短而优雅

#include <vector>
#include <string>
using namespace std;

vector<string> split(string data, string token)
{
    vector<string> output;
    size_t pos = string::npos; // size_t to avoid improbable overflow
    do
    {
        pos = data.find(token);
        output.push_back(data.substr(0, pos));
        if (string::npos != pos)
            data = data.substr(pos + token.size());
    } while (string::npos != pos);
    return output;
}

可以使用任何字符串作为分隔符，也可以与二进制数据一起使用（std:：string支持二进制数据，包括空值）

使用：

auto a = split("this!!is!!!example!string", "!!");

输出：

this
is
!example!string

#include<iostream>
#include<string>
#include<sstream>
#include<vector>
using namespace std;

    vector<string> split(const string &s, char delim) {
        vector<string> elems;
        stringstream ss(s);
        string item;
        while (getline(ss, item, delim)) {
            elems.push_back(item);
        }
        return elems;
    }

int main() {

        vector<string> x = split("thi is an sample test",' ');
        unsigned int i;
        for(i=0;i<x.size();i++)
            cout<<i<<":"<<x[i]<<endl;
        return 0;
}

这类似于堆栈溢出问题：如何在C++中标记字符串？。需要Boost外部库

#include <iostream>
#include <string>
#include <boost/tokenizer.hpp>

using namespace std;
using namespace boost;

int main(int argc, char** argv)
{
    string text = "token  test\tstring";

    char_separator<char> sep(" \t");
    tokenizer<char_separator<char>> tokens(text, sep);
    for (const string& t : tokens)
    {
        cout << t << "." << endl;
    }
}

下面是一个更好的方法。它可以接受任何字符，除非您愿意，否则不会拆分行。不需要特殊的库（嗯，除了std，但谁真的认为这是一个额外的库），没有指针，没有引用，而且它是静态的。只是简单的C++。

#pragma once
#include <vector>
#include <sstream>
using namespace std;
class Helpers
{
    public:
        static vector<string> split(string s, char delim)
        {
            stringstream temp (stringstream::in | stringstream::out);
            vector<string> elems(0);
            if (s.size() == 0 || delim == 0)
                return elems;
            for(char c : s)
            {
                if(c == delim)
                {
                    elems.push_back(temp.str());
                    temp = stringstream(stringstream::in | stringstream::out);
                }
                else
                    temp << c;
            }
            if (temp.str().size() > 0)
                elems.push_back(temp.str());
                return elems;
            }

        //Splits string s with a list of delimiters in delims (it's just a list, like if we wanted to
        //split at the following letters, a, b, c we would make delims="abc".
        static vector<string> split(string s, string delims)
        {
            stringstream temp (stringstream::in | stringstream::out);
            vector<string> elems(0);
            bool found;
            if(s.size() == 0 || delims.size() == 0)
                return elems;
            for(char c : s)
            {
                found = false;
                for(char d : delims)
                {
                    if (c == d)
                    {
                        elems.push_back(temp.str());
                        temp = stringstream(stringstream::in | stringstream::out);
                        found = true;
                        break;
                    }
                }
                if(!found)
                    temp << c;
            }
            if(temp.str().size() > 0)
                elems.push_back(temp.str());
            return elems;
        }
};

我的代码是：

#include <list>
#include <string>
template<class StringType = std::string, class ContainerType = std::list<StringType> >
class DSplitString:public ContainerType
{
public:
    explicit DSplitString(const StringType& strString, char cChar, bool bSkipEmptyParts = true)
    {
        size_t iPos = 0;
        size_t iPos_char = 0;
        while(StringType::npos != (iPos_char = strString.find(cChar, iPos)))
        {
            StringType strTemp = strString.substr(iPos, iPos_char - iPos);
            if((bSkipEmptyParts && !strTemp.empty()) || (!bSkipEmptyParts))
                push_back(strTemp);
            iPos = iPos_char + 1;
        }
    }
    explicit DSplitString(const StringType& strString, const StringType& strSub, bool bSkipEmptyParts = true)
    {
        size_t iPos = 0;
        size_t iPos_char = 0;
        while(StringType::npos != (iPos_char = strString.find(strSub, iPos)))
        {
            StringType strTemp = strString.substr(iPos, iPos_char - iPos);
            if((bSkipEmptyParts && !strTemp.empty()) || (!bSkipEmptyParts))
                push_back(strTemp);
            iPos = iPos_char + strSub.length();
        }
    }
};

例子：

#include <iostream>
#include <string>
int _tmain(int argc, _TCHAR* argv[])
{
    DSplitString<> aa("doicanhden1;doicanhden2;doicanhden3;", ';');
    for each (std::string var in aa)
    {
        std::cout << var << std::endl;
    }
    std::cin.get();
    return 0;
}

这是我的版本获取了Kev的来源：

#include <string>
#include <vector>
void split(vector<string> &result, string str, char delim ) {
  string tmp;
  string::iterator i;
  result.clear();

  for(i = str.begin(); i <= str.end(); ++i) {
    if((const char)*i != delim  && i != str.end()) {
      tmp += *i;
    } else {
      result.push_back(tmp);
      tmp = "";
    }
  }
}

之后，调用函数并执行以下操作：

vector<string> hosts;
split(hosts, "192.168.1.2,192.168.1.3", ',');
for( size_t i = 0; i < hosts.size(); i++){
  cout <<  "Connecting host : " << hosts.at(i) << "..." << endl;
}