"UnicodeDecodeError: 'ascii' codec can't decode byte"

错误原因:input_string必须是unicode，但给出了str

"TypeError: Decoding Unicode is not supported"

此错误的原因:试图将unicode input_string转换为unicode

因此，首先检查你的input_string是否为str，并在必要时转换为unicode:

if isinstance(input_string, str):
   input_string = unicode(input_string, 'utf-8')

其次，上面只是改变了类型，但没有删除非ascii字符。如果你想删除非ascii字符:

if isinstance(input_string, str):
   input_string = input_string.decode('ascii', 'ignore').encode('ascii') #note: this removes the character and encodes back to string.

elif isinstance(input_string, unicode):
   input_string = input_string.encode('ascii', 'ignore')

Got a same error and this solved my error. Thanks! python 2 and python 3 differing in unicode handling is making pickled files quite incompatible to load. So Use python pickle's encoding argument. Link below helped me solve the similar problem when I was trying to open pickled data from my python 3.7, while my file was saved originally in python 2.x version. https://blog.modest-destiny.com/posts/python-2-and-3-compatible-pickle-save-and-load/ I copy the load_pickle function in my script and called the load_pickle(pickle_file) while loading my input_data like this:

input_data = load_pickle("my_dataset.pkl")

load_pickle函数在这里:

def load_pickle(pickle_file):
    try:
        with open(pickle_file, 'rb') as f:
            pickle_data = pickle.load(f)
    except UnicodeDecodeError as e:
        with open(pickle_file, 'rb') as f:
            pickle_data = pickle.load(f, encoding='latin1')
    except Exception as e:
        print('Unable to load data ', pickle_file, ':', e)
        raise
    return pickle_data

"UnicodeDecodeError: 'ascii' codec can't decode byte"

错误原因:input_string必须是unicode，但给出了str

"TypeError: Decoding Unicode is not supported"

此错误的原因:试图将unicode input_string转换为unicode

因此，首先检查你的input_string是否为str，并在必要时转换为unicode:

if isinstance(input_string, str):
   input_string = unicode(input_string, 'utf-8')

其次，上面只是改变了类型，但没有删除非ascii字符。如果你想删除非ascii字符:

if isinstance(input_string, str):
   input_string = input_string.decode('ascii', 'ignore').encode('ascii') #note: this removes the character and encodes back to string.

elif isinstance(input_string, unicode):
   input_string = input_string.encode('ascii', 'ignore')

我得到了字符串“PastelerÃ-a Mallorca”同样的问题，我用:

unicode("Pastelería Mallorca", 'latin-1')

我正在搜索解决以下错误信息:

Unicodedecodeerror: 'ascii'编解码器无法解码位置5454中的字节0xe2:序号不在范围(128)

我最终通过指定'encoding'来修复它:

f = open('../glove/glove.6B.100d.txt', encoding="utf-8")

希望它也能帮助到你。

在Django (1.9.10)/Python 2.7.5项目中，我经常出现UnicodeDecodeError异常;主要是当我试图向日志记录提供unicode字符串时。我为任意对象创建了一个辅助函数，基本上格式化为8位ascii字符串，并将表中不包含的任何字符替换为'?'。我认为这不是最好的解决方案，但由于默认编码是ascii(我不想改变它)，它会这样做:

encode_for_logging(c, encoding='ascii'): 如果isinstance(c, basestring): 返回c.encode(encoding， 'replace') elif isinstance(c, Iterable): C_ = [] 对于v (c) c_。追加(encode_for_logging (v,编码) 返回c_ 其他: 返回encode_for_logging (unicode (c)) ｀