下面是2011年10月9日的解决方案,由用户在https://gist.github.com/982883上发表评论:

UUIDv4 = function b(a){return a?(a^Math.random()*16>>a/4).toString(16):([1e7]+-1e3+-4e3+-8e3+-1e11).replace(/[018]/g,b)}

这实现了与当前最高评级的答案相同的目标,但在50比以更少的比特中,利用强迫性、回报性和曝光性评级。

UUIDv4 =

function b(
  a // placeholder
){
  return a // if the placeholder was passed, return
    ? ( // a random number from 0 to 15
      a ^ // unless b is 8,
      Math.random() // in which case
      * 16 // a random number from
      >> a/4 // 8 to 11
      ).toString(16) // in hexadecimal
    : ( // or otherwise a concatenated string:
      [1e7] + // 10000000 +
      -1e3 + // -1000 +
      -4e3 + // -4000 +
      -8e3 + // -80000000 +
      -1e11 // -100000000000,
      ).replace( // replacing
        /[018]/g, // zeroes, ones, and eights with
        b // random hex digits
      )
}

这里是一个类似的 RFC4122 版本 4 符合的解决方案,解决了这个问题,通过将第一个 13 个 hex 数字以一个 hex 部分的时光,并一旦被一个 hex 部分的微秒从 pageload. 因此,即使 Math.random 是相同的种子,两个客户将不得不产生 UUID 相同的数量的微秒从 pageload (如果高性能

const generateUUID = () => { let d = new Date().getTime(), d2 = ((typeof performance !== 'undefined') && performance.now && (performance.now() * 1000)) || 0; return 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(/[xy]/g, c => { let r = Math.random() * 16; if (d > 0) { r = (d + r) % 16 | 0; d = Math.floor(d / 16); } else { r = (d2 + r) % 16 | 0; d2 = Math.floor(d2 / 16); } return (c == 'x' ? r : (r & 0x7 | 0x8)).toString(16); }); }; const onClick = (e) => document.getElementById('uuid').textContent = generateUUID(); document.getElementById('generateUUID').addEventListener('click', onClick); onClick(); #uuid { font-family: monospace; font-size: 1.5em; } <p id="uuid"></p> <button id="generateUUID">Generate UUID</button>

我使用这个版本. 它是安全和简单的. 它不是为了产生格式化的Uids,它只是为了产生你需要的电缆的随机线条。

export function makeId(length) {
  let result = '';
  const characters = 'ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789';
  const charactersLength = characters.length;

  for (let i = 0; i < length; i++) {
    let letterPos = parseInt(crypto.getRandomValues(new Uint8Array(1))[0] / 255 * charactersLength - 1, 10)
    result += characters[letterPos]
  }
  return result;
}

我想了解布罗法的答案,所以我扩展了它并添加了评论:

var uuid = function () {
    return 'xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx'.replace(
        /[xy]/g,
        function (match) {
            /*
            * Create a random nibble. The two clever bits of this code:
            *
            * - Bitwise operations will truncate floating point numbers
            * - For a bitwise OR of any x, x | 0 = x
            *
            * So:
            *
            * Math.random * 16
            *
            * creates a random floating point number
            * between 0 (inclusive) and 16 (exclusive) and
            *
            * | 0
            *
            * truncates the floating point number into an integer.
            */
            var randomNibble = Math.random() * 16 | 0;

            /*
            * Resolves the variant field. If the variant field (delineated
            * as y in the initial string) is matched, the nibble must
            * match the mask (where x is a do-not-care bit):
            *
            * 10xx
            *
            * This is achieved by performing the following operations in
            * sequence (where x is an intermediate result):
            *
            * - x & 0x3, which is equivalent to x % 3
            * - x | 0x8, which is equivalent to x + 8
            *
            * This results in a nibble between 8 inclusive and 11 exclusive,
            * (or 1000 and 1011 in binary), all of which satisfy the variant
            * field mask above.
            */
            var nibble = (match == 'y') ?
                (randomNibble & 0x3 | 0x8) :
                randomNibble;

            /*
            * Ensure the nibble integer is encoded as base 16 (hexadecimal).
            */
            return nibble.toString(16);
        }
    );
};

function randomHex(length) {
    var random_string = '';
    if(!length){
        length = 1;
    }
    for(var i=0; i<length; i+=1){
        random_string += Math.floor(Math.random() * 15).toString(16);
    }
    return random_string;
}

function guid() {
    return randomHex(8);
}

这创建了一个版本 4 UUID (创建于假冒随机数字):

function uuid()
{
   var chars = '0123456789abcdef'.split('');

   var uuid = [], rnd = Math.random, r;
   uuid[8] = uuid[13] = uuid[18] = uuid[23] = '-';
   uuid[14] = '4'; // version 4

   for (var i = 0; i < 36; i++)
   {
      if (!uuid[i])
      {
         r = 0 | rnd()*16;

         uuid[i] = chars[(i == 19) ? (r & 0x3) | 0x8 : r & 0xf];
      }
   }

   return uuid.join('');
}

下面是产生的 UUID 的样本:

682db637-0f31-4847-9cdf-25ba9613a75c
97d19478-3ab2-4aa1-b8cc-a1c3540f54aa
2eed04c9-2692-456d-a0fd-51012f947136