我试图使用一个选择语句从某个MySQL表中获得除一个以外的所有列。有什么简单的方法吗?

编辑:在这个表格中有53列(不是我的设计)


当前回答

这个问题是关于MySQL的,但我仍然认为值得一提的是,至少谷歌BigQuery和H2原生支持* EXCEPT语法。

SELECT * FROM actor

生产:

|actor_id|first_name|last_name   |last_update            |
|--------|----------|------------|-----------------------|
|1       |PENELOPE  |GUINESS     |2006-02-15 04:34:33.000|
|2       |NICK      |WAHLBERG    |2006-02-15 04:34:33.000|
|3       |ED        |CHASE       |2006-02-15 04:34:33.000|

SELECT * EXCEPT (last_update) FROM actor

生产:

|actor_id|first_name|last_name   |
|--------|----------|------------|
|1       |PENELOPE  |GUINESS     |
|2       |NICK      |WAHLBERG    |
|3       |ED        |CHASE       |

也许,MySQL的未来版本也会支持这种语法?

其他回答

是的,尽管根据表的不同,I/O可能会很高,但我找到了一个解决方案。

SELECT *
INTO #temp
FROM table

ALTER TABLE #temp DROP COlUMN column_name

SELECT *
FROM #temp

实际上有一种方法,当然你需要有权限才能这样做…

SET @sql = CONCAT('SELECT ', (SELECT REPLACE(GROUP_CONCAT(COLUMN_NAME), '<columns_to_omit>,', '') FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME = '<table>' AND TABLE_SCHEMA = '<database>'), ' FROM <table>');

PREPARE stmt1 FROM @sql;
EXECUTE stmt1;

替换<表>,<数据库>和< columns_to_省略>

也许我有一个解决Jan Koritak指出的矛盾的方法

SELECT CONCAT('SELECT ',
( SELECT GROUP_CONCAT(t.col)
FROM
(
    SELECT CASE
    WHEN COLUMN_NAME = 'eid' THEN NULL
    ELSE COLUMN_NAME
    END AS col 
    FROM INFORMATION_SCHEMA.COLUMNS 
    WHERE TABLE_NAME = 'employee' AND TABLE_SCHEMA = 'test'
) t
WHERE t.col IS NOT NULL) ,
' FROM employee' );

表:

SELECT table_name,column_name 
FROM INFORMATION_SCHEMA.COLUMNS 
WHERE TABLE_NAME = 'employee' AND TABLE_SCHEMA = 'test'

= = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = =

table_name  column_name
employee    eid
employee    name_eid
employee    sal

= = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = =

查询结果:

'SELECT name_eid,sal FROM employee'

如果它总是相同的一列,那么你可以创建一个不包含它的视图。

否则,不,我不这么认为。

起初我以为你可以使用正则表达式,但我一直在阅读MYSQL文档,似乎你不能。如果我是你,我会使用另一种语言(如PHP)来生成您想要获取的列的列表,将其存储为字符串,然后使用它来生成SQL。