如何将数据帧列转换为数字类型?
当前回答
如果x是dataframe dat的列名,x的类型是factor,使用:
as.numeric(as.character(dat$x))
其他回答
要将字符转换为数字,您必须通过应用将其转换为因数
BankFinal1 <- transform(BankLoan, LoanApproval=as.factor(LoanApproval))
BankFinal1 <- transform(BankFinal1, LoanApp=as.factor(LoanApproval))
您必须用相同的数据创建两列,因为一列不能转换为数字。如果你做一次转换,它会给出如下错误
transform(BankData, LoanApp=as.numeric(LoanApproval))
警告信息: 在eval(替代(列表 (...)), `_ 数据”,parent.frame ()): 胁迫引入的NAs
所以,在做了两列相同的数据应用后
BankFinal1 <- transform(BankFinal1, LoanApp = as.numeric(LoanApp),
LoanApproval = as.numeric(LoanApproval))
它将成功地将字符转换为数字
要将数据帧列转换为数字,你只需要做:-
因数转换为数字:-
data_frame$column <- as.numeric(as.character(data_frame$column))
如果x是dataframe dat的列名,x的类型是factor,使用:
as.numeric(as.character(dat$x))
虽然你的问题严格是关于数字的,但在开始r时,有许多转换是难以理解的。我将致力于解决帮助的方法。这个问题和这个问题类似。
在R中,类型转换可能是一种痛苦,因为(1)因子不能直接转换为数字,它们需要首先转换为字符类,(2)日期是一种特殊情况,通常需要单独处理,(3)跨数据帧列的循环可能很棘手。幸运的是,“潮流宇宙”已经解决了大部分问题。
This solution uses mutate_each() to apply a function to all columns in a data frame. In this case, we want to apply the type.convert() function, which converts strings to numeric where it can. Because R loves factors (not sure why) character columns that should stay character get changed to factor. To fix this, the mutate_if() function is used to detect columns that are factors and change to character. Last, I wanted to show how lubridate can be used to change a timestamp in character class to date-time because this is also often a sticking block for beginners.
library(tidyverse)
library(lubridate)
# Recreate data that needs converted to numeric, date-time, etc
data_df
#> # A tibble: 5 × 9
#> TIMESTAMP SYMBOL EX PRICE SIZE COND BID BIDSIZ OFR
#> <chr> <chr> <chr> <chr> <chr> <chr> <chr> <chr> <chr>
#> 1 2012-05-04 09:30:00 BAC T 7.8900 38538 F 7.89 523 7.90
#> 2 2012-05-04 09:30:01 BAC Z 7.8850 288 @ 7.88 61033 7.90
#> 3 2012-05-04 09:30:03 BAC X 7.8900 1000 @ 7.88 1974 7.89
#> 4 2012-05-04 09:30:07 BAC T 7.8900 19052 F 7.88 1058 7.89
#> 5 2012-05-04 09:30:08 BAC Y 7.8900 85053 F 7.88 108101 7.90
# Converting columns to numeric using "tidyverse"
data_df %>%
mutate_all(type.convert) %>%
mutate_if(is.factor, as.character) %>%
mutate(TIMESTAMP = as_datetime(TIMESTAMP, tz = Sys.timezone()))
#> # A tibble: 5 × 9
#> TIMESTAMP SYMBOL EX PRICE SIZE COND BID BIDSIZ OFR
#> <dttm> <chr> <chr> <dbl> <int> <chr> <dbl> <int> <dbl>
#> 1 2012-05-04 09:30:00 BAC T 7.890 38538 F 7.89 523 7.90
#> 2 2012-05-04 09:30:01 BAC Z 7.885 288 @ 7.88 61033 7.90
#> 3 2012-05-04 09:30:03 BAC X 7.890 1000 @ 7.88 1974 7.89
#> 4 2012-05-04 09:30:07 BAC T 7.890 19052 F 7.88 1058 7.89
#> 5 2012-05-04 09:30:08 BAC Y 7.890 85053 F 7.88 108101 7.90
使用type.convert()和rapply()的通用方式:
convert_types <- function(x) {
stopifnot(is.list(x))
x[] <- rapply(x, utils::type.convert, classes = "character",
how = "replace", as.is = TRUE)
return(x)
}
d <- data.frame(char = letters[1:5],
fake_char = as.character(1:5),
fac = factor(1:5),
char_fac = factor(letters[1:5]),
num = 1:5, stringsAsFactors = FALSE)
sapply(d, class)
#> char fake_char fac char_fac num
#> "character" "character" "factor" "factor" "integer"
sapply(convert_types(d), class)
#> char fake_char fac char_fac num
#> "character" "integer" "factor" "factor" "integer"
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