我想从Vimeo获得视频的缩略图。

当从Youtube上获得图像时,我只是这样做:

http://img.youtube.com/vi/HwP5NG-3e8I/2.jpg

你知道如何处理Vimeo吗?

同样的问题,没有答案。


当前回答

使用Vimeo url(https://player.vimeo.com/video/30572181),下面是我的示例

<!DOCTYPE html> <html lang="en" xmlns="http://www.w3.org/1999/xhtml"> <head> <meta charset="utf-8" /> <meta http-equiv="X-UA-Compatible" content="IE=edge"> <script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script> <title>Vimeo</title> </head> <body> <div> <img src="" id="thumbImg"> </div> <script> $(document).ready(function () { var vimeoVideoUrl = 'https://player.vimeo.com/video/30572181'; var match = /vimeo.*\/(\d+)/i.exec(vimeoVideoUrl); if (match) { var vimeoVideoID = match[1]; $.getJSON('http://www.vimeo.com/api/v2/video/' + vimeoVideoID + '.json?callback=?', { format: "json" }, function (data) { featuredImg = data[0].thumbnail_large; $('#thumbImg').attr("src", featuredImg); }); } }); </script> </body> </html>

其他回答

如果您不需要自动解决方案,您可以通过在这里输入vimeo ID: http://video.depone.eu/来找到缩略图URL

下面是一个如何在ASP中做同样的事情的例子。NET使用c#。请随意使用不同的错误捕获图像:)

public string GetVimeoPreviewImage(string vimeoURL)
{
    try
    {
        string vimeoUrl = System.Web.HttpContext.Current.Server.HtmlEncode(vimeoURL);
        int pos = vimeoUrl.LastIndexOf(".com");
        string videoID = vimeoUrl.Substring(pos + 4, 8);

        XmlDocument doc = new XmlDocument();
        doc.Load("http://vimeo.com/api/v2/video/" + videoID + ".xml");
        XmlElement root = doc.DocumentElement;
        string vimeoThumb = root.FirstChild.SelectSingleNode("thumbnail_medium").ChildNodes[0].Value;
        string imageURL = vimeoThumb;
        return imageURL;
    }
    catch
    {
        //cat with cheese on it's face fail
        return "http://bestofepicfail.com/wp-content/uploads/2008/08/cheese_fail.jpg";
    }
}

注意:当被请求时,你的API请求应该像这样:http://vimeo.com/api/v2/video/32660708.xml

我写了一个函数在PHP让我这,我希望它对某人有用。缩略图的路径包含在视频页面的链接标记中。这似乎对我有用。

    $video_url = "http://vimeo.com/7811853"  
    $file = fopen($video_url, "r");
    $filedata = stream_get_contents($file);
    $html_content = strpos($filedata,"<link rel=\"videothumbnail");
    $link_string = substr($filedata, $html_content, 128);
    $video_id_array = explode("\"", $link_string);
    $thumbnail_url = $video_id_array[3];
    echo $thumbnail_url;

希望能对大家有所帮助。

Foggson

使用Ruby,你可以做以下事情,比如:

url                      = "http://www.vimeo.com/7592893"
vimeo_video_id           = url.scan(/vimeo.com\/(\d+)\/?/).flatten.to_s               # extract the video id
vimeo_video_json_url     = "http://vimeo.com/api/v2/video/%s.json" % vimeo_video_id   # API call

# Parse the JSON and extract the thumbnail_large url
thumbnail_image_location = JSON.parse(open(vimeo_video_json_url).read).first['thumbnail_large'] rescue nil

这里有一个完美的解决方案

   URL Example : https://vumbnail.com/226020936.jpg
   URL method :  https://vumbnail.com/{video_id}.jpg

这对我很有效。