有人知道是否有断言或类似的东西可以测试被测试的代码中是否抛出了异常吗?


当前回答

function yourfunction($a,$z){
   if($a<$z){ throw new <YOUR_EXCEPTION>; }
}

下面是测试

class FunctionTest extends \PHPUnit_Framework_TestCase{

   public function testException(){

      $this->setExpectedException(<YOUR_EXCEPTION>::class);
      yourfunction(1,2);//add vars that cause the exception 

   }

}

其他回答

/**
 * @expectedException Exception
 * @expectedExceptionMessage Amount has to be bigger then 0!
 */
public function testDepositNegative()
{
    $this->account->deposit(-7);
}

注意“/**”,注意两个“*”。只写“**”(星号)将使代码失败。 同时确保你使用的是phpUnit的最新版本。在phpunit的一些早期版本中,不支持@expectedException异常。我有4.0,它不适合我,我必须更新到5.5 https://coderwall.com/p/mklvdw/install-phpunit-with-composer更新与作曲家。

全面的解决方案

PHPUnit当前异常测试的“最佳实践”似乎…低迷(文档)。

由于我想要的不仅仅是当前的expectException实现,所以我在测试用例中使用了一个trait。它只有大约50行代码。

每个测试支持多个异常 支持异常抛出后调用的断言 健壮和清晰的使用示例 标准断言语法 不仅支持消息、代码和类的断言 支持反向断言,assertNotThrows 支持PHP 7可抛出错误

图书馆

我发布了AssertThrows trait到Github和packagist,这样它就可以与composer一起安装了。

简单的例子

只是为了说明语法背后的精神:

<?php

// Using simple callback
$this->assertThrows(MyException::class, [$obj, 'doSomethingBad']);

// Using anonymous function
$this->assertThrows(MyException::class, function() use ($obj) {
    $obj->doSomethingBad();
});

很整洁的?


完整使用示例

请看下面一个更全面的使用示例:

<?php

declare(strict_types=1);

use Jchook\AssertThrows\AssertThrows;
use PHPUnit\Framework\TestCase;

// These are just for illustration
use MyNamespace\MyException;
use MyNamespace\MyObject;

final class MyTest extends TestCase
{
    use AssertThrows; // <--- adds the assertThrows method

    public function testMyObject()
    {
        $obj = new MyObject();

        // Test a basic exception is thrown
        $this->assertThrows(MyException::class, function() use ($obj) {
            $obj->doSomethingBad();
        });

        // Test custom aspects of a custom extension class
        $this->assertThrows(MyException::class, 
            function() use ($obj) {
                $obj->doSomethingBad();
            },
            function($exception) {
                $this->assertEquals('Expected value', $exception->getCustomThing());
                $this->assertEquals(123, $exception->getCode());
            }
        );

        // Test that a specific exception is NOT thrown
        $this->assertNotThrows(MyException::class, function() use ($obj) {
            $obj->doSomethingGood();
        });
    }
}

?>
public function testException() {
    try {
        $this->methodThatThrowsException();
        $this->fail("Expected Exception has not been raised.");
    } catch (Exception $ex) {
        $this->assertEquals("Exception message", $ex->getMessage());
    }
    
}

PHPUnit expectException方法非常不方便,因为它只允许每个测试方法测试一个异常。

我使用这个helper函数来断言某个函数抛出异常:

/**
 * Asserts that the given callback throws the given exception.
 *
 * @param string $expectClass The name of the expected exception class
 * @param callable $callback A callback which should throw the exception
 */
protected function assertException(string $expectClass, callable $callback)
{
    try {
        $callback();
    } catch (\Throwable $exception) {
        $this->assertInstanceOf($expectClass, $exception, 'An invalid exception was thrown');
        return;
    }

    $this->fail('No exception was thrown');
}

将它添加到您的测试类中,并以这样的方式调用:

public function testSomething() {
    $this->assertException(\PDOException::class, function() {
        new \PDO('bad:param');
    });
    $this->assertException(\PDOException::class, function() {
        new \PDO('foo:bar');
    });
}

您可以使用assertException扩展在一次测试执行期间断言多个异常。

插入方法到您的TestCase并使用:

public function testSomething()
{
    $test = function() {
        // some code that has to throw an exception
    };
    $this->assertException( $test, 'InvalidArgumentException', 100, 'expected message' );
}

我还为喜欢漂亮代码的人做了一个trait ..