在关于C的一个有信誉的来源中,在讨论&操作符后给出了以下信息:

... 有点不幸的是,术语[地址的]仍然存在,因为它混淆了那些不知道地址是关于什么的人,并误导了那些知道地址的人:将指针视为地址通常会导致悲伤……

我读过的其他材料(来自同样有名望的来源,我想说)总是毫不掩饰地将指针和&操作符作为内存地址。我很愿意继续寻找事情的真相,但当有信誉的消息来源不同意时,这有点困难。

现在我有点困惑了——如果指针不是内存地址,那么它到底是什么?

P.S.

作者后来说:……不过,我将继续使用“地址”这个术语,因为发明一个不同的(术语)会更糟糕。


当前回答

Come to think about it, I think it's a matter of semantics. I don't think the author is right, since the C standard refers to a pointer as holding an address to the referenced object as others have already mentioned here. However, address!=memory address. An address can be really anything as per C standard although it will eventually lead to a memory address, the pointer itself can be an id, an offset + selector (x86), really anything as long as it can describe (after mapping) any memory address in the addressable space.

其他回答

指针是一个保存内存地址的变量,而不是地址本身。但是,您可以解除对指针的引用-并访问内存位置。

例如:

int q = 10; /*say q is at address 0x10203040*/
int *p = &q; /*means let p contain the address of q, which is 0x10203040*/
*p = 20; /*set whatever is at the address pointed by "p" as 20*/

就是这样。就是这么简单。

一个演示我所说内容的程序,其输出如下:

http://ideone.com/rcSUsb

程序:

#include <stdio.h>

int main(int argc, char *argv[])
{
  /* POINTER AS AN ADDRESS */
  int q = 10;
  int *p = &q;

  printf("address of q is %p\n", (void *)&q);
  printf("p contains %p\n", (void *)p);

  p = NULL;
  printf("NULL p now contains %p\n", (void *)p);
  return 0;
}

在理解指针之前,我们需要先理解对象。对象是存在的实体,具有一个称为地址的位置说明符。指针与C语言中的其他变量一样,是一个类型为指针的变量,其内容被解释为支持以下操作的对象的地址。

+ : A variable of type integer (usually called offset) can be added to yield a new pointer
- : A variable of type integer (usually called offset) can be subtracted to yield a new pointer
  : A variable of type pointer can be subtracted to yield an integer (usually called offset)
* : De-referencing. Retrieve the value of the variable (called address) and map to the object the address refers to.
++: It's just `+= 1`
--: It's just `-= 1`

指针是根据它当前引用的对象类型进行分类的。唯一重要的信息是物体的大小。

任何对象都支持& (address of)操作,该操作将对象的位置说明符(地址)作为指针对象类型检索。这将减少围绕命名的混乱,因为调用&作为对象的操作而不是作为结果类型为对象类型的指针的指针是有意义的。

注意:在整个解释中,我省略了内存的概念。

A pointer value is an address. A pointer variable is an object that can store an address. This is true because that's what the standard defines a pointer to be. It's important to tell it to C novices because C novices are often unclear on the difference between a pointer and the thing it points to (that is to say, they don't know the difference between an envelope and a building). The notion of an address (every object has an address and that's what a pointer stores) is important because it sorts that out.

然而,标准在特定的抽象层次上进行讨论。作者所说的那些“知道地址是关于什么的”,但对C不熟悉的人,必须在不同的抽象级别上学习地址——也许是通过编写汇编语言。不能保证C实现使用与cpu操作码相同的地址表示(在本文中称为“存储地址”),这些人已经知道。

He goes on to talk about "perfectly reasonable address manipulation". As far as the C standard is concerned there's basically no such thing as "perfectly reasonable address manipulation". Addition is defined on pointers and that is basically it. Sure, you can convert a pointer to integer, do some bitwise or arithmetic ops, and then convert it back. This is not guaranteed to work by the standard, so before writing that code you'd better know how your particular C implementation represents pointers and performs that conversion. It probably uses the address representation you expect, but it it doesn't that's your fault because you didn't read the manual. That's not confusion, it's incorrect programming procedure ;-)

简而言之,C使用了比作者更抽象的地址概念。

The author's concept of an address of course is also not the lowest-level word on the matter. What with virtual memory maps and physical RAM addressing across multiple chips, the number that you tell the CPU is "the store address" you want to access has basically nothing to do with where the data you want is actually located in hardware. It's all layers of indirection and representation, but the author has chosen one to privilege. If you're going to do that when talking about C, choose the C level to privilege!

Personally I don't think the author's remarks are all that helpful, except in the context of introducing C to assembly programmers. It's certainly not helpful to those coming from higher level languages to say that pointer values aren't addresses. It would be far better to acknowledge the complexity than it is to say that the CPU has the monopoly on saying what an address is and thus that C pointer values "are not" addresses. They are addresses, but they may be written in a different language from the addresses he means. Distinguishing the two things in the context of C as "address" and "store address" would be adequate, I think.

你是对的,是理智的。通常,指针只是一个地址,因此您可以将其强制转换为整数并进行任何算术运算。

但有时指针只是地址的一部分。在一些体系结构上,指针被转换为一个增加了基数的地址或使用另一个CPU寄存器。

但是现在,在PC和ARM架构上,使用平面内存模型和原生编译的C语言,可以认为指针是指向一维可寻址RAM中某个位置的整数地址。

以下是我过去是如何向一些困惑的人解释的: 指针有两个影响其行为的属性。它有一个值(在典型环境中)是一个内存地址,还有一个类型(告诉您它所指向的对象的类型和大小)。

例如,给定:

union {
    int i;
    char c;
} u;

你可以有三个不同的指针都指向同一个对象:

void *v = &u;
int *i = &u.i;
char *c = &u.c;

如果你比较这些指针的值,它们都是相等的:

v==i && i==c

但是,如果对每个指针加1,就会发现它们所指向的类型变得相关了。

i++;
c++;
// You can't perform arithmetic on a void pointer, so no v++
i != c

此时,变量i和c将具有不同的值,因为i++使i包含下一个可访问的整数的地址,而c++使c指向下一个可寻址的字符。通常,整数比字符占用更多的内存,所以在它们都加一之后,i的值将比c的值更大。