我想从Vimeo获得视频的缩略图。

当从Youtube上获得图像时,我只是这样做:

http://img.youtube.com/vi/HwP5NG-3e8I/2.jpg

你知道如何处理Vimeo吗?

同样的问题,没有答案。


当前回答

对于像我这样最近正试图弄清楚这个问题的人来说,

https://i.vimeocdn.com/video/[video_id]_[dimension].webp适合我。

(其中尺寸= 200x150 | 640)

其他回答

来自Vimeo Simple API文档:

视频请求

为了获得特定视频的数据, 使用以下url: http://vimeo.com/api/v2/video/video_id.output video_id需要信息的视频ID。 指定 输出类型。我们目前提供JSON, PHP和XML格式。

获取这个URL http://vimeo.com/api/v2/video/6271487.xml

    <videos> 
      <video> 
        [skipped]
        <thumbnail_small>http://ts.vimeo.com.s3.amazonaws.com/235/662/23566238_100.jpg</thumbnail_small> 
        <thumbnail_medium>http://ts.vimeo.com.s3.amazonaws.com/235/662/23566238_200.jpg</thumbnail_medium> 
        <thumbnail_large>http://ts.vimeo.com.s3.amazonaws.com/235/662/23566238_640.jpg</thumbnail_large> 
        [skipped]
    </videos>

解析每个视频以获得缩略图

下面是PHP的近似代码

<?php

$imgid = 6271487;

$hash = unserialize(file_get_contents("http://vimeo.com/api/v2/video/$imgid.php"));

echo $hash[0]['thumbnail_medium'];  

如果您不需要自动解决方案,您可以通过在这里输入vimeo ID: http://video.depone.eu/来找到缩略图URL

2020的解决方案:

我写了一个使用Vimeo Oembed API的PHP函数。

/**
 * Get Vimeo.com video thumbnail URL
 *
 * Set the referer parameter if your video is domain restricted.
 * 
 * @param  int    $videoid   Video id
 * @param  URL    $referer   Your website domain
 * @return bool/string       Thumbnail URL or false if can't access the video
 */
function get_vimeo_thumbnail_url( $videoid, $referer=null ){

    // if referer set, create context
    $ctx = null;
    if( isset($referer) ){
        $ctxa = array(
            'http' => array(
                'header' => array("Referer: $referer\r\n"),
                'request_fulluri' => true,
            ),
        );
        $ctx = stream_context_create($ctxa);
    }

    $resp = @file_get_contents("https://vimeo.com/api/oembed.json?url=https://vimeo.com/$videoid", False, $ctx);
    $resp = json_decode($resp, true);

return $resp["thumbnail_url"]??false;
}

用法:

echo get_vimeo_thumbnail_url("1084537");

分解Karthikeyan P的答案,使其可以用于更广泛的场景:

// Requires jQuery

function parseVimeoIdFromUrl(vimeoUrl) {
  var match = /vimeo.*\/(\d+)/i.exec(vimeoUrl);
  if (match)
    return match[1];

  return null;
};

function getVimeoThumbUrl(vimeoId) {
  var deferred = $.Deferred();
  $.ajax(
    '//www.vimeo.com/api/v2/video/' + vimeoId + '.json',
    {
        dataType: 'jsonp',
        cache: true
    }
  )
  .done(function (data) {
    // .thumbnail_small 100x75
    // .thumbnail_medium 200x150
    // 640 wide
        var img = data[0].thumbnail_large;
        deferred.resolve(img);  
    })
  .fail(function(a, b, c) {
    deferred.reject(a, b, c);
  });
  return deferred;
};

使用

从Vimeo视频URL获取Vimeo Id:

var vimeoId = parseVimeoIdFromUrl(vimeoUrl);

从vimeo Id获取一个vimeo缩略图URL:

getVimeoThumbUrl(vimeoIds[0])
.done(function(img) {
    $('div').append('<img src="' + img + '"/>');
});

https://jsfiddle.net/b9chris/nm8L8cc8/1/

我创建了一个code depen来为您获取图像。

https://codepen.io/isramv/pen/gOpabXg

HTML

<input type="text" id="vimeoid" placeholder="257314493" value="257314493">
<button id="getVideo">Get Video</button>
<div id="output"></div>

JavaScript:

const videoIdInput = document.getElementById('vimeoid');
const getVideo = document.getElementById('getVideo');
const output = document.getElementById('output');

function getVideoThumbnails(videoid) {
  fetch(`https://vimeo.com/api/v2/video/${videoid}.json`)
  .then(response => {
    return response.text();
  })
  .then(data => {
    const { thumbnail_large, thumbnail_medium, thumbnail_small } = JSON.parse(data)[0];
    const small = `<img src="${thumbnail_small}"/>`;
    const medium = `<img src="${thumbnail_medium}"/>`;
    const large = `<img src="${thumbnail_large}"/>`;
    output.innerHTML = small + medium + large;
  })
  .catch(error => {
    console.log(error);
  });
}

getVideo.addEventListener('click', e => {
  if (!isNaN(videoIdInput.value)) {
    getVideoThumbnails(videoIdInput.value);
  }
});