我想从Vimeo获得视频的缩略图。
当从Youtube上获得图像时,我只是这样做:
http://img.youtube.com/vi/HwP5NG-3e8I/2.jpg
你知道如何处理Vimeo吗?
同样的问题,没有答案。
我想从Vimeo获得视频的缩略图。
当从Youtube上获得图像时,我只是这样做:
http://img.youtube.com/vi/HwP5NG-3e8I/2.jpg
你知道如何处理Vimeo吗?
同样的问题,没有答案。
当前回答
分解Karthikeyan P的答案,使其可以用于更广泛的场景:
// Requires jQuery
function parseVimeoIdFromUrl(vimeoUrl) {
var match = /vimeo.*\/(\d+)/i.exec(vimeoUrl);
if (match)
return match[1];
return null;
};
function getVimeoThumbUrl(vimeoId) {
var deferred = $.Deferred();
$.ajax(
'//www.vimeo.com/api/v2/video/' + vimeoId + '.json',
{
dataType: 'jsonp',
cache: true
}
)
.done(function (data) {
// .thumbnail_small 100x75
// .thumbnail_medium 200x150
// 640 wide
var img = data[0].thumbnail_large;
deferred.resolve(img);
})
.fail(function(a, b, c) {
deferred.reject(a, b, c);
});
return deferred;
};
使用
从Vimeo视频URL获取Vimeo Id:
var vimeoId = parseVimeoIdFromUrl(vimeoUrl);
从vimeo Id获取一个vimeo缩略图URL:
getVimeoThumbUrl(vimeoIds[0])
.done(function(img) {
$('div').append('<img src="' + img + '"/>');
});
https://jsfiddle.net/b9chris/nm8L8cc8/1/
其他回答
在javascript中(使用jQuery):
function vimeoLoadingThumb(id){
var url = "http://vimeo.com/api/v2/video/" + id + ".json?callback=showThumb";
var id_img = "#vimeo-" + id;
var script = document.createElement( 'script' );
script.src = url;
$(id_img).before(script);
}
function showThumb(data){
var id_img = "#vimeo-" + data[0].id;
$(id_img).attr('src',data[0].thumbnail_medium);
}
要显示它:
<img id="vimeo-{{ video.id_video }}" src="" alt="{{ video.title }}" />
<script type="text/javascript">
vimeoLoadingThumb({{ video.id_video }});
</script>
api/v2似乎已经死了。 为了使用新的API,您需要注册应用程序,base64将client_id和client_secret编码为授权标头。
$.ajax({
type:'GET',
url: 'https://api.vimeo.com/videos/' + video_id,
dataType: 'json',
headers: {
'Authorization': 'Basic ' + window.btoa(client_id + ":" + client_secret);
},
success: function(data) {
var thumbnail_src = data.pictures.sizes[2].link;
$('#thumbImg').attr('src', thumbnail_src);
}
});
为了安全起见,您可以返回已经从服务器编码的client_id和client_secret。
使用Vimeo url(https://player.vimeo.com/video/30572181),下面是我的示例
<!DOCTYPE html> <html lang="en" xmlns="http://www.w3.org/1999/xhtml"> <head> <meta charset="utf-8" /> <meta http-equiv="X-UA-Compatible" content="IE=edge"> <script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script> <title>Vimeo</title> </head> <body> <div> <img src="" id="thumbImg"> </div> <script> $(document).ready(function () { var vimeoVideoUrl = 'https://player.vimeo.com/video/30572181'; var match = /vimeo.*\/(\d+)/i.exec(vimeoVideoUrl); if (match) { var vimeoVideoID = match[1]; $.getJSON('http://www.vimeo.com/api/v2/video/' + vimeoVideoID + '.json?callback=?', { format: "json" }, function (data) { featuredImg = data[0].thumbnail_large; $('#thumbImg').attr("src", featuredImg); }); } }); </script> </body> </html>
function parseVideo(url) {
// - Supported YouTube URL formats:
// - http://www.youtube.com/watch?v=My2FRPA3Gf8
// - http://youtu.be/My2FRPA3Gf8
// - https://youtube.googleapis.com/v/My2FRPA3Gf8
// - Supported Vimeo URL formats:
// - http://vimeo.com/25451551
// - http://player.vimeo.com/video/25451551
// - Also supports relative URLs:
// - //player.vimeo.com/video/25451551
url.match(/(http:|https:|)\/\/(player.|www.)?(vimeo\.com|youtu(be\.com|\.be|be\.googleapis\.com))\/(video\/|embed\/|watch\?v=|v\/)?([A-Za-z0-9._%-]*)(\&\S+)?/);
if (RegExp.$3.indexOf('youtu') > -1) {
var type = 'youtube';
} else if (RegExp.$3.indexOf('vimeo') > -1) {
var type = 'vimeo';
}
return {
type: type,
id: RegExp.$6
};
}
function getVideoThumbnail(url, cb) {
var videoObj = parseVideo(url);
if (videoObj.type == 'youtube') {
cb('//img.youtube.com/vi/' + videoObj.id + '/maxresdefault.jpg');
} else if (videoObj.type == 'vimeo') {
$.get('http://vimeo.com/api/v2/video/' + videoObj.id + '.json', function(data) {
cb(data[0].thumbnail_large);
});
}
}
我写了一个函数在PHP让我这,我希望它对某人有用。缩略图的路径包含在视频页面的链接标记中。这似乎对我有用。
$video_url = "http://vimeo.com/7811853"
$file = fopen($video_url, "r");
$filedata = stream_get_contents($file);
$html_content = strpos($filedata,"<link rel=\"videothumbnail");
$link_string = substr($filedata, $html_content, 128);
$video_id_array = explode("\"", $link_string);
$thumbnail_url = $video_id_array[3];
echo $thumbnail_url;
希望能对大家有所帮助。
Foggson