如果我想使用System.Net.HttpClient提交一个http获取请求,似乎没有api来添加参数,这是正确的吗?

是否有任何简单的api可用来构建查询字符串,不涉及构建名称值集合和url编码,然后最后连接它们? 我希望使用类似RestSharp的api(即AddParameter(..))


当前回答

HttpClient client = new HttpClient();
var uri = Environment.GetEnvironmentVariable("URL of Api");
                
var requesturi = QueryHelpers.AddQueryString(uri, "parameter_name",parameter_value);
client.BaseAddress = new Uri(requesturi);

然后你也可以添加请求头例如:

client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
client.DefaultRequestHeaders.Add("x-api-key", secretValue);

响应语法eg:

HttpResponseMessage response = client.GetAsync(requesturi).Result;

希望它对你有用。

其他回答

对于那些不想包括系统。Web在项目中还没有使用它,你可以使用System.Net.Http的FormUrlEncodedContent,并做如下的事情:

keyvaluepair版本

string query;
using(var content = new FormUrlEncodedContent(new KeyValuePair<string, string>[]{
    new KeyValuePair<string, string>("ham", "Glazed?"),
    new KeyValuePair<string, string>("x-men", "Wolverine + Logan"),
    new KeyValuePair<string, string>("Time", DateTime.UtcNow.ToString()),
})) {
    query = content.ReadAsStringAsync().Result;
}

字典的版本

string query;
using(var content = new FormUrlEncodedContent(new Dictionary<string, string>()
{
    { "ham", "Glaced?"},
    { "x-men", "Wolverine + Logan"},
    { "Time", DateTime.UtcNow.ToString() },
})) {
    query = content.ReadAsStringAsync().Result;
}

我正在开发的RFC 6570 URI Template库能够执行此操作。所有编码都按照RFC为您处理。在撰写本文时,beta版本已经可用,它不是稳定的1.0版本的唯一原因是文档没有完全满足我的期望(参见问题#17、#18、#32、#43)。

你可以单独构建一个查询字符串:

UriTemplate template = new UriTemplate("{?params*}");
var parameters = new Dictionary<string, string>
  {
    { "param1", "value1" },
    { "param2", "value2" },
  };
Uri relativeUri = template.BindByName(parameters);

或者你可以构建一个完整的URI:

UriTemplate template = new UriTemplate("path/to/item{?params*}");
var parameters = new Dictionary<string, string>
  {
    { "param1", "value1" },
    { "param2", "value2" },
  };
Uri baseAddress = new Uri("http://www.example.com");
Uri relativeUri = template.BindByName(baseAddress, parameters);
HttpClient client = new HttpClient();
var uri = Environment.GetEnvironmentVariable("URL of Api");
                
var requesturi = QueryHelpers.AddQueryString(uri, "parameter_name",parameter_value);
client.BaseAddress = new Uri(requesturi);

然后你也可以添加请求头例如:

client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
client.DefaultRequestHeaders.Add("x-api-key", secretValue);

响应语法eg:

HttpResponseMessage response = client.GetAsync(requesturi).Result;

希望它对你有用。

接受答案的好部分,修改为使用UriBuilder.Uri.ParseQueryString()而不是HttpUtility.ParseQueryString():

var builder = new UriBuilder("http://example.com");
var query = builder.Uri.ParseQueryString();
query["foo"] = "bar<>&-baz";
query["bar"] = "bazinga";
builder.Query = query.ToString();
string url = builder.ToString();

您可能想看看Flurl[披露:我是作者],这是一个流畅的URL构建器,带有可选的配套库,可以将其扩展为一个成熟的REST客户机。

var result = await "https://api.com"
    // basic URL building:
    .AppendPathSegment("endpoint")
    .SetQueryParams(new {
        api_key = ConfigurationManager.AppSettings["SomeApiKey"],
        max_results = 20,
        q = "Don't worry, I'll get encoded!"
    })
    .SetQueryParams(myDictionary)
    .SetQueryParam("q", "overwrite q!")

    // extensions provided by Flurl.Http:
    .WithOAuthBearerToken("token")
    .GetJsonAsync<TResult>();

查看文档了解更多细节。完整的软件包在NuGet上可用:

PM>安装包Flurl。Http

或者只是独立的URL构建器:

PM>安装包Flurl