runthread

update_line.cnt = 0
mypass = 0

runthread=1

gobject.idle_add(update_line)

global t0
t0 = threading.Thread(target=threadMainTest)
t0.start() 

# start the graphics update thread
p.show()

print "out" # will never print - show() blocks indefinitely! 

希望这能帮助到一些人， 干杯!

在我的例子中，我希望在计算窗口时弹出几个窗口。作为参考，方法如下:

from matplotlib.pyplot import draw, figure, show
f1, f2 = figure(), figure()
af1 = f1.add_subplot(111)
af2 = f2.add_subplot(111)
af1.plot([1,2,3])
af2.plot([6,5,4])
draw() 
print 'continuing computation'
show()

一个非常有用的matplotlib的OO接口指南。

您可能需要阅读matplotlib文档中的这个文档，标题为:

在python shell中使用matplotlib

plt.figure(1)
plt.imshow(your_first_image)

plt.figure(2)
plt.imshow(your_second_image)

plt.show(block=False) # That's important 

raw_input("Press ENTER to exist") # Useful when you run your Python script from the terminal and you want to hold the running to see your figures until you press Enter

使用matplotlib调用不会阻塞:

使用画():

from matplotlib.pyplot import plot, draw, show
plot([1,2,3])
draw()
print('continue computation')

# at the end call show to ensure window won't close.
show()

使用交互模式:

from matplotlib.pyplot import plot, ion, show
ion() # enables interactive mode
plot([1,2,3]) # result shows immediatelly (implicit draw())

print('continue computation')

# at the end call show to ensure window won't close.
show()