我试图在PHP中创建一个随机字符串，我得到绝对没有输出:
<?php
function RandomString()
{
$characters = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
$randstring = '';
for ($i = 0; $i < 10; $i++) {
$randstring = $characters[rand(0, strlen($characters))];
}
return $randstring;
}
RandomString();
echo $randstring;
我做错了什么?
当前回答
Laravel解决方案: 如果你正在使用Laravel框架，你可以像这样使用它的StringHelper。
使用“照亮\支持\斯特”;
Str：：random（$strlentgh = 16）
其他回答
我想要特定字符和预设长度的伪随机字符串。我希望当前版本的PHP具有最高质量的伪随机性，此时它可以是v5、v6、v7或v8，并且可以使用默认配置或特殊配置。为了解决这种混乱，我在这里选取了其他几个答案，并包含了函数可用性条件。
使用。要全局使用它，给$VALID_ID_CHARS赋值你想要的字符，然后调用它:
$VALID_ID_CHARS = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789";
$myNewRandomId = makeId(6);
function makeId($desiredLen)
{
global $VALID_ID_CHARS;
if ($desiredLen < 1) {
throw new \RangeException("Length must be a positive integer");
}
$vLen = 0;
if (function_exists('mb_strlen')) {
$vLen = mb_strlen($VALID_ID_CHARS, '8bit') - 1;
} else {
$vLen = strlen($VALID_ID_CHARS) - 1;
}
if (function_exists('random_int')) {
$pieces = [];
for ($i = 0; $i < $desiredLen; ++$i) {
$pieces[] = $VALID_ID_CHARS[random_int(0, $vLen)];
}
return implode('', $pieces);
}
if (function_exists('openssl_random_pseudo_bytes')) {
$random = openssl_random_pseudo_bytes($desiredLen);
$id = '';
for ($i = 0; $i < $desiredLen; ++$i) {
$id .= $VALID_ID_CHARS[ord($random[$i]) % $vLen];
}
return $id;
}
http_response_code(500);
die('random id generation failed. either random_int or openssl_random_pseudo_bytes is needed');
}
<?php
/**
* Creates a random string
*
* @param (int) $length
* Length in characters
* @param (array) $ranges
* (optional) Array of ranges to be used
*
* @return
* Random string
*/
function random_string($length, $ranges = array('0-9', 'a-z', 'A-Z')) {
foreach ($ranges as $r) $s .= implode(range(array_shift($r = explode('-', $r)), $r[1]));
while (strlen($s) < $length) $s .= $s;
return substr(str_shuffle($s), 0, $length);
}
// Examples:
$l = 100;
echo '<b>Default:</b> ' . random_string($l) . '<br />';
echo '<b>Lower Case only:</b> ' . random_string($l, array('a-z')) . '<br />';
echo '<b>HEX only:</b> ' . random_string($l, array('0-9', 'A-F')) . '<br />';
echo '<b>BIN only:</b> ' . random_string($l, array('0-1')) . '<br />';
/* End of file */
以前的答案会生成不安全或难以输入的密码。
这是安全的，并且提供了用户更有可能实际使用的密码，而不是因为一些薄弱的东西而被丢弃。
// NOTE: On PHP 5.x you will need to install https://github.com/paragonie/random_compat
/**
* Generate a password that can easily be typed by users.
*
* By default, this will sacrifice strength by skipping characters that can cause
* confusion. Set $allowAmbiguous to allow these characters.
*/
static public function generatePassword($length=12, $mixedCase=true, $numericCount=2, $symbolCount=1, $allowAmbiguous=false, $allowRepeatingCharacters=false)
{
// sanity check to prevent endless loop
if ($numericCount + $symbolCount > $length) {
throw new \Exception('generatePassword(): $numericCount + $symbolCount are too high');
}
// generate a basic password with just alphabetic characters
$chars = 'qwertyupasdfghjkzxcvbnm';
if ($mixedCase) {
$chars .= 'QWERTYUPASDFGHJKZXCVBNML';
}
if ($allowAmbiguous) {
$chars .= 'iol';
if ($mixedCase) {
$chars .= 'IO';
}
}
$password = '';
foreach (range(1, $length) as $index) {
$char = $chars[random_int(0, strlen($chars) - 1)];
if (!$allowRepeatingCharacters) {
while ($char == substr($password, -1)) {
$char = $chars[random_int(0, strlen($chars) - 1)];
}
}
$password .= $char;
}
// add numeric characters
$takenSubstitutionIndexes = [];
if ($numericCount > 0) {
$chars = '23456789';
if ($allowAmbiguous) {
$chars .= '10';
}
foreach (range(1, $numericCount) as $_) {
$index = random_int(0, strlen($password) - 1);
while (in_array($index, $takenSubstitutionIndexes)) {
$index = random_int(0, strlen($password) - 1);
}
$char = $chars[random_int(0, strlen($chars) - 1)];
if (!$allowRepeatingCharacters) {
while (substr($password, $index - 1, 1) == $char || substr($password, $index + 1, 1) == $char) {
$char = $chars[random_int(0, strlen($chars) - 1)];
}
}
$password[$index] = $char;
$takenSubstitutionIndexes[] = $index;
}
}
// add symbols
$chars = '!@#$%&*=+?';
if ($allowAmbiguous) {
$chars .= '^~-_()[{]};:|\\/,.\'"`<>';
}
if ($symbolCount > 0) {
foreach (range(1, $symbolCount) as $_) {
$index = random_int(0, strlen($password) - 1);
while (in_array($index, $takenSubstitutionIndexes)) {
$index = random_int(0, strlen($password) - 1);
}
$char = $chars[random_int(0, strlen($chars) - 1)];
if (!$allowRepeatingCharacters) {
while (substr($password, $index - 1, 1) == $char || substr($password, $index + 1, 1) == $char) {
$char = $chars[random_int(0, strlen($chars) - 1)];
}
}
$password[$index] = $char;
$takenSubstitutionIndexes[] = $index;
}
}
return $password;
}
注意:str_shuffle()内部使用rand()，不适合用于加密目的(例如生成随机密码)。你需要一个安全的随机数生成器。它也不允许字符重复。
还有一种方法。
UPDATED(现在这会生成任意长度的字符串):
function generateRandomString($length = 10) {
return substr(str_shuffle(str_repeat($x='0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ', ceil($length/strlen($x)) )),1,$length);
}
echo generateRandomString(); // OR: generateRandomString(24)
就是这样。：）
你可以试试这个:
<?php
function random($len){
$char = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
// ----------------------------------------------
// Number of possible combinations
// ----------------------------------------------
$pos = strlen($char);
$pos = pow($pos, $len);
echo $pos.'<br>';
// ----------------------------------------------
$total = strlen($char)-1;
$text = "";
for ($i=0; $i<$len; $i++){
$text = $text.$char[rand(0, $total)];
}
return $text;
}
$string = random(15);
echo $string;
?>
您也可以准时使用md5，但要小心。
您需要使用microtime()而不是time()函数，因为如果多个线程在同一秒内运行，则需要为所有线程获取不同的字符串。
<?php
$string = md5(microtime());
echo $string;
?>
