马克·贝西(Mark Bessey)已经说过了，但这一点需要再次强调，直到人们理解为止。

指针与变量的关系比与文字3的关系更大。

指针是一个值(地址)和类型(带有其他属性，如只读)的元组。类型(以及附加参数(如果有的话)可以进一步定义或限制上下文;如。__far ptr， __near ptr:地址的上下文是什么:堆栈，堆，线性地址，某处的偏移量，物理内存或其他。

正是type的属性使得指针算术与整数算术略有不同。

指针不是变量的反例太多了，不容忽视

fopen返回FILE指针。(变量在哪里) 堆栈指针或帧指针通常是不可寻址的寄存器 *(int *)0x1231330 = 13;——将任意整数值转换为pointer_of_integer类型，并在不引入变量的情况下写入/读取整数值

在c程序的生命周期中，会有许多其他没有地址的临时指针实例——因此它们不是变量，而是带有编译时相关类型的表达式/值。

以下是我过去是如何向一些困惑的人解释的: 指针有两个影响其行为的属性。它有一个值(在典型环境中)是一个内存地址，还有一个类型(告诉您它所指向的对象的类型和大小)。

例如，给定:

union {
    int i;
    char c;
} u;

你可以有三个不同的指针都指向同一个对象:

void *v = &u;
int *i = &u.i;
char *c = &u.c;

如果你比较这些指针的值，它们都是相等的:

v==i && i==c

但是，如果对每个指针加1，就会发现它们所指向的类型变得相关了。

i++;
c++;
// You can't perform arithmetic on a void pointer, so no v++
i != c

此时，变量i和c将具有不同的值，因为i++使i包含下一个可访问的整数的地址，而c++使c指向下一个可寻址的字符。通常，整数比字符占用更多的内存，所以在它们都加一之后，i的值将比c的值更大。

简短的总结 (我也会把它放在顶部):

将指针视为地址通常是一个很好的学习工具，并且通常是普通数据类型指针的实际实现。

(1)但是在许多，也许是大多数编译器上，指向函数的指针不是地址，而是比地址大(通常是2倍，有时更多)，或者实际上是指向内存中结构体的指针，而不是包含函数地址和常量池之类的东西。

(2)指向数据成员的指针和指向方法的指针通常更奇怪。

(3)遗留的x86代码的FAR和NEAR指针问题

(4)几个例子，最著名的是IBM AS/400，具有安全的“胖指针”。

我相信你能找到更多。

细节:

UMMPPHHH ! !到目前为止，许多答案都是相当典型的“程序员菜鸟”答案——但不是编译器菜鸟或硬件菜鸟。因为我假装是一个硬件弱项，并且经常与编译器弱项一起工作，让我抛出我的意见:

在许多(可能是大多数)C编译器中，指向类型为T的数据的指针实际上是T的地址。

很好。

但是，即使在许多这样的编译器上，某些指针也不是地址。你可以通过sizeof(ThePointer)来判断。

For example, pointers to functions are sometimes quite a lot bigger than ordinary addresses. Or, they may involve a level of indirection. This article provides one description, involving the Intel Itanium processor, but I have seen others. Typically, to call a function you must know not only the address of the function code, but also the address of the function's constant pool - a region of memory from which constants are loaded with a single load instruction, rather than the compiler having to generate a 64 bit constant out of several Load Immediate and Shift and OR instructions. So, rather than a single 64 bit address, you need 2 64 bit addresses. Some ABIs (Application Binary Interfaces) move this around as 128 bits, whereas others use a level of indirection, with the function pointer actually being the address of a function descriptor that contains the 2 actual addresses just mentioned. Which is better? Depends on your point of view: performance, code size, and some compatibility issues - often code assumes that a pointer can be cast to a long or a long long, but may also assume that the long long is exactly 64 bits. Such code may not be standards compliant, but nevertheless customers may want it to work.

我们中的许多人都对旧的英特尔x86分段架构有痛苦的记忆，有NEAR指针和FAR指针。值得庆幸的是，这些几乎已经灭绝了，所以只有一个快速的总结:在16位实模式中，实际的线性地址是

LinearAddress = SegmentRegister[SegNum].base << 4 + Offset

而在保护模式下，它可能是

LinearAddress = SegmentRegister[SegNum].base + offset

with the resulting address being checked against a limit set in the segment. Some programs used not really standard C/C++ FAR and NEAR pointer declarations, but many just said *T --- but there were compiler and linker switches so, for example, code pointers might be near pointers, just a 32 bit offset against whatever is in the CS (Code Segment) register, while the data pointers might be FAR pointers, specifying both a 16 bit segment number and a 32 bit offset for a 48 bit value. Now, both of these quantities are certainly related to the address, but since they aren't the same size, which of them is the address? Moreover, the segments also carried permissions - read-only, read-write, executable - in addition to stuff related to the actual address.

A more interesting example, IMHO, is (or, perhaps, was) the IBM AS/400 family. This computer was one of the first to implement an OS in C++. Pointers on this machime were typically 2X the actual address size - e.g. as this presentation says, 128 bit pointers, but the actual addresses were 48-64 bits, and, again, some extra info, what is called a capability, that provided permissions such as read, write, as well as a limit to prevent buffer overflow. Yes: you can do this compatibly with C/C++ -- and if this were ubiquitous, the Chinese PLA and slavic mafia would not be hacking into so many Western computer systems. But historically most C/C++ programming has neglected security for performance. Most interestingly, the AS400 family allowed the operating system to create secure pointers, that could be given to unprivileged code, but which the unprivileged code could not forge or tamper with. Again, security, and while standards compliant, much sloppy non-standards compliant C/C++ code will not work in such a secure system. Again, there are official standards, and there are de-facto standards.

现在，我将放下我的安全演讲，并提到指针(各种类型)通常不是真正地址的其他一些方式:指向数据成员的指针，指向成员函数方法的指针，以及它们的静态版本比普通地址更大。正如这篇文章所说:

有许多方法可以解决这个问题[与单继承和多继承以及虚拟继承有关的问题]。Visual Studio编译器决定如何处理它:指向多重继承类的成员函数的指针实际上是一个结构。” 他们接着说:“强制转换函数指针可以改变它的大小!”

从我对安全性的评论中，您可能会猜到，我曾经参与过C/ c++硬件/软件项目，在这些项目中，指针更像是一种能力，而不是原始地址。

我还可以继续，但我希望你们能明白。

简短的总结 (我也会把它放在顶部):

(0)将指针视为地址通常是一个很好的学习工具，并且通常是普通数据类型指针的实际实现。

(1)但是在许多，也许是大多数编译器上，指向函数的指针不是地址，而是比地址大(通常是2X，有时更多)，或者实际上是指向内存中结构体的指针，而不是包含函数地址和常量池之类的东西。

(2)指向数据成员的指针和指向方法的指针通常更奇怪。

(3)遗留的x86代码的FAR和NEAR指针问题

(4)几个例子，最著名的是IBM AS/400，具有安全的“胖指针”。

我相信你能找到更多。

C或c++指针与简单内存地址的另一个不同之处是，我在其他答案中没有看到不同的指针类型(尽管考虑到它们的总大小，我可能忽略了它)。但它可能是最重要的一个，因为即使是经验丰富的C/ c++程序员也会被它绊倒:

编译器可能会假设不兼容类型的指针不指向相同的地址，即使它们很明显指向相同的地址，这可能会导致简单的pointer==address模型不可能出现的行为。考虑以下代码(假设sizeof(int) = 2*sizeof(short)):

unsigned int i = 0;
unsigned short* p = (unsigned short*)&i;
p[0]=p[1]=1;

if (i == 2 + (unsigned short)(-1))
{
  // you'd expect this to execute, but it need not
}

if (i == 0)
{
  // you'd expect this not to execute, but it actually may do so
}

注意，char*有一个例外，所以使用char*操作值是可能的(尽管不是很可移植)。

指针是一种在C/ c++中本地可用的变量类型，包含一个内存地址。像任何其他变量一样，它有自己的地址并占用内存(数量是特定于平台的)。

由于混淆，您将看到的一个问题是试图通过简单地按值传递指针来更改函数中的引用。这将复制函数作用域内的指针，对这个新指针“指向”的地方的任何更改都不会改变调用该函数的作用域内指针的引用。为了修改函数中的实际指针，通常会将一个指针传递给另一个指针。

指针是一个保存内存地址的变量，而不是地址本身。但是，您可以解除对指针的引用-并访问内存位置。

例如:

int q = 10; /*say q is at address 0x10203040*/
int *p = &q; /*means let p contain the address of q, which is 0x10203040*/
*p = 20; /*set whatever is at the address pointed by "p" as 20*/

就是这样。就是这么简单。

一个演示我所说内容的程序，其输出如下:

http://ideone.com/rcSUsb

程序:

#include <stdio.h>

int main(int argc, char *argv[])
{
  /* POINTER AS AN ADDRESS */
  int q = 10;
  int *p = &q;

  printf("address of q is %p\n", (void *)&q);
  printf("p contains %p\n", (void *)p);

  p = NULL;
  printf("NULL p now contains %p\n", (void *)p);
  return 0;
}