使用jQuery jsonp请求:

<script type="text/javascript">
    $.ajax({
        type:'GET',
        url: 'http://vimeo.com/api/v2/video/' + video_id + '.json',
        jsonp: 'callback',
        dataType: 'jsonp',
        success: function(data){
            var thumbnail_src = data[0].thumbnail_large;
            $('#thumb_wrapper').append('<img src="' + thumbnail_src + '"/>');
        }
    });
</script>

<div id="thumb_wrapper"></div>

下面是一个如何在ASP中做同样的事情的例子。NET使用c#。请随意使用不同的错误捕获图像:)

public string GetVimeoPreviewImage(string vimeoURL)
{
    try
    {
        string vimeoUrl = System.Web.HttpContext.Current.Server.HtmlEncode(vimeoURL);
        int pos = vimeoUrl.LastIndexOf(".com");
        string videoID = vimeoUrl.Substring(pos + 4, 8);

        XmlDocument doc = new XmlDocument();
        doc.Load("http://vimeo.com/api/v2/video/" + videoID + ".xml");
        XmlElement root = doc.DocumentElement;
        string vimeoThumb = root.FirstChild.SelectSingleNode("thumbnail_medium").ChildNodes[0].Value;
        string imageURL = vimeoThumb;
        return imageURL;
    }
    catch
    {
        //cat with cheese on it's face fail
        return "http://bestofepicfail.com/wp-content/uploads/2008/08/cheese_fail.jpg";
    }
}

注意:当被请求时，你的API请求应该像这样:http://vimeo.com/api/v2/video/32660708.xml

对于像我这样最近正试图弄清楚这个问题的人来说，

https://i.vimeocdn.com/video/[video_id]_[dimension].webp适合我。

(其中尺寸= 200x150 | 640)

来自Vimeo Simple API文档:

视频请求

为了获得特定视频的数据， 使用以下url: http://vimeo.com/api/v2/video/video_id.output video_id需要信息的视频ID。 指定 输出类型。我们目前提供JSON， PHP和XML格式。

获取这个URL http://vimeo.com/api/v2/video/6271487.xml

    <videos> 
      <video> 
        [skipped]
        <thumbnail_small>http://ts.vimeo.com.s3.amazonaws.com/235/662/23566238_100.jpg</thumbnail_small> 
        <thumbnail_medium>http://ts.vimeo.com.s3.amazonaws.com/235/662/23566238_200.jpg</thumbnail_medium> 
        <thumbnail_large>http://ts.vimeo.com.s3.amazonaws.com/235/662/23566238_640.jpg</thumbnail_large> 
        [skipped]
    </videos>

解析每个视频以获得缩略图

下面是PHP的近似代码

<?php

$imgid = 6271487;

$hash = unserialize(file_get_contents("http://vimeo.com/api/v2/video/$imgid.php"));

echo $hash[0]['thumbnail_medium'];  

我创建了一个code depen来为您获取图像。

https://codepen.io/isramv/pen/gOpabXg

HTML

<input type="text" id="vimeoid" placeholder="257314493" value="257314493">
<button id="getVideo">Get Video</button>
<div id="output"></div>

JavaScript:

const videoIdInput = document.getElementById('vimeoid');
const getVideo = document.getElementById('getVideo');
const output = document.getElementById('output');

function getVideoThumbnails(videoid) {
  fetch(`https://vimeo.com/api/v2/video/${videoid}.json`)
  .then(response => {
    return response.text();
  })
  .then(data => {
    const { thumbnail_large, thumbnail_medium, thumbnail_small } = JSON.parse(data)[0];
    const small = `<img src="${thumbnail_small}"/>`;
    const medium = `<img src="${thumbnail_medium}"/>`;
    const large = `<img src="${thumbnail_large}"/>`;
    output.innerHTML = small + medium + large;
  })
  .catch(error => {
    console.log(error);
  });
}

getVideo.addEventListener('click', e => {
  if (!isNaN(videoIdInput.value)) {
    getVideoThumbnails(videoIdInput.value);
  }
});

我写了一个函数在PHP让我这，我希望它对某人有用。缩略图的路径包含在视频页面的链接标记中。这似乎对我有用。

    $video_url = "http://vimeo.com/7811853"  
    $file = fopen($video_url, "r");
    $filedata = stream_get_contents($file);
    $html_content = strpos($filedata,"<link rel=\"videothumbnail");
    $link_string = substr($filedata, $html_content, 128);
    $video_id_array = explode("\"", $link_string);
    $thumbnail_url = $video_id_array[3];
    echo $thumbnail_url;

希望能对大家有所帮助。

Foggson